If the fraction whose denominator are equal then they will add up
In the given fraction 1/2 +1/9, the denominator of both the fraction 1/2 & 1/9 is not same
so, to make the base same we take the LCM of the 2 & 9
[tex]\begin{gathered} \text{LCM of 2 \& 9 is 18} \\ Si,\text{ the fraction will be :} \\ \frac{1}{2}+\frac{1}{9}=\frac{9+2}{18} \\ \frac{1}{2}+\frac{1}{9}=\frac{11}{18} \end{gathered}[/tex]Answer : 11/18
Question 11 5 pts Find the value of x. Round to the nearest tenth. х 329 12. Not drawn to scale a. 10.2 b. 14.3 C. 10.4 d. 14.2
Explanation
Step 1
Let
angle= 32
hypotenuse=x
adjacent side=12
so, we need a function that relates angel, hypotenuse and adjacent side
[tex]\text{cos}\emptyset=\frac{adjacent\text{ side}}{\text{hypotenuse}}[/tex]replace,
[tex]\begin{gathered} \text{cos}\emptyset=\frac{adjacent\text{ side}}{\text{hypotenuse}} \\ \text{cos32}=\frac{12}{\text{x}} \\ \text{Multiply both sides by x} \\ x\cdot\text{cos32}=\frac{12}{\text{x}}\cdot x \\ x\cdot\text{cos32}=12 \\ \text{divide both sides by cos 32} \\ \frac{x\cdot\text{cos32}}{\cos \text{ 32}}=\frac{12}{cos\text{ 32}} \\ x=14.15 \\ rounded \\ x=14.2 \end{gathered}[/tex]so, the answer is
[tex]d)x=14.2[/tex]I hope this helps you
45 + 54 = 99 times ( ) + ( )
a) You have to find the greatest common factor for the values 45 and 54
To do so you have to determine the factors for each value and determine the highest value both numbers are divisible for.
Factors of 45 are
1, 3, 5, 9, 15, 45
Factors of 54 are
1, 2, 3, 6, 9, 18, 27, 54
The greatest common factor is 9, this means that you can divide both numbers by 9 and the result will be an integer:
[tex]\frac{45}{9}=5[/tex][tex]\frac{54}{9}=6[/tex]b) Given the addition
[tex]45+54[/tex]You have to factorize the adition using the common factor.
That is to "take out" the 9 of the addition, i.e. divide 45 and 54 by 9 and you get the result (5+6) but for this result to be equvalent to the original calculation, you have to multiply it by 9
[tex]45+54=9(5+6)[/tex]help meeeeeeeeee pleaseee !!!!!
The values of the functions are;
a. (f + g)(x) = x( 2 + 3x)
b. (f - g)(x) = 2x - 3x²
c. (f. g) (x) = 6x²
d. (f/g)(x) = 2/ 3x
What is a function?A function can be defined as an expression, rule, law or theorem that explains the relationship between two variables in a given expression
These variables are called;
The independent variablesThe dependent variablesFrom the information given, we have;
f(x) = 2xg(x) = 3x²To determine the composite functions, we have;
a. (f + g)(x)
Add the functions
(f + g)(x) = 2x + 3x²
Factorize the functions
(f + g)(x) = x( 2 + 3x)
b. (f - g) (x)
Subtract the functions
(f - g)(x) = 2x - 3x²
c. (f. g) (x)
Substitute the values of x as g(x) in f(x)
(f. g) (x) = 2(3x²)
(f. g) (x) = 6x²
d. (f/g)(x) = 2x/ 3x²
(f/g)(x) = 2/ 3x
Hence, the functions are determined by substituting the values of the dependent variables.
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The revenue function R in terms of the number of units sold, a, is given as R = 300x - 0.4x^2where R is the total revenue in dollars. Find the number of units sold a that produces a maximum revenue?Your answer is x =What is the maximum revenue?
