3 students are in a race. How many ways can they finish in 1st, 2nd, and 3rd place?

Answers

Answer 1
They can finish in 1 way

Related Questions

A rectangular prism has a length of 3 inches, a width of 5 inches, and a height of 7 inches.

What is the volume of the prism?

Enter your answer in the box as a simplified mixed number or a decimal.


in.³

Answers

Answer:

105³

Step-by-step explanation:

3x5=15

15x7=105

105 is your answer.

What is the total area of the three triangles? 12.5 square units 13 square units 13.5 square units 14 square units

Answers

The area of the considered 3 triangles is given by: Option B: 13 sq. units.

How to find the area of a triangle whose vertices' coordinates are given?

Suppose the vertices of the considered triangle ABC are on [tex]A(A_x,A_y), B(B_x,B_y), C(C_x,C_y)[/tex], then, the area of the triangle is given by:

[tex]Area = \dfrac{|A_x(B_y-C_y) + B_x(C_y-A_y) + C_x(A_y-B_y)|}{2}[/tex]

For this case, the missing image is attached below.

The second and third triangle are easy as their base and height are parallel to x or y axis.

We will find area of third triangle by coordinates of its vertices.

Getting area of first triangle:

Coordinates of A : (4,10)Coordinates of B : (5,7)Coordinates of C : (7,8)

Thus, we get:

[tex]Area_{ABC} = \dfrac{|4(7-8) + 5(8-10) + 7(10-7)|}{2} = \dfrac{7}{2} = 3.5 \: \rm unit^2[/tex]

Area of second triangle = [tex]\dfrac{|RS| \times h}{2}[/tex]base, and h is the perpendicular line connecting from line RS and the vertex T

From figure we see:

|RS| = 3 units, h = 3 units

Thus, area of second triangle = [tex]3 \times 3 /2 = 4.5 \: \rm unit^2[/tex]

Area of third triangle = [tex]\dfrac{|XY| \times h}{2}[/tex] where XY is base, and h is the perpendicular line connecting from line XY and the vertex Z

From figure we see:

|XY| = 5 units, h = 2 units

Thus, Area of third triangle = [tex]5 \times 2 /2 = 5 \: \rm unit^2[/tex]

Total area = 3.5 + 4.5 + 5  = 13 sq. units

Thus, the area of the considered 3 triangles is given by: Option B: 13 sq. units.

Learn more about area of a triangle from its vertices' coordinates here:

https://brainly.com/question/2532574

Answer:

13

Step-by-step explanation:

I need help

Imagine that you designed a firework. When the firework first explodes, it splits into eight sparkles. Each of those sparkles then explodes and splits into eight new sparkles.

How many sparkles would the second explosion produce? Explain how you determined your answer.

Answers

Answer:

8 x 8 = 64

Step-by-step explanation:

Just including the second explosion, each of the 8 sparks bursts into 8, that means 8 sparks were produced 8 times, or 8x8

Answer:

1 sparkle Burst it produces 8 sparkles so you say 8×8×8×8×8×8×8×8

what fraction gives you an answer of 11/12

Answers

Hi there! The fraction that gives you 11/12 is 44/ 48.

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Hope this helps you!

HI!! Please answer this!

You install a mailbox by buriyng a post as shown. According to postal service guidelines, the bottom of the box must be at least 41 inches, but no more than 45 inches, above the road. Write two inequalities that describe the possible length x, in inches, of the post.

Answers

Answer:

41 ≤ x

x ≤ 45

Step-by-step explanation:

How has the polygon RQTS been translated to produce a polygon with Q’ at (-3, -3)?


shift down 5 units
shift down 6 units
shift down 2 units
shift down 3 units

Answers

Answer: Shift down 3 units

Step-by-step explanation:

From the figure its clear that the existing coordinate of the polygon RQTS are : (−3,0)

Since we have to translate the polygon to (−3,−3)

So:

−3−(−3)=0

−3−(0)=−3

Therefore shift down 3 units is the correct answer

Answer:

shift down 5 units

Step-by-step explanation:

i took the quiz

9x+3=14give your answer as an improper fraction in its simplest form

Answers

Answer:

11/9

Step-by-step explanation:

A box has a square base with side x cm , height 4 cm and volume 289 cm^3. Find x

Answers

Answer:

8.5 cm

Step-by-step explanation:

volume = height × area of base

since this a square, area of base = x²

so 289 = 4 × x²

x² = 289 ÷ 4

x² = 72.25

so x = √72.25

x = 8.5cm

hope this helps

Convert the following fraction to a decimal -11/16

Answers

Answer:

-0.6875

Step-by-step explanation:

[tex]Convert\ -11/16\ to\ decimal\\ \downarrow\\ -0.6875[/tex]

I hope this helps you

:)

Answer: -0.6875.

