2 right triangles have identical angle measures but different side lengths. The first triangle has side lengths of 6, 10, 8 and the second triangle has side lengths of 3, 5, 4. Which transformation maps the large triangle onto the small triangle?

Answers

Answer 1

Answer:

The transformation is 0.5

Step-by-step explanation:

The lengths of the second triangle is just half the length of the first triangle, from the center. As it is just resizing, the angles would not change, resulting in the same triangle, except for size.

Answer 2

Answer:

A- Dilation

Step-by-step explanation:

It doubles the length for all sides of the small traingle.


Related Questions

(4w+32)(-w-5)=0 solution set​

Answers

Answer:

W=5 w=8

Step-by-step explanation:

Giving brainiest explain answer

Answers

Answer:

A.) -5

Step-by-step explanation:

Slope Formula --->     [tex]m = \frac{y_2 - y_1}{x_2 - x_1}[/tex]       m = slope

[tex]m = \frac{2 - (-3)}{-2 - (-1)}[/tex]

Eliminate negatives:

[tex]m = \frac{2 + 3}{ -2 + 1}[/tex]

Solve:

[tex]m = \frac{5}{-1}[/tex]

Simplify:

[tex]m = -5[/tex]

—16t^2 + 64t + 3
Please help as soon as possible 33 points if you do it!!

Answers

Answer:

51t^3

Step-by-step explanation:

64+3=67

67 +(-16)=51

t^2 +t= t^3

now you just add them up but they cant be combined because one is a number and the other a variable w an exponent so we just get 51t^3

If you’re simplifying it’s 64t-253 and if your factoring it’s the same thing as well

y = 3x = 2
=
- x + 6

Answers

(y,x)- 8,—2 i’m not smart i just looked this up

Subtract 7b(2a 2 +5a-7) from (7a 2 -a+3 )-3b(6a 2 -b+3)

Answers

Answer:

[tex]\huge\boxed{-32a^2b+7a^2+3b^2-35ab-a+40b+3}[/tex]

Step-by-step explanation:

[tex]7b(2a^2+5a-7)\qquad|\text{use the distributive property}\\\\=(7b)(2a^2)+(7b)(5a)+(7b)(-7)=14a^2b+35ab-49b\\\\\\(7a^2-a+3)-3b(6a^2-b+3)\qquad|\text{use the distributive property}\\\\=7a^2-a+3+(-3b)(6a^2)+(-3b)(-b)+(-3b)(3)\\\\=7a^2-a+3-18a^2b+3b^2-9b[/tex]

Substraction

[tex](7a^2-a+3-18a^2b+3b^2-9b)-(14a^2b+35ab-49b)\\\\=7a^2-a+3-18a^2b+3b^2-9b-14a^2b-35ab+49b\\\\\text{combine like terms}\\\\=(-18a^2b-14a^2b)+7a^2+3b^2-35ab-a+(-9b+49b)+3\\\\=-32a^2b+7a^2+3b^2-35ab-a+40b+3[/tex]

Is 12 even or odd? Pick you choice

Answers

Answer:

Even

Step-by-step explanation:

What fraction of a metre is 20cm?

Answers

Answer:

1/5

Step-by-step explanation:

A metre is 100cm, thus

20cm/100cm= 1/5

Find the slope:
(-7, 4), (13, 4)
O 20
O Zero
O Undefined

Answers

Answer:

Zero

Step-by-step explanation:

it is to correct answer because I did this before and one of my classes also subscribe to my channel bye

The answer is zero



4-4=0
13-(-7)=20
And since there is no number above the 20 it is zero

Is this true or false? Ill give brainliest

Answers

i think true because 0,4 on there is correct and so is 2,0

Question 121 pts
Daniel had $30 to spend at the fair. If the admission to the fair is $8 and the rides cost $1.25 each, what is the greatest number of rides Daniel can go on?

Answers

Answer:

 17 rides

Step-by-step explanation:

30-8=22

22 divided by 1.25=17.6 and then you cant go on without 1.25 so 17

the answer would be (12)

Answers

Ok thanks for the help

thank you.............................