1) Considering the Revenue function in the standard form:
[tex]R(x)=-0.4x^2+300x[/tex]2) Since this is a quadratic function, we can write out the Vertex of this function:
[tex]\begin{gathered} x=h=-\frac{b}{2a}=\frac{-300}{2(-0.4)}=375 \\ k=f(375)=-0.4(375)^2+300(375)\Rightarrow k=56250 \end{gathered}[/tex]3) So, we can answer this way:
[tex]x=375\:units\:yield\:\$56,250[/tex]NO LINKS!! Describe the domain and range (in BOTH interval and inequality notation) for each function shown part 1a
Answer:
Domain as an inequality: [tex]\boldsymbol{\text{x} < 6 \ \text{ or } \ -\infty < \text{x} < 6}[/tex]
Domain in interval notation: [tex]\boldsymbol{(-\infty, 6)}[/tex]
Range as an inequality: [tex]\boldsymbol{\text{y} \le 6 \ \text{ or } \ -\infty < \text{y} \le 6}[/tex]
Range in interval notation: [tex]\boldsymbol{(-\infty, 6]}[/tex]
=========================================================
Explanation:
The domain is the set of allowed x inputs. For this graph, the right-most point is when x = 6. This endpoint is not part of the domain due to the open hole. The graph goes forever to the left to indicate [tex]\text{x} < 6[/tex] but I think [tex]-\infty < \text{x} < 6[/tex] is far more descriptive.
The second format directly leads to the interval notation of [tex](-\infty, 6)[/tex]
Always use parenthesis for either infinity. We use a parenthesis for the 6 to tell the reader not to include it as part of the domain.
------------------------
The range is the set of possible y outputs.
The highest y can get is y = 6
Therefore, y = 6 or y < 6
The range can be described as [tex]\text{y} \le 6 \ \text{ or } \ -\infty < \text{y} \le 6[/tex] where the second format is better suited to lead directly to the interval notation [tex](-\infty, 6][/tex]
Use a square bracket to include the 6 as part of the range. We don't have any open holes at the peak mountain point.
Answer:
[tex]\textsf{Domain}: \quad (-\infty, 6) \quad -\infty < x < 6[/tex]
[tex]\textsf{Range}: \quad (-\infty,6] \quad -\infty < y\leq 6[/tex]
Step-by-step explanation:
The domain of a function is the set of all possible input values (x-values).
The range of a function is the set of all possible output values (y-values).
An open circle indicates the value is not included in the interval.
A closed circle indicates the value is included in the interval.
An arrow show that the function continues indefinitely in that direction.
Interval notation
( or ) : Use parentheses to indicate that the endpoint is excluded.[ or ] : Use square brackets to indicate that the endpoint is included.Inequality notation
< means "less than".> means "more than".≤ means "less than or equal to".≥ means "more than or equal to".From inspection of the given graph, the function is not continuous and so the domain is restricted.
There is an open circle at x = 6.
Therefore, the domain of the function is:
Interval notation: (-∞, 6)Inequality notation: -∞ < x < 6From inspection of the given graph, the maximum value of y is 6.
The function continues indefinitely to negative infinity.
Therefore, the range of the function is:
Interval notation: (-∞, 6]Inequality notation: -∞ < y ≤ 6Sam goes to a fast food restaurant and orders some tacos and burritos. He sees on the nutrition menu that tacos are 250 calories and burritos are 330 calories. If he ordered 4 items and consumed a total of 1080 calories, how many tacos, and how many burritos did Sam order and eat?
Let x represent the number of tacos that Sam ordered and ate.
Let y represent the number of burritos that Sam ordered and ate.
