maybe try quizzlet that would really help i swear
The output from the machine depends on the input to to
A.
B.
C.
D.
Answer:
i think its B
Step-by-step explanation:
Benjamin owns a small Internet business. Besides himself, he employs nine other people. The salaries earned by the employees are given next in thousands of dollars (Benjamin's salary is the largest, of course): 30, 30, 45, 50, 50, 50, 55, 55, 60, 75.
Required:
a. Determine the mean, median, and mode for salary.
b. Business has been good! As a result. Benjamin has a total of $25.000 in bonus pay to distribute to his employees. One option for distributing bonuses is to give each employee (including himself) $2500. Add the bonuses under this plan to the original salaries to create a new data set. Recalculate the mean, median, and mode. How do they compare to the originals?
c. As a second option. Benjamin can give each employee a bonus of 5% of his or her original salary. Add the bonuses under this second plan to the original salaries to create a new data set. Recalculate the mean, median, and mode. How do they compare to the originals?
d. As a third option, Benjamin decides not to give his employees a bonus at all. Instead, he keeps the $25,000 for himself. Use this plan to create a new data set. Recalculate the mean, median, and mode. How do they compare to the originals?
Answer:
a) mean μ = 50 median M = 50 mode Md = 50
b) mean μ₂ = 52,5 median M = 52,5 mode Md = 52,5 all vales increased in 2,5 ( thousands of $) the same quantity of individuals incements
c) mean μ₃ = 52,50 median M = 52,5 mode Md = 52,5 The same values obtain in b)
d) mean μ₃ = 52,50 median M = 50 and Mode 50
Step-by-step explanation:
a) Mean μ is the average then:
30 30 45 50 50 50 55 55 60 75
μ = 50
The median M, is the central (fifth value) 50
And the mode
Md = 50
b) Adding 2,5 ( in thousands of $) to each one of the employees
32,5 32,5 47,5 52,5 52,5 52,5 57,5 57,5 62,5 77,5
The mean μ₂ = 52,5 $, since the average value has to be increased by the common increased number
The median M = 52,5 and also the mode Md = 52,5
c) 31,5 31,5 47,25 52,5 52,5 52,5 57,75 57,75 63 78,75
The mean μ₃ = 52,50
The median M = 52,50
The Mode Md = 52,50
d) 30 30 45 50 50 50 55 55 60 100
μ₄ = 52,5
Median M = 50
Mode Md = 50
Would 3.99. million flies or 47,000,000 ants have a greater mass
Ants
Step-by-step explanation:
Brad is 3 years older than Francis. The product of their ages is 154. Determine their ages.
Brad is 3 years older than Francis. The product of their ages is 154. Determine their ages.
Given:product of their ages=154Brad is 3 years older than FrancisLet:Age of Francis be xAge of Bard be x+3Answer:A/Q:Age of Bard× Age of Francis=154
x×(x+3)=154x²+3x=154Let's split 3x into +14x and -11x
x²+3x-154=0x²+14x-11x-154=0x(x+14)-11(x+14)=0(x-11)(x+14)=0x=11x=-14So we aren't taking ages in negetive
.°.x=11As we know in starting we have take x as Financis age
.°. Francis age=11✔We know Brad is 3 years older than Francis
.°. Brad age=x+3Brad age=14✔_____________________With regards!
✧Dull Star✧
A manufacturer has designed a process to produce pipes that are 10 feet long. The distribution of the pipe length, however, is actually Uniform on the interval 10 feet to 10.57 feet. Assume that the lengths of individual pipes produced by the process are independent. Let X and Y represent the lengths of two different pipes produced by the process. h)What is the probability that the second pipe (with length Y) is more than 0.11 feet longer than the first pipe (with length X)
The probability that the second pipe (with length Y) is more than 0.11 feet longer than the first pipe (with length X) is approximately 2.6092%.