Step-by-step explanation: -1/16 is -0.0625, and if you add -1/16 eleven times, you get -0.6875.  Therefore, -11/16 as a decimal is -0.6875.

Have a great day! :)

Please help! Its due today!

Answers

Answer:

don't know if this is the right way butttt i'm going to give it a shot

Step-by-step explanation:

Cost: I'm guessing this is for the rent for the shoes or is the total cost?

Bowler World: 5 + 1.1g = c | c + 1.1g = t {(this is the other option) probs not correct}

Lucky Spares: 3 + 1.5g = c | c + 1.5g = t

K so personally you should choose option 1 (for example: 5 + 1.1g = c), i have no idea how the proper format is supposed to be

either i hope this helps :)

Use the distributive property to write the following expression in expanded form.

5(7h + 3m)

Answers

hello!

==============================================================

The distributive property states that:-

[tex]\bigstar{\underline{\boxed{\pmb{a(b+c)=ab+ac}}}[/tex]

Simplify:-

[tex]\bigstar{\boxed{\pmb{5(7h+3m)}}}[/tex]

[tex]\longmapsto\sf{(5~times~7h)+)5*3m)[/tex]

[tex]\longmapsto\sf{35h*15m}[/tex]

===============================================================

note:-

Hope everything is clear; if you need any clarification/explanation, kindly let me know, and I will comment and/or edit my answer :)

Which shapes have two pairs of parallel sides

Answers

Answer:

a rhombus would have 2 pairs of parallel sides, or a parallelogram. (First image is parallelogram and second is rhombus)


Which answers describe the shape below? Check all that apply.


Answers

Answer: C, D, and F

-> C. Quadrilateral

-> D. Parallelogram

-> F. Rectangle

Step-by-step explanation:

-> A. Square

     [✗] A square needs 4 congruent sides, this only has "two sets of two"

-> B. Trapezoid

     [✗] A trapezoid has one pair of parallel sides, but this shape has two

-> C. Quadrilateral

     [✓] This shape has four sides

-> D. Parallelogram

     [✓] This shape's opposite sides are congruent and parallel

-> E. Rhombus

     [✗] This shape's opposite angles/sides are equal, but not all of it's sides are congruent

-> F. Rectangle

     [✓] This shape has four sides, and it's opposite sides are congruent

what is the equation of the line that passes through each pair of points for (-2,3) (3,-2)

Answers

Answer:

y = -x + 1

example:

(-2, 3)

y = -(-2) + 1

y = 2 + 1

y = 3

Answer:

y = -x + 1

Step-by-step explanation:

slope = (y2-y1)/(x2-x1) = (-2-3)/(3-(-2)) = -5/5 = -1

y-int: y=mx+b --> plug in a point --> 3 = (-1)(-2)+b --> b=1

y = -x + 1

Find the geometric mean of 3 and 13. Show work

Answers

Answer:

b

Step-by-step explanation:

a/b=c/d

ad=bc

3/x=x/13

3*13=x*x

√39=√x2

6.244997998398=x

differentiate the following with respect to x

irrelevant answers will be reported​

Answers

Answer:

[tex]\displaystyle y' = - \frac{e^{x^2 + 7} \sqrt{\csc 5x} \Bigg[ \bigg[ 5 \cot (5x) - 4x \bigg] \sin (3x + 4) - 6 \cos (3x + 4) \Bigg] }{2}[/tex]

General Formulas and Concepts:

Calculus

Differentiation

DerivativesDerivative Notation

Derivative Property [Multiplied Constant]:
[tex]\displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)[/tex]

Derivative Property [Addition/Subtraction]:
[tex]\displaystyle \frac{d}{dx}[f(x) + g(x)] = \frac{d}{dx}[f(x)] + \frac{d}{dx}[g(x)][/tex]

Derivative Rule [Basic Power Rule]:

f(x) = cxⁿf’(x) = c·nxⁿ⁻¹

Derivative Rule [Product Rule]:
[tex]\displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)[/tex]

Derivative Rule [Chain Rule]:
[tex]\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)[/tex]

Step-by-step explanation:

Step 1: Define

Identify.

