The velocity of the ride after 2.3s is 22.54m/s and the displacement covered is 26m.
What is free fall?
An object that is falling only due to gravity is said to be in free fall. Any object that is merely subject to the effects of gravity is said to be in free fall. Two crucial aspects of an object's motion are present while it is falling freely:
1) Air resistance does not exist for falling objects in free fall.
2) On Earth, all objects in free fall experience a downward acceleration of 9.8 m/s/s (which is frequently approximated to 10 m/s/s in computations).
Let the upward direction be positive and the downward be negative.
Now, according to the question we have given
The ride is in free fall i.e., u=0m/s and we have to find the velocity after 2.3s in part a.
so we can use the formula
v=u+at
v=0+9.8×2.3
v=22.54m/s
For part b we can use the 2nd equation of motion.
since xi=0 and u=0
xf=0+0+1/2×(-9.8)*2.3²
xf=-26m
Therefore, velocity of the ride after 2.3s is 22.54m/s and the displacement covered is 26m.
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two point charges placed 5 cm apart on the x axis. at what points along the x axis is the potential zero?
The distance where the potential of two similar charges (in terms of magnitude and charge) will be zero at 2.5 cm from both sides. That is at Exect middle of both charges.
For finding the potential at any point due to a point charge(q0) is(Vr) = 1/4π∈*q0/r.
if both the charges are the same sign then the point will be in between of both the charges placed,
so Let the distance where the potential is zero be x in the left side so on the right side it will be 5-x.
as lets assume left charge if placed at the origin
so 1/4π∈*q0/x=1/4π∈*q0/5-x. ............. As both the potentials are equals
so 1/x = 1/5-x
x=5-x
so 2x =5 and here x= 2.5 cm
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students work together durlng an experlment about newlon's laws the students use a setup that conslsts of a cart of known mass connected to one end of a strlng thal ls looped over a pulley of negllgible frlctlon, wlh lts other end connected to a hanging mass the cart ls lnltlally a rest on a horlzontal surface and rolls wlhoul sllpplng when released the lnertla of the cart's wheels ls negllgible, sudents have access o common laboratory equlpment o make measurements of components of the system the shdents double the mass that hangs hom de string they also replace the original cart with a new cart that has double the mass. by doubling bolh masses, how will the tension in lhe string and the acceleration of the cart change?
The tension in the string is the same over the entire length of the string, and equals the difference between the weight of the mass, and the acceleration of the cart.
What is meant by acceleration ?
The rate at which velocity changes is called acceleration. Acceleration typically indicates a change in speed, but not necessarily.An item that follows a circular course while maintaining a constant speed is still moving forward because the direction of its motion is shifting.In physics, acceleration is the rate at which the velocity of an object changes in relation to time. According to Newton's Second Law, the sum of all forces acting on an item results in its acceleration. Meter per second squared (m s2) is the unit of acceleration used in the SI system.The definition of acceleration is the rate of change of velocity. Or Acceleration is the term used to describe a change in velocity over time. Acceleration is a vector quantity because velocity is one as well.To learn more about acceleration refer to
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an object is dropped off a building. if it takes 10 seconds to get halfway to the ground, how long does it take to fall the entire distance? ignore air resistance
Since the object is dropped off a building, we can assume that it is falling under the influence of gravity. The acceleration due to gravity is 9.8 m/s² and the time it takes to fall halfway to the ground is 10 seconds.
The time it takes for an object to fall a certain distance under the influence of gravity is given by the equation:
t = √(2d/g)
Where t is the time, d is the distance, and g is the acceleration due to gravity.
We know that it takes 10 seconds to fall halfway to the ground, so we can use that information to find the total time it takes to fall the entire distance.
Halfway is half the distance, so we can multiply the time to fall halfway by 2 to find the time to fall the entire distance:
t = √(2d/g) x 2
t = 2 x √(2d/g)
t = √(4d/g)
t = √(4 x d/g)
t = √(d/g)
t = √(d/(9.8 m/s²))
So, we need to know the distance that the object is falling to find the total time it takes to fall the entire distance.