36x-2 + 34x+2 = 180 solve

Answers

Answer:

First, collect the like terms

36x+34x=180+2-2

Solve,

74x=180

x=180/74

2.43243243243

When you round it, it will be approximately,

x≅2.43

Step-by-step explanation:

I hope it helped please give me brainliest

Answer:

[tex]x = \frac{18}{7} [/tex]

What is the expected value of the random variable with the given probability distribution? If necessary, round your answer to the nearest hundreth.

A) 0.62
B) 1.62
C) 3.70
D) 4.33

Answers

ANSWER: D)4.33




EX: 4.33

(sinA + cosA)/ (secA + cosecA) = sinA* cosA​

Answers

Answer:

Proof below

Step-by-step explanation:

Trigonometric Identities

We'll prove that:

[tex]\displaystyle \frac{\sin A+\cos A}{\sec A+\csc A}=\sin A*\cos A[/tex]

Recall:

[tex]\displaystyle \sec A =\frac{1}{\cos A}[/tex]

[tex]\displaystyle \csc A =\frac{1}{\sin A}[/tex]

Applying those definitions:

[tex]\displaystyle \frac{\sin A+\cos A}{\sec A+\csc A}=\frac{\sin A+\cos A}{\frac{1}{\cos A}+\frac{1}{\sin A}}[/tex]

Adding the fractions:

[tex]\displaystyle \frac{\sin A+\cos A}{\sec A+\csc A}=\frac{\sin A+\cos A}{\frac{\sin A+\cos A}{\cos A*\sin A}}[/tex]

Dividing the fractions:

[tex]\displaystyle \frac{\sin A+\cos A}{\sec A+\csc A}=(\sin A+\cos A)*\frac{\cos A*\sin A}{\sin A+\cos A}[/tex]

Simplifying:

[tex]\displaystyle \frac{\sin A+\cos A}{\sec A+\csc A}=\cos A*\sin A[/tex]

Hence proved

2x + 7 > 11
Please and thank you

Answers

Answer:

x = > 2

Step-by-step explanation:

This is the answer because:

1) >2 means x is any number greater than 2

2) For example, 2 x 3 = 6 +  7 = 13

3) 13 is greater than 11

Hope this helps!

Complete the proof for the following Algebraic Equation:

3x + 6 = 2(x-1)

Select the answer for x below and show the proof on your page for uploading.

O x - 4

Ox= 1

O x=8

O x--7​

Answers

x= -8

Step-by-step explanation:

3x + 6 = 2(x-1)

3x + 6 = 2x - 2

3x - 2x = -2 -6

x = -8

1/4(z 3z) 7=−z 1 please help with this ive been stuck

Answers

Answer:

z=0

Step-by-step explanation:

if the equation was 1/4(3z)7=-1z

Central City High's basketball team will be entering the playoffs at the end of their regular season. There will be 3 other teams in the playoffs, with season average scores of 87, 92, and 119. Central City High has played 7 games with an average score of 91. What score range could they have in their eighth and last regular season game to have the second highest season average score in the tournament?

Answers

Answer:

99<x<315

Step-by-step explanation:

Answer:

C.

Step-by-step explanation:

edg. 2021

number of boys and girls are in the class are in the ratio of 7 : 5 the number of boys is 8 more than the number of girls what is a total class strength?​

Answers

Answer:

Step-by-step explanation:

Given ratio of boys and girls in the class =7:5

No of boys is 8more than the girls

So

Let no of boys in the class =7x

No of girls in the class=5x

7x=5x+8

2x=8

X=8/2

X=4.

Total strength =no of boys + no of girls

=7x+5x

=7×4+5×4

= 28+20

=48.

Total strength in the class is 48.

Answer:

Total class strength = 48

Step-by-step explanation:

Boys : Girls = 7 : 5

Number of boys  = 7x

Number of girls = 5x

7x - 5x = 8

      2x = 8      

       x = 8/2

       x = 4

Total strength = 7x + 5x = 12x = 12*4  = 48

Mariana drinks 2 pints of milk each day. How many days does it take her to drink 1 gallon of milk?

