2. What number is equal to five units + three tenths? Circle the correct answer.
0.53
0.35
5.3
3.5
53
35

Answer:

8/343

so A

Step-by-step explanation:

Answer:

There is a strong positive relationship, therefore as x increases, y increases

Step-by-step explanation:

Answer:

-2

Step-by-step explanation:

Answer:

-2

Step-by-step explanation:

the y intercept is the point on the graph where the line crosses the x axis

Answer:

11 7/15 (Not listed on paper!)

Step-by-step explanation:

6 12 /15  +  4 4 /6  =

(6 + 4) + (  12 /15  +  4/ 6 )

=  10 +  12 × 2

15 × 2

+  

4 × 5

6 × 5

=  10 +  

24 /30

+  

20 /30

=  10 +  

24 + 20 /30

=  10 +  

44 /30

=  10 +  

44 ÷ 2

30 ÷ 2

=  10 +  

22 /15

=  10 +  

1 7 /15

=  

11 7 /15

(Eleven and seven fifteenths)

[Sorry but all of the answers you gave are all wrong!]

Step-by-step explanation:

Here is the answer...

Hope this helps you

Answer:

20

Step-by-step explanation:

3x+14=2(2x-3)

3x+14=4x-6

3x-4x=-6-14

-x=-20

X=20

So the valueof X is 20

Answer:

Not a function

Step-by-step explanation:

Answer:

I think it’s A,C, and E

Step-by-step explanation:

I’m not for sure but if you plot those points in the shaded region for graph C, those should be correct .

Answer:

3

Step-by-step explanation:

Answer:

it would be 8 to 15

Step-by-step explanation:

you would write it as a fraction 8/15. then, you would try and simplify it. because you cant simplify 8/15 anymore, your answer would be 8/15! hope this helps :)

Answer:

3=15

4=20

5=25

Step-by-step explanation:

bold are the answers

Answer:

Following are the solution to this question:

Step-by-step explanation:

C'(t) was its time, in years, or t shift of cash per unit. That C'(1980) meaning, therefore, becomes the change of cashier's population to t = 1980.  

They could either use t = 1970 or t = 1990 to approximate the C'(1980) price. When using t = 1970:

[tex]C'(1980) = \frac{[C(1980) - C(1970)]}{[1980 - 1970]}\\\\[/tex]

              [tex]= \frac{(571 - 265)}{10}\\\\ = \$ \ 30.6 \\[/tex]

t = 1990:

[tex]C'(1980) = \frac{[C(1980) - C(1990)]}{[1980 - 1990]}[/tex]

              [tex]= \frac{(571 - 1063)}{ -10} \\\\= \$ \ 49.2[/tex]

Answer:

b. 36

Step-by-step explanation:

Evaluate x^4 - 4 x^2 + 3 x where x = -3:

x^4 - 4 x^2 + 3 x = (-3)^4 - 4×(-3)^2 - 3×3

Hint: | Evaluate (-3)^2.

(-3)^2 = 9:

(-3)^4 - 49 - 3×3

Hint: | Determine the sign of (-3)^4.

(-3)^4 = (-1)^4×3^4 = 1×3^4:

3^4 - 4×9 - 3×3

Hint: | Compute 3^4 by repeated squaring.

3^4 = (3^2)^2:

(3^2)^2 - 4×9 - 3×3

Hint: | Evaluate 3^2.

3^2 = 9:

9^2 - 4×9 - 3×3

Hint: | Evaluate 9^2.

9^2 = 81:

81 - 4×9 - 3×3

Hint: | Multiply -4 and 9 together.

-4×9 = -36:

81 + -36 - 3×3

Hint: | Multiply 3 and -3 together.

3 (-3) = -9:

81 - 36 + -9

Hint: | Group the negative terms in 81 - 36 - 9 together and factor out the minus sign.

81 - 36 - 9 = 81 - (36 + 9):

81 - (36 + 9)

Hint: | Evaluate 36 + 9 using long addition.

| 1 |  

| 3 | 6

+ | | 9

| 4 | 5:

81 - 45

Hint: | Subtract 45 from 81.

| 7 | 11

| 8 | 1

- | 4 | 5

| 3 | 6:

Answer: 36

Answer:

$12.55

Step-by-step explanation:

25-6.75=18.25

18.25-3.70=14.55

14.55-2=12.55

Miguel has $12.55 left

Answer: AEC = 80

              X=30

YW ;)

Answer:

No, every student will have 3.2 minutes

Answer:

Each student has approximately 3 minutes and 12 seconds.

