12x^2-22x-5=-5x use the quadratic formula to solve express your answer in simplest form

Answer: A: (x+3)

Step-by-step explanation:

Lets simplify this first:

[tex]2x^2 + 2x - 12[/tex]

[tex]2(x^2 + x - 6)[/tex]

we can factor this into:

[tex]2(x+3)(x-2)[/tex]

so, from the options, we can see that option A is correct.

If the common difference is 2, then the sum of the first 8 terms is 88 and If the common difference is 3, then the sum of the first 8 terms is 116.

To find the sum of the first 8 terms of the sequence, we need to identify a pattern in the sequence so that we can find the 8th term and then use the formula for the sum of the first n terms of an arithmetic sequence.

Looking at the given sequence, we can see that each term is increasing by a certain amount. To find that amount, we can subtract consecutive terms:

6 - 4 = 2

9 - 6 = 3

So, the sequence has a common difference of 2 or 3. Since we have only three terms, it is not clear which of the two is the correct common difference. Therefore, we will assume both and calculate the sum for each.

If the common difference is 2, then the 8th term is:

[tex]a_{8}[/tex] = [tex]a_{1}[/tex] + 7d = 4 + 7(2) = 18

If the common difference is 3, then the 8th term is:

[tex]a_{8}[/tex] = [tex]a_{1}[/tex] + 7d = 4 + 7(3) = 25

Now, we can use the formula for the sum of the first n terms of an arithmetic sequence:

[tex]S_{n}[/tex] = n/2([tex]a_{1}[/tex] + [tex]a_{n}[/tex])

If the common difference is 2, then:

[tex]S_{8}[/tex] = 8/2(4 + 18) = 88

If the common difference is 3, then:

[tex]S_{8}[/tex] = 8/2(4 + 25) = 116

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Answer:

5xy + 6y

Step-by-step explanation:

4x(2y) + 3y(2-x)

= 8xy + 6y - 3xy

= 5xy + 6y

So, the answer is 5xy + 6y

The simplified expression is:5xy + 6y

Expanding the expression gives:

4x(2y) + 3y(2 - x) = 8xy + 6y - 3xy

Combining like terms, we get:

8xy - 3xy + 6y = 5xy + 6y

Therefore, the simplified expression is:

5xy + 6y

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The CES (Constant Elasticity of Substitution) production function is a mathematical model used to represent the relationship between inputs and output in production. To determine the concavity or convexity of the CES production function, we need to look at its second derivative.

The general CES production function is given by:

Q = A * [(α * L^ρ) + (β * K^ρ)]^(1/ρ)

Where:
Q = Output
A = Total factor productivity
L = Labor input
K = Capital input
α and β = Input share parameters
ρ = Elasticity of substitution parameter

To determine concavity or convexity, we examine the second derivatives with respect to L and K:

∂²Q/∂L² and ∂²Q/∂K²

If both second derivatives are negative, the production function is concave. If both are positive, it's convex. If the signs are different, the function exhibits neither concavity nor convexity.

In the case of the CES production function, the sign of the second derivatives will be determined by the value of the elasticity of substitution parameter (ρ). If ρ is positive, the production function exhibits convexity, whereas if ρ is negative, the production function exhibits concavity. If ρ equals zero, it is neither convex nor concave.

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Answer:

Step-by-step explanation:

The value of the prefix expression plus negative upwards arrow 3 space 2 upwards arrow 2 space 3 divided by space 6 minus 4 space 2 is equal to 82. To evaluate the given prefix expression, we start from right to left.

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The vector component of u orthogonal to v is (821/113)i - (56/113)j.

(a) The projection of u onto v can be found using the formula: proj_v u = (u . v / ||v||^2) * v, where "." denotes the dot product and "||v||" denotes the magnitude of v.

First, we find the dot product of u and v:

u . v = (3i + 4j) . (8i + 7j)

= 3(8) + 4(7)

= 44

Next, we find the magnitude of v:

||v|| = sqrt((8)^2 + (7)^2)

= sqrt(113)

Finally, we can use the formula to find the projection of u onto v:

proj_v u = (44 / 113) * (8i + 7j)

= (352/113)i + (308/113)j

Therefore, the projection of u onto v is (352/113)i + (308/113)j.