[tex]\displaystyle y = e^{x^2 + 7} \sin (3x + 4) \sqrt{\csc (5x)}[/tex]

Step 2: Differentiate

Apply Derivative Rule [Product Rule]:
[tex]\displaystyle y' = \big[ e^{x^2 + 7} \big]' \sin (3x + 4) \sqrt{\csc (5x)} + e^{x^2 + 7} \big[ \sin (3x + 4) \big]' \sqrt{\csc (5x)} + e^{x^2 + 7} \sin (3x + 4) \big[ \sqrt{\csc (5x)} \big]'[/tex]Apply Exponential Differentiation [Derivative Rule - Chain Rule]:
[tex]\displaystyle y' = e^{x^2 + 7} (x^2 + 7)' \sin (3x + 4) \sqrt{\csc (5x)} + e^{x^2 + 7} \big[ \sin (3x + 4) \big]' \sqrt{\csc (5x)} + e^{x^2 + 7} \sin (3x + 4) \big[ \sqrt{\csc (5x)} \big]'[/tex]Apply Derivative Rules and Properties [Basic Power Rule + Addition/Subtraction]:
[tex]\displaystyle y' = 2xe^{x^2 + 7} \sin (3x + 4) \sqrt{\csc (5x)} + e^{x^2 + 7} \big[ \sin (3x + 4) \big]' \sqrt{\csc (5x)} + e^{x^2 + 7} \sin (3x + 4) \big[ \sqrt{\csc (5x)} \big]'[/tex]Apply Trigonometric Differentiation [Derivative Rule - Chain Rule]:
[tex]\displaystyle y' = 2xe^{x^2 + 7} \sin (3x + 4) \sqrt{\csc (5x)} + e^{x^2 + 7} \cos (3x + 4) (3x + 4)' \sqrt{\csc (5x)} + e^{x^2 + 7} \sin (3x + 4) \big[ \sqrt{\csc (5x)} \big]'[/tex]Apply Derivative Rules and Properties [Basic Power Rule + Addition/Subtraction]:
[tex]\displaystyle y' = 2xe^{x^2 + 7} \sin (3x + 4) \sqrt{\csc (5x)} + 3e^{x^2 + 7} \cos (3x + 4) \sqrt{\csc (5x)} + e^{x^2 + 7} \sin (3x + 4) \big[ \sqrt{\csc (5x)} \big]'[/tex]Apply Derivative Rules [Basic Power Rule + Chain Rule]:
[tex]\displaystyle y' = 2xe^{x^2 + 7} \sin (3x + 4) \sqrt{\csc (5x)} + 3e^{x^2 + 7} \cos (3x + 4) \sqrt{\csc (5x)} + e^{x^2 + 7} \sin (3x + 4) \frac{\big[ \csc (5x) \big] '}{2\sqrt{\csc (5x)}}[/tex]Apply Trigonometric Differentiation [Derivative Rule - Chain Rule]:
[tex]\displaystyle y' = 2xe^{x^2 + 7} \sin (3x + 4) \sqrt{\csc (5x)} + 3e^{x^2 + 7} \cos (3x + 4) \sqrt{\csc (5x)} + e^{x^2 + 7} \sin (3x + 4) \frac{- \csc (5x) \cot (5x) (5x)'}{2\sqrt{\csc (5x)}}[/tex]Apply Derivative Rules and Properties [Basic Power Rule + Multiplied Constant]:
[tex]\displaystyle y' = 2xe^{x^2 + 7} \sin (3x + 4) \sqrt{\csc (5x)} + 3e^{x^2 + 7} \cos (3x + 4) \sqrt{\csc (5x)} + e^{x^2 + 7} \sin (3x + 4) \frac{-5 \csc (5x) \cot (5x)}{2\sqrt{\csc (5x)}}[/tex]Rewrite:
[tex]\displaystyle y' = - \frac{e^{x^2 + 7} \sqrt{\csc 5x} \Bigg[ \bigg[ 5 \cot (5x) - 4x \bigg] \sin (3x + 4) - 6 \cos (3x + 4) \Bigg] }{2}[/tex]

∴ we have found the derivative of the function.