Alternatively, if we know the height of the building, we can use it to find the distance that the object is falling. And then we can use that distance in the above equation to find the total time it takes to fall the entire distance.
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a ball thrown horizontally at 26 m/s travels a horizontal distance of 58 m before hitting the ground. from what height was the ball throw
The ball was thrown from a height of 15.82 meters above the ground.
To find the height from which the ball was thrown, we can use the equations of motion for vertical and horizontal motion individually.
First, we know that the horizontal velocity of the ball is constant, so we can use the equation:
distance = velocity * time
We know the distance (58 m) and the velocity (26 m/s) of the ball, so we can find the time it takes for the ball to travel 58 m:
time = distance/velocity
time = 58 m / 26 m/s
Now we can use this time to find the height from which the ball was thrown. Since the vertical motion of the ball is affected by gravity, we can use the equation:
vertical distance = initial vertical velocity * time + (1/2) * acceleration due to gravity * time^2
Since the ball was thrown horizontally, its initial vertical velocity is 0 m/s. The acceleration due to gravity is 9.8 m/s^2 (going down).
We can substitute the values into the equation:
[tex]height = 0 m/s * time + (1/2) * 9.8 m/s^2 * time^2[/tex]
[tex]h = (1/2) * 9.8 m/s^2 * time^2[/tex]
[tex]h = (1/2) * 9.8 m/s^2 * (58 m / 26 m/s)^2[/tex]
height = 15.82 m
Therefore, the ball was thrown from a height of 15.82 meters above the ground.
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a cube whose sides are of length d is placed in a uniform electric field of magnitude so that the field is perpendicular to two opposite faces of the cube. what is the net flux through the cube?
The net flux through the cube is equal to [tex]2E*d^2[/tex]
The net flux through the cube is calculated by the flux through each of the six faces of the cube. The flux through a face is calculated by the electric field through the face multiplied by the area of the face.
For this situation, the electric field is perpendicular to two inverse faces of the cube, which means that the flux through these two faces is the maximum possible (since the field is perpendicular to the face).
The flux through these two faces is given by:
[tex]Flux = E * A = E * d^2[/tex] (where E is the electric field and d is the side length of the cube)
The electric field is parallel to the other four faces of the cube, which means that the flux through these faces is zero (since the field is parallel to the face and not passing through it).
Therefore, the net flux through the cube is the sum of the flux through the two faces where the field is perpendicular:
[tex]Net flux = 2 * (E * d^2) = 2E*d^2[/tex]
So the net flux through the cube is equal to [tex]2E*d^2[/tex], with E being the magnitude of the uniform electric field and d is the side length of the cube.
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how do I find average distance with the numbers below:
MAIN: 92.2g
255cm,242 cm,245cm
for science help pls
Answer:
To find the average distance of the numbers you provided (255cm, 242cm, 245cm), you can add all the numbers together and divide by the number of numbers in the set.
In this case, you would add 255cm + 242cm + 245cm = 742cm, and then divide by 3 (the number of numbers in the set) to get an average distance of 244cm.
You can also use this formula: (255 +242 + 245) /3 = 244
According to newton's second law of motion, if we have a rigid, unchanging mass and we observe it accelerating, what must be happening? question 8 options: a. a force is being applied to the mass b. no force was or is being applied to the massc. the mass must be changing d. the object's inertia is decreasing
"A force is being applied to the mass." that is option A is happening if we have a rigid, unchanging mass and we observe it accelerating.
What is force?A force is an effect in physics that may modify the velocity of an item. A force can cause a mass item to change its velocity, or accelerate. Intuitively, force may be characterized as a push or a pull. A force is a vector quantity since it has both magnitude and direction. The term "force" has a specific meaning in science. At this level, it is quite acceptable to refer to a force as a push or a pull. A force is not something that an item possesses or possesses. Another item applies a force to another. The concept of a force is not restricted to living or non-living entities.
Here,
Newton's second law of motion: F = m · a.
F - force applied.
m - mass of the object receiving the force.
a - the acceleration of the object.
One newton is the force needed to accelerate one kilogram of mass at the rate of one metre per second squared in direction of the applied force. The weight of an object is the amount of force acting on the object due to gravity. SI unit for weight is newton (N).