(b) The vector component of u orthogonal to v can be found by subtracting the projection of u onto v from u:

u - proj_v u = (3i + 4j) - ((352/113)i + (308/113)j)

= (821/113)i - (56/113)j

Therefore, the vector component of u orthogonal to v is (821/113)i - (56/113)j.

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The requried teenager's age is 15 years old.

Let's assume the ages of Deena's three children are a, b, and c (in no particular order). We know that one of them is a teenager, so without loss of generality, let's assume that a is the teenager. Then we have:

a * b * c = 1155

We can use trial and error to find values of a, b, and c that satisfy the equation above and the conditions we've established. One possible set of values is:

a = 15

b = 7

c = 11

You can check that these values satisfy the equation:

15 * 7 * 11 = 1155

and that a is a teenager. Therefore, the teenager's age is 15 years old.

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The width of the box is approximately 8.5 inches.

We have,

The equation to find the width of the box, w, is:

V = l × w × h

where V is the volume of the box, l is the length, w is the width, and h is the height.

Substituting the given values, we get:

357 = 10.5 × w × 4

Simplifying, we get:

357 = 42w

Dividing both sides by 42, we get:

w = 357/42

w ≈ 8.5

Therefore,

The width of the box is approximately 8.5 inches.

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The solutions are

i)  x = 2

ii) Therefore, there is no integer x that satisfies the congruence.

iii) x = 2

What is the equivalent expression?

Equivalent expressions are expressions that perform the same function despite their appearance. If two algebraic expressions are equivalent, they have the same value when we use the same variable value.

i. To solve 7 × 3 = 3 (mod 11), we need to find an integer x such that 7 × 3 is congruent to 3 modulo 11.

First, we can simplify 7 × 3 by calculating 73 = 343 and then taking the remainder when 343 is divided by 11. We get:

7 × 3 = 343 = 31 × 11 + 2

So, we have:

7 × 3 = 2 (mod 11)

To solve for x, we can try multiplying both sides by the modular inverse of 7 modulo 11.

The modular inverse of 7 modulo 11 is 8, because 7 x 8 is congruent to 1 modulo 11. So, we have:

8 × 7 × 3 = 8 × 2 (mod 11)

Simplifying:

56 × 3 = 16 (mod 11)

5 × 3 = 16 (mod 11)

We can check the values of x = 2 and x = 7 to see which one satisfies the congruence:

5 × 23 = 30 = 2 (mod 11)

5 × 73 = 365 = 9 (mod 11)

So the solution is x = 2.

ii. To solve 3.14 = 5 (mod 11), we need to find an integer x such that 3.14 is congruent to 5 modulo 11.

Since 3.14 is not an integer, we cannot directly apply modular arithmetic to it.

Instead, we can use the fact that 3.14 is equal to 3 + 0.14, and try to solve the congruence for each part separately.

First, we can find an integer k such that 3 + 11k is congruent to 5 modulo 11. This means:

3 + 11k = 5 + 11m for some integer m

Simplifying:

11k - 11m = 2

Dividing by 11:

k - m = 2/11

Since k and m are integers, the only possible value of k - m is 0. Therefore, we have:

k - m = 0

k = m

Substituting k = m, we get:

3 + 11k = 5 + 11k

This is not possible, since 3 is not congruent to 5 modulo 11. Therefore, there is no integer x that satisfies the congruence.

iii. To solve x8 = 10 (mod 11), we need to find an integer x such that x8 is congruent to 10 modulo 11.

We can try raising each integer from 0 to 10 to the power of 8, and check which one is congruent to 10 modulo 11:

0⁸ = 0 (mod 11)

1⁸ = 1 (mod 11)

2⁸ = 256 = 10 (mod 11)

3⁸ = 6561 = 10 (mod 11)

4⁸ = 65536 = 1 (mod 11)

5⁸ = 390625 = 10 (mod 11)

6⁸ = 1679616 = 1 (mod 11)

7⁸ = 5764801 = 5 (mod 11)

8⁸ = 16777216 = 1 (mod 11)

9⁸ = 43046721 = 10 (mod 11)

10⁸ = 10000000000 = 1 (mod 11)

Therefore, the solutions are x = 2,

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The slope of RS approaches infinity, indicating a vertical line.