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Learn more about differentiation: https://brainly.com/question/26836290
Learn more about calculus: https://brainly.com/question/23558817

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Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

To find the derivative of the function [tex]\displaystyle\sf\:y=e^{x^{2}+7}\sin(3x+4)\sqrt{\csc(5x)}}[/tex] with respect to [tex]\displaystyle\sf x[/tex], we'll use the chain rule and product rule.

Let's break down the function into its individual parts:

[tex]\displaystyle\sf u= e^{x^{2}+7}[/tex]

[tex]\displaystyle\sf v= \sin(3x+4)[/tex]

[tex]\displaystyle\sf w= \sqrt{\csc(5x)}}[/tex]

Now, let's differentiate each part separately:

Using the chain rule, the derivative of [tex]\displaystyle\sf u= e^{x^{2}+7}[/tex] is:

[tex]\displaystyle\sf \dfrac{du}{dx}= (2x)e^{x^{2}+7}[/tex]

Using the chain rule, the derivative of [tex]\displaystyle\sf v= \sin(3x+4)[/tex] is:

[tex]\displaystyle\sf \dfrac{dv}{dx}= 3\cos(3x+4)[/tex]

To differentiate [tex]\displaystyle\sf w= \sqrt{\csc(5x)}}[/tex], we can rewrite it as [tex]\displaystyle\sf w= (\csc(5x))^{1/2}[/tex]. Using the chain rule, the derivative of [tex]\displaystyle\sf w[/tex] is:

[tex]\displaystyle\sf \dfrac{dw}{dx}= \dfrac{1}{2}(\csc(5x))^{-1/2}(-\cot(5x))(5)[/tex]

Simplifying the derivative [tex]\displaystyle\sf \dfrac{dw}{dx}[/tex]:

[tex]\displaystyle\sf \dfrac{dw}{dx}= -\dfrac{5\cot(5x)}{2\sqrt{\csc(5x)}}[/tex]

Now, using the product rule, the derivative of [tex]\displaystyle\sf y[/tex] with respect to [tex]\displaystyle\sf x[/tex] can be calculated as follows:

[tex]\displaystyle\sf \dfrac{dy}{dx}= \dfrac{du}{dx} \cdot v \cdot w + u \cdot \dfrac{dv}{dx} \cdot w + u \cdot v \cdot \dfrac{dw}{dx}[/tex]

Substituting the values of [tex]\displaystyle\sf \dfrac{du}{dx}[/tex], [tex]\displaystyle\sf \dfrac{dv}{dx}[/tex], and [tex]\displaystyle\sf \dfrac{dw}{dx}[/tex]:

[tex]\displaystyle\sf \dfrac{dy}{dx}= \left((2x)e^{x^{2}+7}\right) \cdot \sin(3x+4) \cdot \sqrt{\csc(5x)} + e^{x^{2}+7} \cdot \left(3\cos(3x+4)\right) \cdot \sqrt{\csc(5x)} - e^{x^{2}+7} \cdot \sin(3x+4) \cdot \dfrac{5\cot(5x)}{2\sqrt{\csc(5x)}}[/tex]

Simplifying further:

[tex]\displaystyle\sf \dfrac{dy}{dx}= \left(2xe^{x^{2}+7}\right) \sin(3x+4) \sqrt{\csc(5x)} + 3e^{x^{2}+7}\cos(3x+4) \sqrt{\csc(5x)} - \dfrac{5e^{x^{2}+7} \sin(3x+4) \cot(5x)}{2\sqrt{\csc(5x)}}[/tex]

Therefore, the derivative of [tex]\displaystyle\sf y[/tex] with respect to [tex]\displaystyle\sf x[/tex] is:

[tex]\displaystyle\sf y' = -2e^{x^{2}+7}\csc(5x)[5\cot(5x)-4x]\sin(3x+4) - 3e^{x^{2}+7}\sqrt{\csc(5x)}\cos(3x+4) - \dfrac{5e^{x^{2}+7}\sin(3x+4)\cot(5x)}{2\sqrt{\csc(5x)}}[/tex]

Simplifying further, we have:

[tex]\displaystyle\sf y' = -2e^{x^{2}+7}\csc(5x)[5\cot(5x)-4x \sin(3x+4) - 6e^{x^{2}+7}\cos(3x+4)\sqrt{\csc(5x)}[/tex]