Here,
Since the length of the pipes follows a uniform distribution on the interval [10 feet, 10.57 feet], the probability density function (PDF) for each pipe is:
f(x) = 1 / (10.57 - 10) = 1 / 0.57 ≈ 1.7544 for 10 ≤ x ≤ 10.57
Since the lengths of the pipes are independent, the joint probability density function (PDF) of X and Y is the product of their individual PDFs:
f(x, y) = f(x) * f(y) = 1.7544 * 1.7544 = 3.0805 for 10 ≤ x ≤ 10.57 and 10 ≤ y ≤ 10.57
Now, we want to find the probability that the second pipe (Y) is more than 0.11 feet longer than the first pipe (X).
Mathematically, we want to find P(Y > X + 0.11).
Let's set up the integral to calculate this probability:
P(Y > X + 0.11) = ∬[10 ≤ x ≤ 10.57] [y > x + 0.11] f(x, y) dx dy
We integrate with respect to x first and then with respect to y:
P(Y > X + 0.11) = ∫[10 ≤ y ≤ 10.57] ∫[10 ≤ x ≤ y - 0.11] f(x, y) dx dy
P(Y > X + 0.11) = ∫[10 ≤ y ≤ 10.57] [∫[10 ≤ x ≤ y - 0.11] 3.0805 dx] dy
P(Y > X + 0.11) = ∫[10 ≤ y ≤ 10.57] [3.0805 * (x)] from x = 10 to x = y - 0.11 dy
P(Y > X + 0.11) = ∫[10 ≤ y ≤ 10.57] [3.0805 * (y - (10 - 0.11))] dy
P(Y > X + 0.11) = 3.0805 * ∫[10 ≤ y ≤ 10.57] (y - 9.89) dy
P(Y > X + 0.11) = 3.0805 * [(y² / 2) - 9.89y] from y = 10 to y = 10.57
P(Y > X + 0.11) = 3.0805 * [((10.57)² / 2) - 9.89 * 10.57 - (((10)² / 2) - 9.89 * 10)]
P(Y > X + 0.11) = 3.0805 * [((111.7249 / 2) - 104.9135 - (50 / 2 - 98.9)]
P(Y > X + 0.11) = 3.0805 * [(55.86245 - 104.9135 + 49.9)]
P(Y > X + 0.11) = 3.0805 * [0.84895]
P(Y > X + 0.11) ≈ 2.6092
Therefore, the probability that the second pipe (with length Y) is more than 0.11 feet longer than the first pipe (with length X) is approximately 2.6092%.
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COLLE
past d
see co
A boat capsized and sank in a lake Based on an assumption of a mean weight of 131 lb, the boat was rated to carry 60 assengers (s the load lin was 7,860 lb).
After the boat sank, the assumed mean weight for similar boats was changed from 131 lb to 173 lb Complete parts a and below.
a. Assume that a similar boat is loaded with 60 passengers, and assume that the weights of people are normally distributed with a mea of 176 1 lb end a standard
deviation of 40.2 lb. Find the probability that the boat is overloaded because the 60 passengers have a mean weight greater than 131 ||
The probability is
(Round to four decimal places as needed)
b. The boat was later rated to carry only 17 passengers, and the load limit was changed to 2,941 lb. Find the probability t at the boat is erloaded bause the
mean weight of the passengers is greater than 173 (so that their total weight is greater than the maximum capacity of 29 1 lb)
The probability is
(Round to four decimal places as needed)
Do the new ratings appear to be safe when the boat is loaded with 17 passengers? Choose the correct answer below.
sees o
ents
see sc
see sco
past do
O A. Because the probability of overloading is lower with the new ratings than with the old ratings, the new ratings appes to be safe
OB. Because there is a high probability of overloading, the new ratings appear to be safe when the boat is loaded with passengers
OC. Because there is a high probability of overloading, the new ratings do not appear to be safe when the boat is loaded with 17 passe ers:
Click to select your answer(s)
past due
Help me plz
8th grade math
Answer
I would say the 3rd one.
Step-by-step explanation:
I do not really remember this but I am in 8th grade math to (Algebra)
Pls help me plssss. Bella measured the heights of her corn stalks in centimeters. The heights are 81, 88, 69,65, 87.
What is the mean height of Bella's corn stalks? ——————————
O A 69 cm
O B. 75 cm
O C. 78 cm
OD 80 cm
O E 81 cm
Answer:
the answer is C. 78
Step-by-step explanation:
First, you have to add together 81, 88, 69, 65, and 87; its total is 390. The next step is to see how many numbers there are. In total there are 5 numbers. Lastly, you have to divide 390 by 5 which is 78.