Step-by-step explanation:

You divide the total amount of minutes by the total amount of students. 48/15=3.2

After you get your answer, you convert to minutes. There are 3 minutes and the .2 converts to 12 seconds

Answer:

slope = 3

Step-by-step explanation:

to find the slope you do (y2-y1)/(x2-x1)=m

so we can plug the points into this formula

(5,7)     (2,-2)

x1 y1    x2 y2

-2-7/2-5=m

-9/-3=m

Simplifies to

3=m

Answer:

a) there is no chart but we can elaborate one:

taxi fee            half-miles driven

$1.75                      0

$2.05                     1

$2.35                     2

$2.65                     3

$2.95                     4

$3.25                     5

$3.55                     6

b) y = 0.3x + 1.75

where:

y = taxi fee

x = half miles driven

Answer:

The factors for the numerator [n] and denominator [d] after reducing will be:

[tex]\frac{x^2-25}{x^2-4x}\div \:\frac{2x^2+2x-40}{x^3-x}=\frac{\left(x-5\right)\left(x+1\right)\left(x-1\right)}{2\left(x-4\right)^2}[/tex]

Step-by-step explanation:

Given the expression

[tex]\frac{x^2-25}{x^2-4x}\div \frac{2x^2+2x-40}{x^3-x}[/tex]

[tex]\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a}{b}\div \frac{c}{d}=\frac{a}{b}\times \frac{d}{c}[/tex]

[tex]=\frac{x^2-25}{x^2-4x}\times \frac{x^3-x}{2x^2+2x-40}[/tex]

[tex]\mathrm{Multiply\:fractions}:\quad \frac{a}{b}\times \frac{c}{d}=\frac{a\:\times \:c}{b\:\times \:d}[/tex]

[tex]=\frac{\left(x^2-25\right)\left(x^3-x\right)}{\left(x^2-4x\right)\left(2x^2+2x-40\right)}[/tex]

[tex]=\frac{\left(x^2-25\right)x\left(x^2-1\right)}{\left(x^2-4x\right)\left(2x^2+2x-40\right)}[/tex]

[tex]\mathrm{Cancel\:the\:common\:factor:}\:x[/tex]

[tex]=\frac{\left(x^2-25\right)\left(x^2-1\right)}{2\left(x-4\right)\left(x^2+x-20\right)}[/tex]

∵ As factor  [tex]\left(x^2-25\right)\left(x^2-1\right)=\left(x+5\right)\left(x-5\right)\left(x+1\right)\left(x-1\right)[/tex]

so the expression becomes

[tex]=\frac{\left(x+5\right)\left(x-5\right)\left(x+1\right)\left(x-1\right)}{2\left(x-4\right)\left(x^2+x-20\right)}[/tex]

∵ As factor [tex]2\left(x-4\right)\left(x^2+x-20\right)=2\left(x-4\right)^2\left(x+5\right)[/tex]

so the expression becomes

[tex]=\frac{\left(x+5\right)\left(x-5\right)\left(x+1\right)\left(x-1\right)}{2\left(x-4\right)^2\left(x+5\right)}[/tex]

[tex]\mathrm{Cancel\:the\:common\:factor:}\:x+5[/tex]

[tex]=\frac{\left(x-5\right)\left(x+1\right)\left(x-1\right)}{2\left(x-4\right)^2}[/tex]

Therefore, the factors for the numerator [n] and denominator [d] after reducing will be:

[tex]\frac{x^2-25}{x^2-4x}\div \:\frac{2x^2+2x-40}{x^3-x}=\frac{\left(x-5\right)\left(x+1\right)\left(x-1\right)}{2\left(x-4\right)^2}[/tex]

Answer:

Lesson 2 and metric conversions from Module 2. ... Problem 2: Convert hours to minutes. ... of minutes in one hour. How many minutes are in an hour? 0. 1. 2. 3. 4. 5. 6. 7. 8.

The complete table is given below. Then the correct option is C.

       Hours     Minutes

The analysis of mathematical representations is algebra, and the handling of those symbols is logic.

The following is a conversion table for hours and minutes.

We know that in one hour, there are 60 minutes.

In two hours, there are 120 minutes.

In three hours, there are 180 minutes.

Similarly, in four hours, there are 240 minutes.

Then the complete table is given below.

Hours     Minutes

  2             120

  3             180

  4             240

Then the correct option is C.

The complete question is given below.

The following is a conversion table for hours and minutes. Which numbers belong in the hour's column?

Hours        Minutes

                    120

                    180

                    240

More about the Algebra link is given below.

https://brainly.com/question/953809

#SPJ5

Answer:

I don't know how you would submit this but I do know it's a transformation. So you would move it across the x-axis 4 or 5 times depending on the shape. So I would maybe just write out each individual number like 3,4,5

Step-by-step explanation:

Answer: 109.5

Step-by-step explanation: EACH year for three years would be 1095 if you  multiply 365 (each year) by 3 (the amount of years) and then divide that by 10. Im not entirely sure but I hope I helped

Answer:

Your answer is: ↓

If your converting in Logarithmic Form then your answer is: [tex]log_{i}(-1)=2[/tex]

If you are trying to figure if that equation is determined T/F: The answer is T.

If you are trying to evaluate (expand) the question your answer is:[tex]-1=-1[/tex]

Step-by-step explanation:

Hope this helped : )

Answer:

(1,1)

Step-by-step explanation:

Answer:

6?

Step-by-step explanation:

Answer:

6

Step-by-step explanation:

2 + 4 =6

just add 2 by 4 than ans 6

Answer:

The company is expected the company will receive

Answer:

126.8 Hope this helps