From the information given, If he ordered 4 items, it means that
x + y = 4
If tacos are 250 calories, it means that the number of calories in x tacos is 250 * x = 250x
If burritos are 330 calories, it means that the number of calories in y burritos is 330 * y = 330y
If he consumed a total of 1080 calories, it means that
250x + 330y = 1080
From the first equation, x = 4 - y
By substituting x = 4 - y into the second equation, we have
250(4 - y) + 330y = 1080
1000 - 250y + 330y = 1080
- 250y + 330y = 1080 - 1000
80y = 80
y = 80/80
y = 1
x = 4 - y = 4 - 1
x = 3
Thus, Sam ordered and ate 3 tacos and 1 burritos
Write an equation that represents a reflection in the y-axis of the graph of g(x)=|x|.
h(x)= ?
the reflection of the function g(x)=|x| in the y-axis will be h(x) = |x|
What is reflection in coordinate geometry ?
this represents the flip or mirror image of transformation about the given axis.
For every point in the plane (x, y), a 90° rotation can be described by the transformation P(x, y) → P'(-y, x). We can achieve this same transformation by performing two reflections.
Here, the given function is :
g(x)=|x|
Now, the reflection in the y-axis will be same that is :
h(x)= g(x)
h(x) = |x|
Therefore, the reflection of the function g(x)=|x| in the y-axis will be h(x) = |x|
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I need help with this
Find the zero for the polynomial function and give the multiplicity for each zero. State whether the graph crosses to x axis or touch the x axis and turn around, at each zero.
we have the function
f(x)=2(x-6)(x-7)^2
REmember that the zeros of the function are the values of x when the value of the function is equal to zero
In this problem
the zeros of the function are
x=6 -------> multiplicity 1 (the graph crosses to x axis)
x=7 ----- multiplicity 2 (touch the x axis and turn around)
see the attached figure to better understand the problem
For which values of A, B, and C will Ax + By = C be a horizontal line through the point (−4, 2)?
The set of values {A = 0, B = 1, and C = 2} to have a completely horizontal line.
What is a horizontal line?A horizontal line is defined as a line with slope m = 0 that is parallel to the x-axis.
A horizontal line across (-4,2) informs us of two things.
A horizontal line with slope m = 0 is parallel to the x-axis.
The line crosses the point (-4,2).
Ax + By = C has m = B/A = 0 slope and intersects point (-4,2).
Then, B = A×0 indicates that any constant A will work, and the Ax term disappears.
Ax + By = C then becomes y = C. To find C, use the point (-4,2).
⇒ C = 2
This line's equation is y = 2, and any point (x,2) matches the equation.
Therefore, the set of values {A = 0, B = 1, and C = 2} to have a completely horizontal line.
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Answer:
Step-by-step explanation:
17
if Maria collected R rocks and Javy collected twice as many rocks as Maria and Pablo collected 5 less than Javy. What is the sum of rocks collected by Pablo and Maria?
This problem deals with the numbers expressed in a more general way: letters or variables
That belongs to Algebra
We know Maria collected R rocks. Let's put this in a separate line:
M = R
Where M is meant to be the number of rocks collected by Maria
Now we also know Javy collected twice as many rocks as Maria did. Thus, if J is that variable, we know that
J = 2R
Pablo collected 5 less rocks than Javy. This is expressed as
P = J - 5
or equivalently:
P = 2R - 5
since J = 2R, as we already stated
We are now required to calculate the sum of rocks collected by Pablo and Maria.
This is done by adding P + M:
P + M = (2R - 5) + (R)
We have used parentheses to indicate we are replacing variables for their equivalent expressions
Now, simplify the expression:
P + M = 2R - 5 + R
We collect the same letters by adding their coefficients:
P + M = 3R - 5
Answer: Pablo and Maria collected 3R - 5 rocks together
Triangle LMN is drawn with vertices at L(−2, 1), M(2, 1), N(−2, 3). Determine the image vertices of L′M′N′ if the preimage is rotated 90° clockwise. L′(1, 2), M′(1, −2), N′(3, 2) L′(−1, 2), M′(−1, −2), N′(−3, 2) L′(−1, −2), M′(−1, 2), N′(−3, −2) L′(2, −1), M′(−2, −1), N′(2, −3)
ANSWER
L'(1, 2), M'(1, -2), N'(3, 2)
EXPLANATION
The rule for rotating a point (x, y) 90° clockwise is,
[tex](x,y)\rightarrow(y,-x)[/tex]So, the vertices of triangle LMN will be mapped to,
[tex]\begin{gathered} L(-2,1)\rightarrow L^{\prime}(1,2) \\ M(2,1)\rightarrow M^{\prime}(1,-2) \\ N(-2,3)\rightarrow N^{\prime}(3,2) \end{gathered}[/tex]Hence, the image has vertices L'(1, 2), M'(1, -2), N'(3, 2).
