2. In Parallelogram TRIK, what is the mzt?
R
T
5x°
2(x + 30°
K
I
I
Answers
Answer:
[tex]T = 100[/tex]
Step-by-step explanation:
See attachment for parallelogram TRIK
Given
[tex]T = 5x[/tex]
[tex]I = 2(x + 30)[/tex]
Required
Determine T
Because T and I are opposite angles of the parallelogram, then they are congruent.
i.e.
[tex]T = I[/tex]
Substitute values for T and I
[tex]5x = 2(x + 30)[/tex]
Open bracket
[tex]5x = 2x + 60[/tex]
Collect Like Terms
[tex]5x - 2x = 60[/tex]
[tex]3x = 60[/tex]
Solve for x
[tex]x = \frac{60}{3}[/tex]
[tex]x =20[/tex]
Recall that:
[tex]T = 5x[/tex]
[tex]T = 5 * 20[/tex]
[tex]T = 100[/tex]
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Step-by-step explanation:
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Step-by-step explanation:
Answer:
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Answer:
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А.0
В.1
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Answers
Answer:
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Step-by-step explanation:
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Step-by-step explanation:
Answer:
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Step-by-step explanation:
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Answer:
A
Step-by-step explanation:
when you look at the y axis 2.5 is a point
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Answer:
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Step-by-step explanation:
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Answer:
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Answer:
15
Step-by-step explanation:
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Answer: what graoh?
Step-by-step explanation:
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Answers
Answer:
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Answer:
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Step-by-step explanation:
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Step-by-step explanation:
The value of f(0) from the graph of f(x) is (a) 12 only
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Answer:
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Step-by-step explanation:
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Item 3
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Answers
Answer:
C) The cost increases $2.50 for every additional pair of shoes rented.
Step-by-step explanation:
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Step-by-step explanation:
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Answers
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Answers
Answer:
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Step-by-step explanation:
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Answers
Answer:
- 36
Step-by-step explanation:
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Answer:
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Step-by-step explanation:
Distribute:7x+24x-21
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Answers
Answer:
108
Step-by-step explanation:
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Please find the derivative of [tex]\displaystyle \frac{e^{\frac{3}{x}}}{x^2}[/tex]. Show all work necessary - thanks!
Answers
Hello! :)
[tex]\large\boxed{\frac{-e^{\frac{3}{x}} (3 + 2x )}{x^{4}}}[/tex]
Find the derivative using the quotient rule:
[tex]\frac{f(x)}{g(x)} = \frac{g(x) * f'(x) - f(x) * g'(x)}{(g(x))^{2}}[/tex]
In this instance:
[tex]f(x) = e^{\frac{3}{x} }\\\\g(x) = x^{2}[/tex]
Use the following properties to find the derivative of f(x) and g(x):
[tex]e^{u} = u' * e^{u}\\\\x^{n} = nx^{n-1}[/tex]
Use the quotient rule:
[tex]\frac{x^{2} * (e^{\frac{3}{x}} * (-3x^{-2})) - e^{\frac{3}{x}} * 2x }{(x^{2} )^{2}}[/tex]
Simplify the numerator:
[tex]\frac{(e^{\frac{3}{x}} * (-3)) - e^{\frac{3}{x}} * 2x }{(x^{2} )^{2}}[/tex]
Factor out [tex]e^{\frac{3}{x}}[/tex]
[tex]\frac{e^{\frac{3}{x}} (-3 - 2x )}{x^{4}}[/tex]
Factor out -1 from the numerator:
[tex]\frac{-e^{\frac{3}{x}} (3 + 2x )}{x^{4}}[/tex]
And we're done! Thanks for posting the question to my 1000th answer!