(a) (i) To find the equation of the tangent to curve C at point P(4,4), we need to find the derivative of the curve at that point.

Given the equation of curve C, we differentiate it with respect to x:

dy/dx = 2x - 5

Now we substitute x = 4 into the derivative to find the slope of the tangent at P:

dy/dx at x=4 = 2(4) - 5 = 3

The slope of the tangent at P is 3. Using the point-slope form of a line, the equation of the tangent is:

y - 4 = 3(x - 4)

y - 4 = 3x - 12

y = 3x - 8

Therefore, the equation of the tangent to C at P is y = 3x - 8.

(ii) The normal to curve C at point P is perpendicular to the tangent, so its slope is the negative reciprocal of the tangent's slope.

The slope of the normal at P is -1/3. Using the point-slope form of a line, the equation of the normal is:

y - 4 = (-1/3)(x - 4)

y - 4 = (-1/3)x + 4/3

y = (-1/3)x + 16/3

Therefore, the equation of the normal to C at P is y = (-1/3)x + 16/3.

(b) To find the coordinates of point Q, we need to find the intersection point of the normal to C at Q and the normal to C at P.

Since we are given that RQ is perpendicular to RP, the slopes of RQ and RP are negative reciprocals of each other.

The slope of RP is 3 (from part (a)(i)). Therefore, the slope of RQ is -1/3.

The equation of the normal at Q is:

y - yQ = (-1/3)(x - xQ)

We know that the coordinates of Q satisfy the equation of the normal at P:

y = (-1/3)x + 16/3Substituting yQ = (-1/3)xQ + 16/3 into the equation of the normal at Q, we have:

(-1/3)xQ + 16/3 = (-1/3)(x - xQ)

Simplifying, we get:

(-1/3)xQ + 16/3 = (-1/3)x + (1/3)xQ

(4/3)xQ = (1/3)x + 16/3

Comparing coefficients, we have:

4xQ = x + 16

4xQ - x = 16

3xQ = 16

xQ = 16/3

Plugging this value of xQ back into the equation of the normal at P, we get:

yQ = (-1/3)(16/3) + 16/3

yQ = -16/9 + 16/3

yQ = 16/9

Therefore, the coordinates of point Q are (16/3, 16/9).

To find the x-coordinate of point R, we need to solve the equations of the tangents at points P and Q simultaneously.

The equation of the tangent at P is y = 3x - 8 (from part (a)(i)).

The equation of the tangent at Q can be found by differentiating the equation of curve C with respect to x and substituting xQ = 16/3:

dy/dx = 2x - 5

dy/dx at x=16/3 = 2(16/3) - 5 = 27/3 = 9

Using the point-slope form, the equation of the tangent at Q is y - (16/9) = 9(x - (16/3)):

y - (16/9) = 9x - 16

y = 9x - 16/9

Now, we solve the equations of the tangents to find the intersection point S:

3x - 8 = 9x - 16/9

Multiply through by 9 to eliminate fractions:

27x - 72 = 81x - 16

Rearrange and simplify:

81x - 27x = 72 - 16

54x = 56

x = 56/54

x = 28/27

Therefore, the x-coordinate of point R is 28/27.

(d) To show that the line RS is parallel to the y-axis, we need to show that the slopes of RS and the y-axis are equal.

The slope of RS can be found by using the coordinates of R (xR) and S and applying the slope formula:

slope of RS = (yS - yR) / (xS - xR)

We already have the x-coordinate of R, which is xR = 28/27.

From part (a)(ii), the equation of the normal at P is y = (-1/3)x + 16/3, which is the equation of the tangent at Q.