#9A
What is a reasonable first step to solve for y?
1/ 4x + 3y = 2z
Wite the number
in standered form 80+9=
Answer:
89
eighty-nine
350 - 15x = 200 - 10x
Sam’s Jet Ski rental charges $350 to rent a jetski plus $15 per hour. Brian’s Jet Ski rental charges $200 to rent a jetski plus $10 per hour
Steven has an account with $350 in it and he withdrawals $15 per day. Jessica has an account with $200 and withdrawals $10 per day.
Water tank A has 350 gallons of water and is losing 10 gallons per minute. Water tank B has 200 gallons of water and is losing 15 gallons per minute
Tree A has a height of 350 centimeters and is growing at a rate of 15 cm per day. Tree B has a height of 200 centimeters and is growing at a rate of 10 centimeters per day
Answer
Steven has an account with $350 in it and he withdrawals $15 per day. Jessica has an account with $200 and withdrawals $10 per day.
Question 1. Write a function called simulate that generates exactly one simulated value of your test statistic under the null hypothesis. It should take no arguments and simulate 50 area codes under the assumption that the result of each area is sampled from the range 200-999 inclusive with equal probability. Your function should return the number of times you saw the 781 area code in those 50 random spam calls.
Answer:
The function written in python is as follows:
import random
def simulate():
count = 0
for i in range(1,51):
num = random.randint(200,1000)
if num == 781:
count = count + 1
print(count)
Step-by-step explanation:
This line imports the random library
import random
This line defines the function
def simulate():
This line initializes count to 0
count = 0
This line iterates from 1 to 50
for i in range(1,51):
This line generates random number between 200 and 999
num = random.randint(200,1000)
This line checks if random number is 781
if num == 781:
If yes, the count variable is incremented by 1
count = count + 1
This line prints the number of times 781 is generated
print(count)
Andy is scuba diving. He starts at sea level and then descends 10 feet in 212 minutes.
Descent = 10 feet
Time required = 2 1/2 minutes.
The rate of descent = (10 feet)/(2.5 mn) = 4 ft/min
In 6 minutes, the descent will be
(4 ft/min)*(6 min) = 24 ft
Answer:
(a) 4 feet/minute
(b) 24 feet
Since there are no exponents in this problem, the next step is
✔ (- 2)2.2
.
Simplify the previous step and you get
.
The final answer is
Anwers:
22 is the answer
Bond X is a premium bond making semiannual payments. The bond pays a coupon rate of 9 percent, has a YTM of 7 percent, and has 13 years to maturity. Bond Y is a discount bond making semiannual payments. This bond pays a coupon rate of 7 percent, has a YTM of 9 percent, and also has 13 years to maturity. The bonds have a $1,000 par value.
What is the price of each bond today? If interest rates remain unchanged, what do you expect the price of these bonds to be one year from now? In three years? In eight years? In 12 years? In 13 years?