"There is a force acting on the mass." Option A is what happens when we see a stiff, unchanging mass accelerating.
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a gray kangaroo can bound across a flat stretch of ground with each jump carrying it 8.0 m from the takeoff point. what is its horizontal speed?
A gray kangaroo can bound across a flat stretch of ground with each jump carrying it 8.0 m from the takeoff point, so his horizontal speed is 12.69 m/sec.
The projectile appears to be travelling straight forward without changing directions, according to the horizontal speed. The moment the projectile is launched, no net forces are exerted in a horizontal direction. As a result of zero acceleration, the projectile's horizontal speed remains constant throughout the trajectory motion.
To aid in their hopping, kangaroos have modified their bodies to include robust tails and larger rear feet. Some kangaroo subspecies, like red and grey kangaroos, are capable of successfully jump 10 feet vertically, 40 feet horizontally, and at speeds of over 30 mph because to these modifications.
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H= 0.0055m, R= 3m, How far did the object fall?
The formula s = (1/2)gt2 = 0.5 * 9.80665 * 82 = 313.8 m can be used to calculate the free fall distance. If you are aware of how high the object is.
How far can you fall into?Most falls occur from a height of 20 to 25 feet (6 to 8 metres), but anything higher than that can be fatal very quickly. According to a 2005 study conducted in Paris on 287 fall victims, falls from 8 storeys (30 metres) or above are always lethal.The highest survival thresholds for a person to tolerate impact velocity in water are ostensibly near to 100 ft/sec (68.2 mph) corrected velocity, or the equivalent of a 186-foot freefall.Nearly half of all fatal falls occur at a height between 0 and 20 feet, according to a study of construction accidents in India. Between 21 and 40-foot deadly falls made up the next-largest group. Alternatively stated, 20 feet is sufficient to be fata.To learn more about fall refer to:
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Two wires enter a box, are each connected to a terminal, and then exit again. The total conductor count is
Two wires enter a box, connect to individual terminals, and then leave the box once more. There are 2 conductor in total.
In physics, a conductor is a material that allows electric current to flow through it easily. This is in contrast to an insulator, which does not allow electric current to flow through it easily. Common examples of conductors include metals such as copper and aluminum, while common examples of insulators include rubber and plastic. Conductors are used in many electrical devices, such as wires and circuit boards, to help transfer electrical energy. The electrical resistance of a conductor is a measure of how easily electric current flows through it and is affected by factors such as the conductor's material, temperature, and cross-sectional area.
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you purchased 2.2 kg of apples from wollaston. you noticed that they used a spring scale with the smallest division of 17.7 g to weigh them. what is the relative error in this weight measurement as a percentage?
The weight measurement was off by 0.8% of the accepted value.
What is weight?Weight is a measure of the gravitational force that an object experiences due to its mass. Weight is typically measured in Newtons (N), and the formula for weight is mass multiplied by the acceleration due to gravity (g). Weight is an important factor in many activities such as sports, exercise, and even everyday tasks. The amount of weight an object carries affects its balance, stability, and momentum. Weight is an important factor to consider when using machines and tools.
Relative error is the ratio of the amount of error to the accepted value. To calculate the relative error in this weight measurement, we can use the following equation:
Relative Error = (17.7 g/2.2 kg) * 100%
The relative error in this weight measurement is 0.8%. This means that the weight measurement was off by 0.8% of the accepted value.
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Which of the following scenarios describes an object being acted on by a conservative force?
A scenario which describes an object being acted on by a conservative force is the one in which a feather falls from one end of a tube to the other inside a vacuum. Thus, the correct option is C.
What is Conservative force?The conservative force is a force with the property which the total work done in moving a particle between two points, it is independent of the path taken by the object. Equivalently, if a particle travels in a closed loop, then the total work done by the object is the sum of the independent forces which are acting along the path multiplied by the displacement of the object by a conservative force is zero.
A feather which is falling from one end of a tube to the other inside a vacuum is an example of conservative force. This is a Conservative force because, here we are looking at a vacuum and it is a closed system of no other forces present in it due to vacuum.