Plugging in x = 28/27 into the equation of the tangent at Q, we can find the y-coordinate of point S:

yS = (-1/3)(28/27) + 16/3

yS = -28/81 + 16/3

yS = -28/81 + 48/81

yS = 20/81

Now we can calculate the slope of RS:

slope of RS = (yS - yR) / (xS - xR)

slope of RS = (20/81 - 16/3) / (xS - 28/27)

To show that RS is parallel to the y-axis, we need to show that the slope of RS is equal to infinity or undefined.

If we examine the denominator (xS - 28/27), we can see that as xS approaches 28/27, the denominator becomes zero.

Therefore, the slope of RS approaches infinity, indicating a vertical line.

Hence, we can conclude that the line RS is parallel to the y-axis.

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Answer:

BC = 24

Step-by-step explanation:

the angle between the tangent and the radius at the point of contact A is 90°

then Δ ABC is a right triangle

using the sine ratio in the right triangle

sin30° = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{AC}{BC}[/tex] = [tex]\frac{12}{BC}[/tex] ( multiply both sides by BC

BC × sin30° = 12 ( divide both sides by sin30° )

BC = [tex]\frac{12}{sin30}[/tex] = 24

With regard to the clindrical designs, note that is advisable for Kevin to opt for the first design which requires about 108.35 square inches of plastic. The second design requires about 431.97 square so Kevin does not have enough plastic to make the second design.

Here we used the surface area formula for cylinders.

Surface Area = 2πr² + 2πrh
R is the base and h is the height.

For First Design we have

Diameter (d) = 2r = 3

so r = 1.5

So Surface Area = 2π(1.5)² + 2π(1.5) (10)

SA First Cylinder = 108.35

Repeating the same step for the second cylinder we have:

SA 2ndCylinder = 431.97

Thus, the conclusion we have above is the correct one because:

108.35in² <  205in² > 431.97in²

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Natalia's minimum hourly wage to support her family of 4 is $16.98.

The minimum hourly wage can be determined using some of the basic mathematical operations, including multiplication, addition, and division.

The estimated yearly income to support the first person = $18,946

The additional income required to support each additional person in the family = $4,437

The number of family members in Natalia's = 4

Natalia's work week hours = 38

The number of weeks per year = 50

Total work week hours per year = 1,900 hours (38 x 50)

First person's income = $18,946

Additional income for 3 = $13,211 ($4,437 x 3)

Total income = $32,257

Hourly wage = $16.98 ($32,257 ÷ 1,900)

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The rule for the table is y = -8x + 88.

The price of the shoes after 8 month is 24 dollars.

The table shows the discount prices for a pair of shoes over several months.

Therefore, the rule for the tables can be represented as follows:

y = mx + b

where

Therefore, using (1,80)(2, 72)

m = 72 - 80 / 2 - 1

m = -8

Hence,

y = -8x + b

using (1, 80)

80 = -8 + b

b = 88

Therefore,

y = -8x + 88

Therefore, let's find the price after 8 months

y = -8(8) + 88

y = -64 + 88

y = 24

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When working with an ANOVA, the parameter we use is A) σ2.

When working with an ANOVA, the parameter we use is σ2. This parameter represents the population variance, which is important in comparing the means of different groups and determining if there is a significant difference between them.

The population variance, σ2, measures the spread or variability of the data within each group or treatment. It provides information about how much the individual observations deviate from the group mean.

By comparing the variances between groups and within groups, ANOVA allows us to assess if the observed differences in means are statistically significant or simply due to random variation.

The ANOVA test calculates a statistic called the F-statistic, which is the ratio of the between-group variability to the within-group variability. This F-statistic follows an F-distribution, and its significance determines whether the observed differences in means are likely due to the treatments or just random chance.

Therefore, the correct option is a) σ2.

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The mass percent of the vinegar solution is approximately 3.85%.

To calculate the mass percent of a vinegar solution containing 3.74 g of acetic acid in a total mass of 97.20 g, follow these steps:

1. Identify the mass of acetic acid (3.74 g) and the total mass of the solution (97.20 g).
2. Divide the mass of acetic acid by the total mass of the solution:

    3.74 g ÷ 97.20 g.
3. Multiply the result by 100 to get the mass percent:

    (3.74 g ÷ 97.20 g) × 100.