Therefore, the derivative of [tex]\displaystyle\sf y[/tex] with respect to [tex]\displaystyle\sf x[/tex] is:

[tex]\displaystyle\sf y' = -2e^{x^{2}+7}\csc(5x)[5\cot(5x)-4x]\sin(3x+4) - 6e^{x^{2}+7}\cos(3x+4)\sqrt{\csc(5x)}[/tex]

[tex]\huge{\mathfrak{\colorbox{black}{\textcolor{lime}{I\:hope\:this\:helps\:!\:\:}}}}[/tex]

♥️ [tex]\large{\underline{\textcolor{red}{\mathcal{SUMIT\:\:ROY\:\:(:\:\:}}}}[/tex]

Two sides of a parallelogram are 110 feet and 850 feet. The measure of the angle between these sides is 157 Find the area of the parallelogram to the nearest square foot.

Answers

Answer: 36533

Step-by-step explanation:

Find the area of the regular polygon. Give the answer to the nearest tenth.
Square with a radius of 13 m.

Answers

Answer:

338 m^2

Hope this helps!

If this helps please show your thanks by marking brainliest ;)

IDENTIFY THE PROPERTY WHICH JUSTIFIES THE FOLLOWING CONCLUSION

A. REFLECTIVE PROPERTY
B. ADDITION PROPERTY OF EQUALITY
C. SYMMETRIC PROPERTY
D. MULTIPLICATION PROPERTY OF EQUALITY

1. If ×=4, then × + 2=7
....__.....__
2.AB = AB

3. If × = y, Then 2× = 2y

4. If 9 = 6+3, then 6+3 =9

Please answer correctly do not concentrate wrong and rely only on the pontos:)​

Answers

Answer:

Step-by-step explanation:

17) B. They are adding 2 to both sides.

18) A. A segment is equal to itself.

19) D. They are multiplying both sides by 2.

20) C. They are simply swapping the left and right hand sides of the equation

What are the new coordinates of Point R after a 90 degree clockwise rotation?

Answers

Step-by-step explanation:

P(-4,-1)======P'(-1,4)

Q(-4,-3)=====Q'(-3,4)

R(-2,3)======R'(3,2)

Alex constructs a circle that passes through all three vertices of the triangle shown.
E
Where will the center of the circle be located?

Answers

Answer: A, TRUST ME!

Step-by-step explanation:

Calculate the average daily balance, finance charge, and new balance using the average daily balance method. Round all dollar amounts to the nearest cent. If applicable, include a thousands comma. Monthly rate: 1.75% Date Payments Purchases Balance Number of Days Product 9/1-9/5 $387.525 1,937.60 976 $50.00 $337.521 337.52 977 - 9/18 A В С 9/19 $62.66 $400.181 400.18 9/20-9/30 D E F Total 30 G A= $ BE C= $ D=$ E= F=$ G=$ Average daily balance : 30 = $ Finance charge = monthly rate x average daily balance = $ New balance = previous balance payment/credits + finance charge + new purchases = $​

Answers

Answer:

Step-by-step explanation:

Credit should go to the previous helper here:

https://brainly.com/question/21285117

I have not cross-checked but the previous answers were:

"

For average daily balance:

Form date 9/1 to date 9/5 :

Balance x number of the days = $ 387.52 x 5 days = $ 1937.6

As on date 9/6 :

($ 387.52 - $ 50.00) x 1 day = $ 337.52

From date 9/7 to date 9/18 :

Balance = $ 337.50

Number of days = 12 days

Therefore, product = 12 days x $ 337.52

= $ 4050.24

As on 9/19 :

($ 337.52  + $ 62.66) x 1 day = $ 400.18

From date 9/20 to date 9/30

Balance :$ 400.18

Number of days = 11 days

Therefore, product = 11 days x $ 400.18

= $ 4401.98

Average daily balance

=  ($ 1937.6 +  $ 337.50 + $ 4050.24 + $ 400.18 + $ 4401.98) / 30

= $ 370.91

Finance charge = $ 370.91 x 1.75 %

= $ 6.49

New balance = $ 370.91 + $ 6.49

= $ 377.4

"

Four beakers contain water as shown below.