TWENTY POINTS//WILL MARK BRAINLIEST
Marty graphs the hyperbola (y+2)236−(x+5)264=1 .
How does he proceed?
Drag a value, phrase, equation, or coordinates in the boxes to correctly complete the statements.
Put responses in the correct input to answer the question. Select a response, navigate to the desired input and insert the response. Responses can be selected and inserted using the space bar, enter key, left mouse button or touchpad. Responses can also be moved by dragging with a mouse.
Marty first identifies the center of the hyperbola as Response area, and that the hyperbola opens Response area. Since a = Response area, the coordinates of the vertices are Response area.
The slopes of the asymptotes of this parabola are ± Response area, and the asymptotes pass through the center of the hyperbola. The equations of the asymptotes are Response area.
Once this information is gathered, the asymptotes are graphed as dashed lines, and the hyperbola is drawn through the vertices, approaching the asymptotes.
The procedure to construct the graph of the hyperbola is described as follows:
Marty first identifies the center of the hyperbola as (-5,2), and that the hyperbola opens up and down. Since a = 6, the coordinates of the vertices are (-5, -4) and (-5, 8).The slopes of the asymptotes of this parabola are a = ± 3/4, and the asymptotes pass through the center of the hyperbola. The equations of the asymptotes are y - 2 = ± 3/4(x + 5).Hyperbola equation and graphThe equation of a vertical hyperbola with center (x*, y*) is given according to the equation presented as follows:
(y - y*)²/a² - (x - x*)²/b² = 1.
This means that the hyperbola opens up vertically, up and down.
The equation of the hyperbola in this problem is given as follows:
(y + 2)²/36 - (x + 5)²/64 = 1.
Thus the coordinates of the center are given as follows:
(-5, 2).
The numeric value of coefficient a is calculated as follows:
a² = 36 -> a = 6.
Meaning that the coordinates of the vertices of the hyperbola are given as follows:
(-5, 2 - 6) = (-5,-4).(-5, 2 + 6) = (-5,8).The slopes of the asymptotes of the parabola are given according to the rule presented as follows:
±a/b.
The coefficient b is calculated as follows:
b² = 64 -> b = 8.
Hence:
a/b = 6/8 = 3/4.-a/b = -6/8 = -3/4.Since the asymptotes pass through the center, the equation is:
y - 2 = ± 3/4(x + 5).
The graph is given by the image at the end of the answer.
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Write the slope-intercept form of the equation of the line graphed on the coordinate plane.
The slope-intercept form is:
[tex]y\text{ = mx + b}[/tex]We have to find these coefficients. To do that we have to choose two points in the graph and apply the following formula. I will use (0,1) and (-1,-1). The formula is:
[tex]y-yo\text{ = m(x-xo)}[/tex]The formula of the coefficient 'm' is:
[tex]m\text{ = }\frac{y2-y1}{x2-x1}[/tex]Let's substitute the points into the formula above to find the value of m. Then we use one of the points to find the slope-intercept form of the equation:
[tex]m\text{ = }\frac{-1-1}{-1-0}=2[/tex]Applying it to the second equation using the point (0,1):
[tex]y-1=2(x-0)[/tex][tex]y=2x+1[/tex]Answer: The slope-intercept form of the equation will be 2x+1.