Thus, the mass percent of the vinegar solution is approximately 3.85%.

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Answer:

The beam will clear the wires

Step-by-step explanation:

First find length of the beam, b:

sin40 = 8/b

b = sin40(8) = 12.446 ft

Now find height of tip of beam, h,  from ground when beam is at 60°:

sin60 = h/12.446

h = sin60(12.446) = 10.78 ft

The height of the wires = 10.78 + 2 = 12.78 ft

(Height of wires) - (length of beam standing up straight) = 12.78 - 12.446 ≈ 0.33 ft

The beam will clear the wires by about 4 "

An equation to represent the number of bricks that will be needed for 2 walls is m = 2x

Here, a house has x bricks and 10 pounds of glue to build a wall.

this means that to build one wall, it requires 'x' number of bricks.

Let us assume that for 2 wall it will need 'm' number of bricks.

Using Unitary method the number of bricks needed for 2 walls would be,

⇒ m = 2 × x

⇒ m = 2x

This means that to build two walls, it will take 2x number of bricks, where x is the number of bricks needed to build a single wall.

Therefore,  an equation that represents the number of bricks that will be needed for 2 walls: 2x

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A) The probability of a randomly selected catch being a mouse caught by Cyd 40%.

b) If Cyd didn't catch the bird, then no other cat did.

c) The probability of a randomly selected is 0.333

d) The probability that a catch being a mouse caught by Greg is 0

e) The probability of a randomly selected catch is a mouse caught by Rom is 0. 2 is verified by the catch made by Ken is a mouse.

F) The probability that a catch which is a mouse was made by Cyd is 40%.

a) The probability of a randomly selected catch being a mouse caught by Cyd can be calculated as follows:

Probability of Mouse caught by Cyd = 0.20

Probability of any catch being a Mouse = 0.50 (given in the problem statement)

Therefore, Probability (Mouse caught by Cyd) = 0.20 / 0.50 = 0.40 or 40%

b) To calculate the probability of a bird not caught by Cyd, we need to subtract the probability of a bird caught by Cyd from 1 (since the event of a bird not caught by Cyd is complementary to the event of a bird caught by Cyd).

Probability of Bird caught by Cyd = 1 - Probability of any catch being a Mouse = 1 - 0.50 = 0.50

Probability of any catch not being a Mouse = 1 - Probability of any catch being a Mouse = 1 - 0.50 = 0.50

Therefore, Probability (Bird caught by Cyd) = 0.50 / 0.50 = 1.

And, Probability (Bird not caught by Cyd) = 1 - 1 = 0.

c) Greg's catches are equally likely to be a mouse, a bird, or a vole. We can calculate the probability of a catch being a mouse caught by Greg as follows:

Given, Probability of Mouse caught by Greg = Probability of Vole caught by Greg = Probability of Bird caught by Greg = 0.45 / 3 = 0.15

Therefore, Total Probability of any catch caught by Greg = 0.15 + 0.15 + 0.15 = 0.45

Hence, Probability (Mouse caught by Greg) = 0.15 / 0.45 = 1/3 or 0.333 (approx.)

d) We are given that the probability of a randomly selected catch being a mouse caught by Ken is 0.5. We need to find the probability that a catch being a mouse is caught by Greg.

So, the probability of any catch being caught by Ken = 50 / 100 = 0.5.

We know that the total probability of any catch caught by Greg is 0.45 (as calculated in part c).

Therefore, Probability (Mouse caught by Greg) = x, Probability (Vole caught by Greg) = x, and Probability (Bird caught by Greg) = 0.45 - 2x (since the probabilities must add up to 0.45).

Probability (Mouse) = Probability (Mouse caught by Ken) + Probability (Mouse caught by Greg)

0.5 = 0.5 + x

x = 0

This means that there is no probability of a mouse being caught by Greg, since all of the mice are already accounted for by Ken.

e) We are given that the probability of a randomly selected catch being a mouse caught by Rom is 0.2. We need to verify if the catch made by Ken is a mouse.

So, the probability of any catch being caught by Rom = 20 / 100 = 0.2.

We know that the probability of a catch being a mouse caught by Ken is 0.5.