Answers

Answer:

4 days

Step-by-step explanation:

because Mariana drank 2 pints a day 8 pints are in a gallon so 8 ÷ 2 = 4

help please anyone?
giving brainliestt

Answers

Answer:

School Y = 4 points

School X = 12 points

Step-by-step explanation:

school x=school y+8

school x=3 school y

x=y+8

x=3y

3y=y+8

2y=8

y=4

x=12

Two trapezoids below are similar what is the length of RS?

Answers

9514 1404 393

Answer:

  11.5 m

Step-by-step explanation:

The fact that the figures are similar means the side lengths are proportional:

  RS/QT = BC/AD

  RS/(7 m) = (2.3 m)/(1.4 m)

  RS = (7 m)(2.3/1.4) . . . . . . multiply by 7 m

  RS = 11.5 m

 

True or false, f(x) is a function

Answers

Answer:

Step-by-step explanation:

True!!

The answer is true...

HEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEELLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP


What is the coefficient of the fourth term in this expression?
m3+2kn2+mn2+6k2n

Answers

The coefficients would be 6 and 2.
Coefficient of k would be 6 and for n it would be 2.

A zookeeper is preparing to care for snakes in an exhibit. For every 2 snakes, she needs 1 bowl of water. How many bowls of water are needed if the number of snakes is x? *

Answers

Answer:

k

Step-by-step explanation:

work out area of this semi circle with diameter 10

Answers

Area of a circle is pi x r^2

R is the radius which is have the diameter: r = 10/2 = 5

Area of the full circle would be 3.14 x 5^2 = 3.14 x 25 = 78.5 square units.

A semi circle is half a full circle

Area of the semi circle = 78.5/2 = 39.25 square units.

Need help on this Math problem

Answers

Answer:

I hope I helped :)

Step-by-step explanation:

a. The y-intercept represents b. (y = mx + b) also b is 20 because that's where the line touches the y-axis.

b. The slope represents Sam's monthly fee.

c. Sam's monthly fee is 0.4 or 2/5

d. Every 50 minutes is $20.

Reggie plans to have a garden with 36 plants. He wants the ratio of tomato plants to cucumber plants to be 4:5. How many cucumber plants will be in Reggie's garden?

Answers

Answer:

20

Step-by-step explanation:

Total no of plants in a garden = 36

The ratio of tomato plants to cucumber plants to be 4:5.

Let tomato plants are 4x and cucumber plants is 5x.

ATQ,

4x+5x=36

9x = 36

x = 4

For cucumber plant, 5x = 5(4) = 20

So, there are 20 cucumber plants will be in Reggie's garden

cal d gradient B(4,-7), c(-6-5) and d two point find d gradient​

Answers

Answer:

d = - 1/5

Step-by-step explanation:

slope form: m= y2-y1/x2-x1

m= -5-(-7)/-6-4

m= 2/-10

m= - 1/5

1. A relation contains the ordered pairs shown. One of the ordered pairs is missing an x-coordinate. {(-1,4),(0,4),(2,5),(3,-6),(?,7)} What could be the missing x-coordinate if the relation is not a function?

Answers

Answer:

There are 4 possible scenarios where given relation could not be a function:

i)  [tex](-1, 4), (0,4), (2,5), (3,-6), (-1, 7)[/tex]

ii) [tex](-1, 4), (0,4), (2,5), (3,-6), (0, 7)[/tex]

iii) [tex](-1, 4), (0,4), (2,5), (3,-6), (2, 7)[/tex]

iv) [tex](-1, 4), (0,4), (2,5), (3,-6), (3, 7)[/tex]

Step-by-step explanation:

From Function Theory, we remember that a relation is not a function when at least one element from domain (x-coordinate) is related to one or more elements from range (y-coordinate). Hence, there are four possibilities of making the relation not a function:

i)  [tex](-1, 4), (0,4), (2,5), (3,-6), (-1, 7)[/tex]

ii) [tex](-1, 4), (0,4), (2,5), (3,-6), (0, 7)[/tex]

iii) [tex](-1, 4), (0,4), (2,5), (3,-6), (2, 7)[/tex]

iv) [tex](-1, 4), (0,4), (2,5), (3,-6), (3, 7)[/tex]

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