Answer:
[tex]\displaystyle \frac{d}{dx}[\frac{e^{\frac{3}{x}}}{x^2}] = \frac{-3e^{\frac{3}{x}}}{x^4} - \frac{2e^{\frac{3}{x}}}{x^3}[/tex]
General Formulas and Concepts:
Pre-Algebra
Splitting FractionsAlgebra I
Terms/CoefficientsFactoringExponential Rule [Multiplying]: [tex]\displaystyle b^m \cdot b^n = b^{m + n}[/tex]Calculus
Derivatives
Derivative Notation
Basic Power Rule:
f(x) = cxⁿ f’(x) = c·nxⁿ⁻¹Derivative Rule: [tex]\displaystyle \frac{d}{dx} [e^u]=e^u \cdot u'[/tex]
Quotient Rule: [tex]\displaystyle \frac{d}{dx} [\frac{f(x)}{g(x)} ]=\frac{g(x)f'(x)-g'(x)f(x)}{g^2(x)}[/tex]
Step-by-step explanation:
Step 1: Define
[tex]\displaystyle \frac{e^{\frac{3}{x}}}{x^2}\\f(x) = e^{\frac{3}{x}}\\g(x) = x^2[/tex]
Step 2: Differentiate
Quotient Rule: [tex]\displaystyle \frac{d}{dx}[\frac{e^{\frac{3}{x}}}{x^2}] = \frac{\frac{d}{dx}[e^{\frac{3}{x}}] \cdot x^2 - \frac{d}{dx}[x^2] \cdot e^{\frac{3}{x}}}{(x^2)^2}[/tex]Derivative Rule: [tex]\displaystyle \frac{d}{dx}[\frac{e^{\frac{3}{x}}}{x^2}] = \frac{e^{\frac{3}{x}} \cdot \frac{-3}{x^2} \cdot x^2 - \frac{d}{dx}[x^2] \cdot e^{\frac{3}{x}}}{(x^2)^2}[/tex][Simplify] Multiply: [tex]\displaystyle \frac{d}{dx}[\frac{e^{\frac{3}{x}}}{x^2}] = \frac{-3e^{\frac{3}{x}} - \frac{d}{dx}[x^2] \cdot e^{\frac{3}{x}}}{(x^2)^2}[/tex]Basic Power Rule: [tex]\displaystyle \frac{d}{dx}[\frac{e^{\frac{3}{x}}}{x^2}] = \frac{-3e^{\frac{3}{x}} - 2x^{2-1} \cdot e^{\frac{3}{x}}}{(x^2)^2}[/tex][Simplify] Subtract Exponents: [tex]\displaystyle \frac{d}{dx}[\frac{e^{\frac{3}{x}}}{x^2}] = \frac{-3e^{\frac{3}{x}} - 2x \cdot e^{\frac{3}{x}}}{(x^2)^2}[/tex][Simplify] Multiply: [tex]\displaystyle \frac{d}{dx}[\frac{e^{\frac{3}{x}}}{x^2}] = \frac{-3e^{\frac{3}{x}} - 2xe^{\frac{3}{x}}}{(x^2)^2}[/tex][Simplify] Exponent Rule: [tex]\displaystyle \frac{d}{dx}[\frac{e^{\frac{3}{x}}}{x^2}] = \frac{-3e^{\frac{3}{x}} - 2xe^{\frac{3}{x}}}{x^{2 + 2}}[/tex][Simplify] Add Exponents: [tex]\displaystyle \frac{d}{dx}[\frac{e^{\frac{3}{x}}}{x^2}] = \frac{-3e^{\frac{3}{x}} - 2xe^{\frac{3}{x}}}{x^4}[/tex][Simplify] Fraction Split: [tex]\displaystyle \frac{d}{dx}[\frac{e^{\frac{3}{x}}}{x^2}] = \frac{-3e^{\frac{3}{x}}}{x^4} - \frac{2xe^{\frac{3}{x}}}{x^4}[/tex][Simplify - 2nd Fraction] Cancel Like Terms: [tex]\displaystyle \frac{d}{dx}[\frac{e^{\frac{3}{x}}}{x^2}] = \frac{-3e^{\frac{3}{x}}}{x^4} - \frac{2e^{\frac{3}{x}}}{x^3}[/tex]And we have our final answer!
A manufacturer produces 1 ton of baseballs per day and packs them in cartons of 24 baseballs each. If all of the balls are the minimum allowable weight, how many cartons of balls does the company produce each day?
Answers
Given :
Mass of baseball produced per day, m = 1 ton.
1 carton of baseball contain 24 baseballs.
To Find :
If all of the balls are the minimum allowable weight, how many cartons of balls does the company produce each day.
Solution :
Minimum allowable weight of a baseball is 5 ounces.
We know, 1 ton = 2000 pounds and 1 pounds = 16 ounces.
So, 1 ton = 32000 ounces .
Number of baseballs produced :
n = 32000/5
n = 6400
Number of carton produce each day, N = 6400/24 = 266.67
Since, carters cannot be in decimal.
Therefore, carton produce in each day is 266 .
EASY QUESTION!!!
Write the slope-intercept form of the equation of the line through the point (3, -4) with the slope of -6. *
y = -6x - 4
y = -6x + 3
y = -6x +14
y = -3x + 4
Answers
m (which is the slope is -6)
b (which is the y-intercept is -4)