Probability of Mouse caught by Rom | Mouse caught by Ken = 1 (since all mice are assumed to be distinct)

Probability (Mouse caught by Ken) = 0.5

Probability (Mouse caught by Rom) = 0.2

Therefore, Probability (Mouse caught by Ken | Mouse caught by Rom) = 1 * 0.5 / 0.2 =0.25 or 25% (approx.)

This means that if we know that Rom caught a mouse, the probability of Ken catching a mouse is actually higher than the overall probability of any catch being a mouse.

f) Finally, we need to find the probability that a catch which is a mouse was made by Cyd. We can use Bayes' Theorem again to calculate this:

Probability (Mouse | Mouse caught by Cyd) = 1 (since all mice are assumed to be distinct)

Probability (Mouse caught by Cyd) = 0.2 (since Cyd catches 20% of all creatures)

Probability (Mouse) = 0.5 (since half of all creatures caught are mice)

Therefore, Probability (Mouse caught by Cyd | Mouse) = 1 * 0.2 / 0.5 = 0.4 or 40%.

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The consumer surplus if the demand function for a particular beverage is given by D(q) is $896.42.

The demand function given is:[tex]D(q) = (9q + 5)^2[/tex]

To find the equilibrium quantity, we set the demand equal to the supply:

[tex]D(q) = S(q)[/tex]

[tex](9q + 5)^2= q + 12[/tex]

Expanding the square, we get:

[tex]81q^2+ 90q + 25 = q + 12[/tex]

[tex]81q^2+ 89q + 13 = 0[/tex]

Using the quadratic formula, we get:

[tex]q = (-89[/tex]± [tex]\sqrt{892 - 48113})/(2[/tex]×[tex]81)[/tex]

[tex]q = 0.058[/tex] or [tex]-1.056[/tex]

Since we are interested in the positive solution, the equilibrium quantity is [tex]q = 0.058.[/tex]

To find the equilibrium price, we substitute q = 0.058 into the demand function:

[tex]D(0.058) = (9[/tex]×[tex]0.058 + 5)^2[/tex]

[tex]D(0.058) = 5.823[/tex]

So the equilibrium price is 5.823.

To find the consumer's surplus, we need to find the area under the demand curve and above the equilibrium price up to the equilibrium quantity. This represents the total amount that consumers are willing to pay for the product.

The integral of the demand function is:

∫[tex](9q + 5)^2dq = (1/27)[/tex]×[tex](9q+5)^3+ C[/tex]

Evaluating this at q = 0.058 and q = 0, and subtracting, we get:

[tex](1/27)[/tex]×[tex](5.881)^3- C = 901.704 - C[/tex]

We don't need to know the value of the constant C, since it will cancel out when we subtract the area under the demand curve up to the equilibrium price. To find this area, we integrate the demand function from 0 to the equilibrium quantity:

∫([tex](9q + 5)^2[/tex] dq from 0 to [tex]0.058 = 0.881[/tex]

So the consumer's surplus is:

[tex]901.704 - 0.881[/tex]×[tex]5.823 = $896.42[/tex] (rounded to the nearest cent)

Therefore, the consumer's surplus is $896.42.

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75% of the time, a student who is just guessing will get 28 or below out of 107.

We have,

The probability of getting a question correct by guessing is 1/4.

Let X be the number of questions guessed correctly.

Since X follows a binomial distribution with n=10 and p=1/4, the expected value of X is given by E(X) = np = 10 * 1/4 = 2.5.

The variance of X is given by Var(X)

= np(1 - p)

= 10 x 1/4 x 3/4

= 1.875, and the standard deviation is the square root of the variance, which is √(1.875) ≈ 1.37.

To get the minimum passing score of 60%, you need to get at least 6 questions correct.

The probability of getting exactly 6 questions correct.

P(X=6) = (10 choose 6) x (1/4)^6 x (3/4)^4 ≈ 0.016.

To get any passing score, you need to get 6 or more questions correct. The probability of getting 6, 7, 8, 9, or 10 questions correct.