How long will it take money to double if it is invested at the following rates?(A) 7.8% compounded weekly(B) 13% compounded weekly(A) years(Round to two decimal places as needed.)
Answer:
Explanation:
A) We'll use the below compound interest formula to solve the given problem;
[tex]A=P(1+r)^t[/tex]where P = principal (starting) amount
A = future amount = 2P
t = number of years
r = interest rate in decimal = 7.8% = 7.8/100 = 0.078
Since the interest is compounded weekly, then r = 0.078/52 = 0.0015
Let's go ahead and substitute the above values into the formula and solve for t;
[tex]\begin{gathered} 2P=P(1+0.0015)^t \\ \frac{2P}{P}=(1.0015)^t \\ 2=(1.0015)^t \end{gathered}[/tex]Let's now take the natural log of both sides;
[tex]\begin{gathered} \ln 2=\ln (1.0015)^t \\ \ln 2=t\cdot\ln (1.0015) \\ t=\frac{\ln 2}{\ln (1.0015)} \\ t=462.44\text{ w}eeks \\ t\approx\frac{462.55}{52}=8.89\text{ years} \end{gathered}[/tex]We can see that it will take 8.89 years for
B) when r = 13% = 13/100 = 0.13
Since the interest is compounded weekly, then r = 0.13/52 = 0.0025
Let's go ahead and substitute the values into the formula and solve for t;
[tex]\begin{gathered} 2P=P(1+0.0025)^t \\ \frac{2P}{P}=(1.0025)^t \\ 2=(1.0025)^t \end{gathered}[/tex]Let's now take the natural log of both sides;
[tex]\begin{gathered} \ln 2=\ln (1.0025)^t \\ \ln 2=t\cdot\ln (1.0025) \\ t=\frac{\ln 2}{\ln (1.0025)} \\ t=277.60\text{ w}eeks \\ t\approx\frac{2.77.60}{52}=5.34\text{ years} \end{gathered}[/tex]
Find the measurement of each side indicated and round to the nearest tenth for both triangles
a) We have a right triangle.
We have to find the value of x, which is the hypotenuse.
We can relate the angle B, the side AC and x with a trigonometric ratio as:
[tex]\begin{gathered} \sin (B)=\frac{\text{Opposite}}{\text{Hypotenuse}}=\frac{AC}{AB} \\ \sin (57\degree)=\frac{10.8}{x} \\ x=\frac{10.8}{\sin (57\degree)} \\ x\approx\frac{10.8}{0.83867} \\ x\approx12.9 \end{gathered}[/tex]b) In this case, x is the adyacent side to angle A.
We can relate the sides and the angle as:
[tex]\begin{gathered} \cos (A)=\frac{\text{Adyacent}}{\text{Hypotenuse}}=\frac{AC}{AB} \\ \cos (47\degree)=\frac{x}{3} \\ x=3\cdot\cos (47\degree) \\ x\approx3\cdot0.682 \\ x\approx2.0 \end{gathered}[/tex]Answer:
a) x = 12.9
b) x = 2.0
two slices of dans famous pizza have 230 calories how many calories would you expect to be in 5 slices of pizza
We can answer this question, using proportions. We can see it graphically as follows:
Then, we have that 5 slices will have 575 calories.
A car is traveling at a speed of 70 kilometers per hour. What is the car's speed in miles per hour? How many miles will the car travel in 5 hours? In your computations, assume that 1 mile is equal to 1.6 kilometers. Do not round your answers.
What is the car's speed in miles per hour?
Let's make a conversion:
[tex]\frac{70\operatorname{km}}{h}\times\frac{1mi}{1.6\operatorname{km}}=\frac{43.75mi}{h}[/tex]How many miles will the car travel in 5 hours?