Which two beakers of water can be combined to fill one beaker to exactly 1,000 mL?


beaker B and beaker C

beaker B and beaker C

beaker A and beaker C

beaker A and beaker C

beaker A and beaker B

beaker A and beaker B

beaker A and beaker D

beaker A and beaker D

Answers

Answer:

A&C

Step-by-step explanation:

It would be A because it has 750 mL and C because it has 250mL and 750+250=1000

Also can you mark brainlyist you dont have to

Help me please 4 questions 50 points this is due today

Answers

Answer:

Q15: A

Q12: A,C,D

Q13: B

Q14: C

Answer:

1) Left 5, Down 1

2) A, C, D

3) B

4) D

Step-by-step explanation:

Desmos graphing calculator will help you with all of these.

Henry found some pants on sale for 60% off. If the pants were originally $100, how much are they now?

Answers

If something is 60% off, that means it is now going to be 40% of its original price because

100 - 60 = 40

To find final price multiply the percentage as a decimal by the price.

40% is 40/100 which as a decimal is 0.4

0.4 x 100 = $40

The pants will be 40 dollars.

Answer:

$40

Step-by-step explanation:

Old Sale Price = $100

It was given 60% discount

 60% of 100 = 0.6 x 100 = 60

we remove the discount from  the original price( 100 -60 ) =  40.

So the new sale price for the pants are now $40

You are paid $1380 for working 80 hours in two weeks at your full-time job. At this rate of pay, how much would you be paid if ypu worked 100 hours in a month

Answers

Answer:

To answer this, we have to do the equation below:

[tex]1,380/80[/tex]

When we do this, we come up with the answer of 17.25

Now we know that we get paid $17.25 an hour.

Now, we must do the equation below:

[tex]100 X 17.25[/tex]

When we multiply, we get the answer of 1,725

So, we get paid $1,725 if we work for 100 hours.

Step-by-step explanation:

Hope this helps!

PLEASE MARK ME AS BRAINLIEST I REALLY WANT TO LEVEL UP

What does the fair and accurate credit transactions act provide for consumers? a. it entitles consumers to get one free credit report per year from the big three reporting agencies. b. it entitles consumers to notify credit reporting agencies if their identity is stolen. c. it entitles consumers to file a complaint with the federal trade commission if their identity is stolen. d. it entitles consumers to find out about who has access to personal information and if it is being handled securely.

Answers

Fair and accurate credit transactions act entitles consumers to find out about who has access to personal information and if it is being handled securely.

What is fair and accurate credit transactions act?

Fair and accurate credit transactions act passed in 2003 which is made to improve the protection of customer.

The objective of fair and accurate credit transactions act-

To improve the protection of customer.Ensure provisions in case of identity theft.Provide access to consumers to find out about who has access to personal information.

Thus, fair and accurate credit transactions act entitles consumers to find out about who has access to personal information and if it is being handled securely.

Option d is the correct option.

Learn more about the fair and accurate credit transactions act here

https://brainly.com/question/6656307

Answer: a. It entitles consumers to get one free credit report per year from the big three reporting agencies.

Step-by-step explanation: quizlet

Problem 2
What is the probability of pulling a heart, replacing it, pulling a club, replacing it, pulling a diamond,
replacing it, then pulling a spade, all from a standard deck?.

Answers

Answer:

subtract one for heart drawn without replacement leaves 51 cards on which thirteen are clubs. probability of drawing club 13/51. After drawing a heart as first card there are 51 cards left and 13 of them are clubs. So the probability on drawing a club then equals 13/51

Maura is jogging on her treadmill. She runs 2.25 miles in
1
2
of an hour. At that speed, how many miles could Maura run in 1
1
2
hours?

Answers

Answer:

6.75 miles

Step-by-step explanation:

Since it is 2.25 per 1/2 hour to get to 1 1/2 hour you multiply by 3. Then you do 2.25 times 3 and it gives you 6.75 miles.

hope that helps

Answer:

6.75 miles

Step-by-step explanation:

How many 1/2 hours in 1 1/2 hour? 1.5 ÷ 0.5 = 3

2.25 x 3 = 6.75

OR

Find the unit rate = 2.25 x 2 = 4.50 (we multiply it by 2 because there 2 half hours in an hour)
4.50 x 1.50 = 6.75

and Intervention
1. The library is 5 miles from the post office. How many yards is the library
from the post office?
yards

Answers

8800 yards. I think, not sure.
Other Questions
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