= P(X≥6) = P(X=6) + P(X=7) + P(X=8) + P(X=9) + P(X=10).

Using a binomial calculator, we find P(X ≥ 6) ≈ 0.078.

To find the score that a student who is just guessing will get 75% of the time or below out of 107, we can use the normal approximation to the binomial distribution.

The mean of the distribution is np = 26.75, and the standard deviation is sqrt(np(1-p)) = 3.27.

We can standardize the score by subtracting the mean and dividing by the standard deviation:

(75th percentile score - mean) / standard deviation

= (0.75 - 0.5) / 0.5 = 0.5.

Solving for the 75th percentile score, we get,

= (0.5 x 3.27) + 26.75

= 28.16.

Therefore,

75% of the time, a student who is just guessing will get 28 or below out of 107.

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As per the given triangle, the value of sin A in decimal form, rounded to three decimal places, is approximately 0.946.

We can use the definition of sine to find sin A:

sin A = opposite/hypotenuse

In this case, the opposite side is the height of the triangle, which is 35, and the hypotenuse is 37. Therefore:

sin A = 35/37

This fraction cannot be simplified any further, so the value of sin A in fraction form is 35/37.

To find the equivalent decimal, we can divide the numerator by the denominator:

sin A = 35/37 ≈ 0.946

Therefore, the value of sin A in decimal form, rounded to three decimal places, is approximately 0.946.

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Answer:

18

Step-by-step explanation:

make p the subject of the formula

P=126/7

p= 18

Answer:

89

Step-by-step explanation:

it is a straight line mean 180 degrees.

180 subtract 91 is 89

Answer:The measure of angle b is 89 degrees.

Step-by-step explanation:

Types of angles:

• Angles between 0 and 90 degrees (0°< θ <90°) are called acute angles.

• Angles between 90 and 180 degrees (90°< θ <180°) are known as obtuse angles.

• Angles that are 90 degrees (θ = 90°) are right angles.

• Angles that are 180 degrees (θ = 180°) are known as straight angles.

• Angles between 180 and 360 degrees (180°< θ < 360°) are called reflex angles.

• Angles that are 360 degrees (θ = 360°) are full turn.

We know that,

 Angles that are 180 degrees (θ = 180°) are known as straight angles.

In this question ,let

a= 91 and we have to find b=?

here,by straight angle

a+b=180

91+b=180

b=180-91

b=89

this is the required answer.

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To solve this problem :
A = P(1 + r/n)^(nt)
Where:
A = the final amount
P = the principal amount (the initial investment)
r = the annual interest rate (as a decimal)
n = the number of times the interest is compounded per year
t = the number of years
In this case, we have:
P = $46,950.00
r = 6.78% = 0.0678
n = 2 (since the interest is compounded semi-annually)
t = 12 (since we are investing for 12 years and withdrawing at the end of every three months)

To find the amount that can be withdrawn, we need to solve for A when t = 12/4 = 3 (since we are withdrawing every three months):
A = P(1 + r/n)^(nt)
A = $46,950.00(1 + 0.0678/2)^(2*3)
A = $46,950.00(1.0339)^6
A = $46,950.00(1.2307)
A = $57,789.27
So the sum of money that can be withdrawn from the fund is $57,789.27.

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We can use the empirical rule to approximate the interval. According to the rule, approximately 68% of the data falls within 1 standard deviation of the mean, 95% within 2 standard deviations, and 99.7% within 3 standard deviations.

So, for a normal distribution with a mean of 2.5 and a standard deviation of 0.6, we can say that approximately 68% of the GPAs fall between 1.9 (2.5-0.6) and 3.1 (2.5+0.6), 95% fall between 1.3 (2.5-2(0.6)) and 3.7 (2.5+2(0.6)), and 99.7% fall between 0.7 (2.5-3(0.6)) and 4.3 (2.5+3(0.6)).

To find the interval that would contain approximately 81.5% of the GPAs, we need to find the range that covers the middle 81.5% of the data. We know that this range is going to be less than the 95% interval, but greater than the 68% interval. Therefore, we can say that the interval containing approximately 81.5% of the GPAs is between 1.3 and 3.1.

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