1h---------------------->43.75mi
5h---------------------> x mi
[tex]\begin{gathered} \frac{1}{5}=\frac{43.75}{x} \\ x=5\times43.75 \\ x=218.75mi \end{gathered}[/tex]For the quadratic function, identify any horizontal or vertical translations. Enter "0" and "none" if there is none.f(x) = (x + 5)² - 4Horizontal:__ units to the (Select an answer (right, left, none)Vertical:__ units to the (Select an answer ( up, down, none)
Given:
[tex]f(x)=(x+5)^2-4[/tex]The parent function of the given function (x²)
We will find the horizontal or vertical translations to get the given function.
the general form of the translation will be as follows:
[tex]f(x\pm a)\pm b[/tex]Where (a) is the horizontal translation and (b) is the vertical translation
Comparing the given equation to the formula:
[tex]a=5,b=-4[/tex]So, the answer will be:
Horizontal: 5 units to the left
Vertical: 4 units down
3. Darren won Round 3 of the game. Sherri is wondering if she lost Round 3 by 5 points or by 25 points. Explain to Sherri how many points Darren won Round3 by and show the mathematics you used to justify your answer.4. Sherri and Darren actually played with a third player, their friend Eric. Unfortunately, Eric forgot to record the points he scored in each of the three roundsin the table.
Sherry lost the round 3 by 25 points
Explanation:Sherry's point in third round = -10
Darren's point in the third round = 15
To determine the number of points Sherry lost round 3 by, we will subtracct Sherry's point from Darren's point:
[tex]\begin{gathered} \text{Darren's point - Sherry's point} \\ =\text{ 15 - (-10)} \\ =\text{ 15 + 10} \\ =\text{ 25} \end{gathered}[/tex]Sherry lost round 3 by 25 points
A line passes through the points (7,9) and (10,1). What is its equation in point-slope form?
Use one of the specified points in your equation. Write your answer using integers, proper fractions, and improper fractions. Simplify all fractions.
Answer:
[tex](y - 9) = (-8/3)\, (x - 7)[/tex].
Step-by-step explanation:
If a line in a cartesian plane has slope [tex]m[/tex], and the point [tex](x_{0},\, y_{0})[/tex] is on this line, then the point-slope equation of this line will be [tex](y - y_{0}) = m\, (x - x_{0})[/tex].
The slope of a line measures the rate of change in [tex]y[/tex]-coordinates relative to the change in the [tex]x[/tex]-coordinates. If a line goes through two points [tex](x_{0},\, y_{0})[/tex] and [tex](x_{1},\, y_{1})[/tex], the slope of that line will be:
[tex]\begin{aligned}m &= \frac{y_{1} - y_{0}}{x_{1} - x_{0}}\end{aligned}[/tex].
In this question, the two points on this line are [tex](7,\, 9)[/tex] and [tex](10,\, 1)[/tex], such that [tex]x_{0} = 7[/tex], [tex]y_{0} = 9[/tex], [tex]x_{1} = 10[/tex], and [tex]y_{1} = 1[/tex]. Substitute these values into the equation to find the slope of this line:
[tex]\begin{aligned}m &= \frac{y_{1} - y_{0}}{x_{1} - x_{0}} \\ &= \frac{1 - 9}{10 - 7} \\ &= \left(-\frac{8}{3}\right)\end{aligned}[/tex].
With the point [tex](7,\, 9)[/tex] as the specific point [tex](x_{0},\, y_{0})[/tex] (such that [tex]x_{0} = 7[/tex] and [tex]y_{0} = 1[/tex]) as well as a slope of [tex]m = (-8 / 3)[/tex], the point-slope equation of this line will be:
[tex]y - y_{0} = m\, (x - x_{0})[/tex].
[tex]\displaystyle y - 9 = \left(-\frac{8}{3}\right)\, (x - 7)[/tex].
cos2 0-cos 20 = sin2 0
According to Double identities
[tex]\cos (2x)=2cos^2(x)-1[/tex][tex]\begin{gathered} \cos ^2(x)-sen^2(x)=2\cos ^2(x)-1 \\ -sen^2(x)=2\cos ^2(x)-\cos ^2(x)-1 \\ -sen^2(x)=\cos ^2(x)-1 \\ 1=\cos ^2(x)+sen^2(x) \end{gathered}[/tex]help meeeeeeeeee pleaseee !!!!!