Answer:
Bond Xcurrent market price:
PV of face value = $1,000 / (1 + 3.5%)²⁶ = $
PV of coupon payments = $45 x 16.89035 (PV annuity factor, 3.5%, 26 periods) = $760.07
current market price = $408.84 + $760.07 = $1,168.91
price in 1 year:
PV of face value = $1,000 / (1 + 3.5%)²⁴ = $437.96
PV of coupon payments = $45 x 16.05837 (PV annuity factor, 3.5%, 24 periods) = $722.63
market price = $437.96 + $722.63 = $1,160.59
price in 3 years:
PV of face value = $1,000 / (1 + 3.5%)²⁰ = $502.57
PV of coupon payments = $45 x 14.2124 (PV annuity factor, 3.5%, 20 periods) = $639.56
market price = $502.57+ $639.56 = $1,142.13
price in 8 years:
PV of face value = $1,000 / (1 + 3.5%)¹⁰ = $708.92
PV of coupon payments = $45 x 8.31661 (PV annuity factor, 3.5%, 10 periods) = $374.25
market price = $708.92 + $374.25 = $1,083.17
price in 12 years:
PV of face value = $1,000 / (1 + 3.5%)² = $933.51
PV of coupon payments = $45 x 1.89969 (PV annuity factor, 3.5%, 2 periods) = $85.49
market price = $933.51 + $85.49 = $1,019
price in 13 years:
market price = $1,000 + $45 = $1,045
Bond Ycurrent market price:
PV of face value = $1,000 / (1 + 4.5%)²⁶ = $318.40
PV of coupon payments = $35 x 15.14661 (PV annuity factor, 4.5%, 26 periods) = $530.13
current market price = $318.40 + $530.13 = $847.53
price in 1 year:
PV of face value = $1,000 / (1 + 4.5%)²⁴ = $347.70
PV of coupon payments = $35 x 14.49548 (PV annuity factor, 4.5%, 24 periods) = $507.34
market price = $347.70 + $507.34 = $855.04
price in 3 years:
PV of face value = $1,000 / (1 + 4.5%)²⁰ = $414.64
PV of coupon payments = $35 x 13.00794 (PV annuity factor, 4.5%, 20 periods) = $455.28
market price = $414.64+ $455.28 = $869.92
price in 8 years:
PV of face value = $1,000 / (1 + 4.5%)¹⁰ = $643.93
PV of coupon payments = $35 x 7.91272 (PV annuity factor, 4.5%, 10 periods) = $276.95
market price = $643.93 + $276.95 = $920.88
price in 12 years:
PV of face value = $1,000 / (1 + 4.5%)² = $915.73
PV of coupon payments = $35 x 1.87267 (PV annuity factor, 4.5%, 2 periods) = $65.54
market price = $915.73 + $65.54 = $981.27
price in 13 years:
market price = $1,000 + $35 = $1,035
Loren spent $42.25 to fill her car with 13 gallons of gas. How much did Loren pay per gallon?
Answer: 3.25
Step-by-step explanation: What I did was Multiply 42.25 by 100 ( To make it easier) and then divide it by 13. After that, I divided the quotient by 100 to get the real answer, which was 3.25
Let me know if I was helpful or not!
$75 dinner; 18% tip
Explained step by step pls
Answer: $13.50
Step-by-step explanation:
Answer:
$13.5
Step-by-step explanation:
Everything you do is multiply 75 by 0.18 ( 0.18 represents 18%)
which gives you 13.5, so the tip would be $13.50
How much smaller is x−3 than x+4?
Answer: bsf google
Step-by-step explanation: go to google look it up and find the answer
Answer:
x-3
Step-by-step explanation:
It's x-3 because if you put 12-3 it will be 9 but if you add x+4 it will be 16
Helppp need help (p.s: Zearn
(50×20) - (1×20)
Step-by-step explanation:
there is 50 twenties (20) so its 50 × 20 and 1 twenty is 20
logan drew 4 hearts and 40 circles. What is the ratio of hearts to al shapes?
Answer:
1:11
Step-by-step explanation:
4(hearts):44(all) in simplest form is 1:11 because 4 and 44 are divisible by 4.
Answer:4:40
Step-by-step explanation:
Big chickens: The weights of broilers (commercially raised chickens) are approximately normally distributed with mean 1387 grams and standard deviation 192 grams. Use the TI-84 Plus calculator to answer the following. (a) What proportion of broilers weigh between 1150 and 1308 grams? (b) What is the probability that a randomly selected broiler weighs more than 1510 grams? (c) Is it unusual for a broiler to weigh more than 1610 grams? Round the answers to at least four decimal places.
Answer:
a) 0.2318
b) 0.2609
c) No it is not unusual for a broiler to weigh more than 1610 grams
Step-by-step explanation:
We solve using z score formula
z-score is is z = (x-μ)/σ, where x is the raw score, μ is the population mean, and σ is the population standard deviation.
Mean 1387 grams and standard deviation 192 grams. Use the TI-84 Plus calculator to answer the following.
(a) What proportion of broilers weigh between 1150 and 1308 grams?