Therefore, the correct option is C.
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Your question is incomplete, most probably the complete question is:
Which of the following scenarios describes an object being acted on by a conservative force?
A. A woman hikes up a mountain to a point 20 feet above ground.
B. A dishwasher was pulled up to a window by a rope, using a pulley system.
C. A feather falls from one end of a tube to the other inside a vacuum.
D. A puck glides across and slowly comes to a stop on an ice rink.
a harmonic wave traveling along a string is generated by an oscillator that completes 180 vibrations per minute. if it is observed that a given crest, or maximum, travels 300 cm in 10 s, what is the wavelength?
The wavelength of the harmonic wave is 90 cm, if it completes 180 vibrations per minute and travels 300 cm in 10 s.
Time taken to complete 180 vibrations, = 1 minute = 60 sec
Number of vibrations completed by wave in 1 sec, = 180/60 = 3
So the frequency, f = 3 Hertz
Time taken to complete 1 vibration, T = 1/3 seconds
Wavelength is the distance travelled by the wave in one vibration/cycle. We know one cycle takes 1/3 seconds to complete, so the distance travelled by the wave in 1/3 second = (300/10) × (1/3) = 90 cm
So the wavelength λ = 90 cm.
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betelgeuse is the bright red star representing the left shoulder of the constellation orion. all the following statements about betelgeuse are true. which one can you infer from its red color?
Its surface is cooler than the surface of the sun is the statement that we can infer from its red color.
Betelgeuse is also called Alpha Orionis. It is the second brightest star in the constellation Orion, thus marking the eastern shoulder of the hunter. Its name is derived from the Arabic term, which means “the giant’s shoulder.” It is one of the most luminous stars in the sky at night.
Having an apparent magnitude of about 0.6 it is a variable star. Its size is roughly 764 times as that of the Sun. As the apparent magnitude of this star is 0.6 which is a comparison with the sunlight, we can say it is cooler than the surface of the sun.
Hence the correct option is A.
--The given question is incomplete, the complete question is,
"betelgeuse is the bright red star representing the left shoulder of the constellation orion. all the following statements about betelgeuse are true. which one can you infer from its red color? a) Its surface is cooler than the surface of the Sun. b) It is much more massive than the Sun c) It is much brighter than the Sun d) It is moving away from us
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A highway curves to the left with radius of curvature of 46 m and is banked at 19° so that cars can take this curve at higher speeds.
Consider a car of mass 843 kg whose tires have a static friction coefficient 0.88 against the pavement.
How fast can the car take this curve without skidding to the outside of the curve? The acceleration of gravity is 9.8 m/s^2
Answer in units of m/s.
The maximum speed in which the car can move on the curve without skidding to the outside of the curve is 12.46 m/s.
What is the maximum speed of the car without skidding?
The maximum speed in which the car can move on the curve without skidding to the outside of the curve is calculated by using the following formula.
v = √ ( rg tanθ )
where;
r is the radius of the curveg is acceleration due to gravityθ is the banking anglev = √ ( 46 x 9.8 x tan 19 )
v = 12.46 m/s
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Two billiard balls, each with a mass of 0. 35 kg, strike each other head-on. One ball is initially moving left at 4. 1 m/s and ends up moving right at 3. 5 m/s. The second ball is initially moving to the right at 3. 5 m/s. Find the velocity of the second ball
The velocity of the second ball will be 4.1 m/s towards the left, If the initial velocity of the second ball is 3.5 m/sec towards right.
Initial velocity of first ball, v₁ = +4.1 m/s [positive: towards the left]
Initial velocity of second ball, v₂ = -3.5 m/s [negative: towards the right]
final velocity after collision of first ball, v₃ = -3.5 m/s
Let the final velocity after collision of second ball, = v₄
Mass of each ball is 0.35 kg
By the law of conservation of momentum,
m₁v₁ + m₂v₂ = m₃v₃ + m₄v₄
0.35×(4.1) + 0.35(-3.5) = 0.35×(-3.5) + 0.35×v₄
4.1 - 3.5 = -3.5 + v₄
v₄ = +4.1
Positive sign indicates that the velocity will be towards the left.
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