The addition of the given functions f(x) and g(x) is equal to the expression x^2+ 3x + 5
Composite function.Function composition is an operation that takes two functions, f and g, and creates a function, h, that is equal to g and f, such that h(x) = g.
Given the following functions
f(x) = x^2 + 5
g(x) = 3x
We are to determine the sum of both functions as shown;
(f+g)(x) = f(x) + g(x)
Substitute the given functions into the formula
(f+g)(x) = x^2+5 + 3x
Write the expression in standard form;
(f+g)(x) = x^2+ 3x + 5
Hence the sum of the functions f(x) and g(x) is equivalent to x^2+ 3x + 5
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Finding the area of unusual shapes
The shape in question is a composite shape.
It comprises two(2) shapes which are a triangle and a semi-circle.
The area of the shape is the sum of the area of the triangle and that of the semi-circle
The area of the triangle is:
[tex]A_{triangle}=\frac{1}{2}\times base\times height[/tex][tex]\begin{gathered} \text{Base of the triangle =}6\text{ yard} \\ Height\text{ of the triangle= 4 yard} \end{gathered}[/tex]Thus,
[tex]\begin{gathered} A_{triangle}=\frac{1}{2}\times6\times4 \\ A_{triangle}=12\text{ yards} \end{gathered}[/tex]Area of the Semi-circle is:
[tex]A_{semi-circle}=\frac{\pi\times r^2}{2}[/tex][tex]\begin{gathered} \text{Diameter of the circle=6 yard} \\ \text{Radius}=\frac{Diameter}{2} \\ \text{Radius}=\frac{6}{2}=3\text{ yard} \end{gathered}[/tex][tex]\begin{gathered} A_{semi-circle}=\frac{3.14\times3^2}{2} \\ A_{semi-circle}=\frac{28.26}{2} \\ A_{semi-circle}=14.13\text{ yard} \end{gathered}[/tex]Hence, the area of the composite shape is:
[tex]\begin{gathered} \text{Area of the triangle + Area of the semi-circle} \\ 12+14.13=26.13\text{ yard} \end{gathered}[/tex]What is the equation of the following graph?A. f(x) = 2(3*)OB. f(x) = (4)Oc. f(x) = 3(2)D. f(x) = 5(2") y
Given
The graph,
To find:
The equation representing the given graph.
Explanation:
It is given that,
That implies,
From the given graph,
It is clear that the curve passes through, (0,5).
Then, for x=0,
Consider the equation,
[tex]\begin{gathered} f(0)=5(2^0) \\ =5\times1 \\ =5 \end{gathered}[/tex]Which is equal to y=5.
Hence, the equation representing the above graph is,
[tex]f(x)=5(2^x)[/tex]Find the minimum or maximum value of the function f(x)=8x2+x−5. Give your answer as a fraction.
Answer
Minimum value of the function = (-41/8)
Explanation
The minimum or maximum of a function occurs at the turning point of the graph of the function.
At this turning point, the first derivative of the function is 0.
The second derivative of the function is positive when the function is at minimum and it is negative when the function is at maximum.
f(x) = 8x² + 2x - 5
(df/dx) = 16x + 2
At minimum or maximum point,
16x + 2 = 0
16x = -2
Divide both sides by 16
(16x/16) = (-2/16)
x = (-1/8)
Second derivative
f(x) = 8x² + 2x - 5
(df/dx) = 16x + 2
(df²/d²x) = 16 > 0, that is, positive.
So, this point is a minimum point.
f(x) = 8x² + 2x - 5
f(-1/8) = 8(-1/8)² + 2(-1/8) - 5
= 8 (1/64) - (1/4) - 5
= (1/8) - (1/4) - 5
= (1/8) - (2/8) - (40/8)
= (1 - 2 - 40)/8
= (-41/8)
Hope this Helps!!!
