Chemistry College

2. Suppose you are testing the gas in laboratory. If you inserted the burning magnesium ribbon inside the gas jar and magnesium ribbon burnt completely and formed light yellow ash as residue, then which gas was there in the gas jar and what is the name of compound present in yellow ash?​

Answers

Answer 1

When the magnesium ribbon is burned, it enters the carbon dioxide gas jar and continues to burn. The carbon is left behind as a black soot and extra energy is released as a result of the reaction where the magnesium atoms join the oxygen in the carbon dioxide to form magnesium oxide.

Magnesium ribbon is used in pyrotechnics to ignite thermite reactions or to create certain firework mixes. One of the most popular techniques to start chemical reactions that need a higher temperature to ignite is with magnesium ribbon.The light produced by the burning magnesium ribbon is strong enough to temporarily impair vision. Avert looking at the light source directly. Magnesium combustion in air generates strong heat that can result in burns and start the combustion process in combustible materials.

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Related Questions

3. 135 g of ice is placed in a beaker of water. The water temperature in the beaker is 67 °C. After all the icemelts, the final water temperature in the beaker is 19.7 °C. 4 ptsHeat of fusion for water = 334 J/g. Specific heat of water = 4.184 J/g °C. T2-T1 = 47.3 °C.Note there are a couple different ways to solve this problems to sove this por(a) Determine the initial volume of water in the beaker (before the ice was added).(b) Determine the final volume of water in the beaker (after all the ice has melted).

Answers

Answer:

Explanation:

Answer to the 1st one. I have my doubts for the second one so didn't post :)

How do I write the Empirical Formula for: A compound composed of: 9.93% carbon, 58.6% chlorine, and 31.4% fluorine

Answers

The empirical formula for a compound composed of 9.93% carbon, 58.6% chlorine, and 31.4% fluorine is CCl₂F₂.

To write the empirical formula, let us assume that total mass of the compound is 100 g, then-

Mass of carbon = 9.93 g

Mass of chlorine = 58.6 g

Mass of fluorine = 31.4 g

We know that,

Molar mass of Carbon = 12.0 g/mol

Molar mass of Chlorine = 35.5 g/mol

Molar mass of Fluorine = 18.9 g/mol

Now, we will calculate the number of moles of each using the formula -

Number of moles = Given mass

                                 Molar mass

Moles of Carbon =   9.93 g     = 0.82 mol

                               12.01 g/mol

Moles of Chlorine =    58.6 g     = 1.65 mol

                                 35.5 g/mol

Moles of fluorine =    31.4 g     = 1.66 mol

                                18.9 g/mol

Now, divide each value with the smallest amount of mole we got,

carbon = 0.82 = 1

               0.82

chlorine = 1.65 =  2

                 0.82

fluorine = 1.66 = 2

                0.82

Therefore, the empirical formula of the compound can be written as - CCl₂F₂

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A bike rides at an average speed of 25 km/h. How many minutes will it take for this rider to ride a distance of 20 km?

Answers

Answer:

48 minutes

Explanation:

60 divided by 25 equals 2.4 then you times 2.4 by 20

Which of the following will not affect the rate of a reaction?nature of the reactantscolor of reactanttemperatureconcentration of a reactant

Answers

Answer:

Color of reactant. Option B is correct

Explanations:What is a rate of reactions?

This is defined as the speed at which a reaction takes place. It can be expressed in terms of the concentration of reactants or products formed per unit time.

The following are the factors that affects reaction rate.

- concentration of a reactant

- Temperature

- Nature of the reactant

- Surface Area

- Catalysts.

Based on the explanations above, we can conclude that the color of reactant will not affect the rate of a reaction

number of litres of gas in 4.51 mol Xe

Answers

First, we assume STP conditions and Ideal gas conditions.

In STP conditions, we say that:

1 mol of any gas = 22.4 L (liters)

Procedure:

1 mol Xe ------ 22.4 L (STP)

4.51 moles Xe ------- X

X = 101 L

Answer: 101 L

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