Write the equation for a parabola with a focus at (1,2) and a directrix at y=6
Solution:
Given:
[tex]\begin{gathered} focus=(1,2) \\ directrix,y=6 \end{gathered}[/tex]Step 1:
The equation of a parabola is given below as
[tex]\begin{gathered} y=\frac{1}{4(f-k)}(x-h)^2+k \\ (h,f)=focus \\ h=1,f=2 \end{gathered}[/tex]Step 2:
The distance from the focus to the vertex is equal to the distance from the vertex to the directrix:
[tex]\begin{gathered} f-k=k-6 \\ 2-k=k-6 \\ 2k=2+6 \\ 2k=8 \\ \frac{2k}{2}=\frac{8}{2} \\ k=4 \end{gathered}[/tex]Step 3:
Substitute the values in the general equation of a parabola, we will have
[tex]\begin{gathered} y=\frac{1}{4(f-k)}(x-h)^{2}+k \\ y=\frac{1}{4(2-4)}(x-1)^2+4 \\ y=-\frac{1}{8}(x-1)^2+4 \\ \end{gathered}[/tex]By expanding, we will have
[tex]\begin{gathered} y=-\frac{1}{8}(x-1)^{2}+4 \\ y=-\frac{1}{8}(x-1)(x-1)+4 \\ y=-\frac{1}{8}(x^2-x-x+1)+4 \\ y=-\frac{1}{8}(x^2-2x+1)+4 \\ y=-\frac{x^2}{8}+\frac{x}{4}-\frac{1}{8}+4 \\ y=-\frac{x^2}{8}+\frac{x}{4}-\frac{1+32}{8} \\ y=-\frac{x^2}{8}+\frac{x}{4}+\frac{31}{8} \end{gathered}[/tex]Hence,
The final answer is
[tex]\begin{gathered} \Rightarrow y=-\frac{x^{2}}{8}+\frac{x}{4}+\frac{31}{8}(standard\text{ }form) \\ \Rightarrow y=-\frac{1}{8}(x-1)^2+4(vertex\text{ }form) \end{gathered}[/tex]The table shows a function. Is the function linear or nonlinear?x y0 1918 1200
By plotting the points, we get a non-linear function
The Leaning Tower of Pisa
was completed in 1372 and
makes an 86* angle with
the ground. The tower is
about 57 meters tall, measured
vertically from the ground
to its highest point. If you
were to climb to the top and
then accidently drop your
keys, where would you
start looking for them?
How far from the base of.
the tower would they land?
The distance where the keys would drop from the base is 3.5m
Calculation far from the base of tower?Height of the tower = 57m
Angle it makes to the ground = 86°
To solve this question, you have to understand that the tower isn't vertically upright and the height of the tower is different from the distance from the top of the tower to the ground.
The tower makes an angle 86° to the ground and that makes it not vertically straight because a vertically straight building is at 90° to the ground.
The distance from where the keys drop to the base of the tower can be calculated using
We have to use cosθ = adjacent / hypothenus
θ = 86°
Adjacent = ? = x
Hypothenus = 57m
Cos θ = x / hyp
Cos 86 = x / 57
X = 57 × cos 86
X = 57× 0.06976
X = 3.97 = 4m
The keys would fall from the tower's base at a distance of about 4 meters.
To learn more about far from the base refer to:
https://brainly.com/question/9624014
#SPJ13
Which is equal to 2 over 5? A. 2%B. 2.5%C. 20%D. 25%E. 40%
Calculating the value of 2 over 5 in percentage, we have:
[tex]\begin{gathered} \frac{2}{5}=\frac{20}{50}=\frac{40}{100}=40\text{\%} \\ or \\ \frac{2}{5}=0.4=40\text{\%} \end{gathered}[/tex]So the correct option is E.