For 1150 grams
z = 1150 - 1387/192
= -1.23438
Probability value from Z-Table:
P(x = 1150) = 0.10853
For 1308 grams
z = 1308 - 1387/192
= -0.41146
Probability value from Z-Table:
P(x = 1308) = 0.34037
Proportion of broilers weigh between 1150 and 1308 grams is:
P(x = 1308) - P(x = 1150)
0.34037 - 0.10853
= 0.23184
≈ 0.2318
(b) What is the probability that a randomly selected broiler weighs more than 1510 grams?
1510 - 1387/192
= 0.64063
Probabilty value from Z-Table:
P(x<1510) = 0.73912
P(x>1510) = 1 - P(x<1510) = 0.26088
≈ 0.2609
(c) Is it unusual for a broiler to weigh more than 1610 grams?
1610- 1387/192
= 1.16146
Probability value from Z-Table:
P(x<1610) = 0.87727
P(x>1610) = 1 - P(x<1610) = 0.12273
≈ 0.1227
No it is not unusual for a broiler to weigh more than 1610 grams
help with math pls pls
Answer:
62 degrees
Step-by-step explanation:
If 167 degrees is the whole angle measurement, then you take 167-105.
what is the sum a 23 and 4 /4
Answer:
the anwser is 24 please mark brianliest
Answer:
The answer is 24.
A chemist is performing an experiment by observing the effects when she combines two solutions. She monitors the temperature of the combined solution over the course of eight hours and records it in this table below.
The chemist can model the temperature with a polynomial function. During these eight hours, over what interval is the temperature decreasing?
A. From hour 0 to hour 8
B. From hour 5 to hour 8
C. From hour 0 to hour 5
D. From hour 2 to hour 6
Answer:
A. From hour 0 to hour 5
Step-by-step explanation:
For all Plato users
Interval of the temperature decreasing is from hour 0 to hour 5.
What is interval?
an interval is defined as a group of numbers which includes all numbers between the beginning and the end.
According to given data is showing that the temperature decreasing zero hour to 1 hour , then 1 to 2 hour, then 2 to 3 hour, then 3 to 4 hour, then 4 to 5 hour.
So the interval of the temperature decreasing is from hour 0 to hour 5.
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The Sweet Shoppe sells a half-dozen cupcakes for $16.50. The Cupcake Factory sells a dozen cupcakes for $30.00. Jameska purchases two cupcakes from each shop. What is the difference in the purchases?
The difference in the purchases is $
.
Answer:
$1.50
Step-by-step explanation:
The cost of half of dozen of cupcakes at Sweet Shoppe = $16.50.
The cost of a dozen cupcakes at Cupcake factory = $30.00. Therefore the cost of half a dozen cupcakes at Cupcake factory = $30.00 / 2 = $15.00
The difference in purchases = cost of half a dozen cupcakes at Sweet Shoppe - cost of half of dozen of cupcakes at cupcake factory
The difference in purchases = $16.50 - $15.00 = $1.50
This means that their is a difference of $1.50 for half a dozen cupcakes between the Sweet Shoppe and cupcake factory.
What is 3/100 - 1/50 equal?
Answer:
0.01?
Step-by-step explanation:
An electrican's shop charges $55
service fee plus $50 per hour for labor.
The linear equation that models
C= $50+ $55, where h is the number of labor hours and C is the total cost.
How much would the shop charge a customer for a job that takes 17hrs?
Answer:
$905
Step-by-step explanation:
$50×h+55=?
h=17 and you pay so $50×h
so $50×h=850
so now that you calculated the cost of the labor add the $55 dollar service fee
850+55=905
Diana goes on vacation with $260. Each day, she spends the same amount of
money. After 1, 2, 3, and 4 days on vacation, she has $242, $224, $206, and
$188, respectively.
Please help
In , the Pew Internet & American Life Project asked teens aged to several questions about their attitudes toward social media. The results showed that say social media makes them feel more connected to what is going on in their friends' lives; say social media helps them interact with a more diverse group of people; and feel pressure to post content that will get a lot of likes and comments.
Round your answers to four decimal places.
a. Develop a point estimate of the proportion of teens aged to who say social media makes them feel more connected to what is going on in their friends' lives.
b. Develop a point estimate of the proportion of teens aged to who say social media helps them interact with a more diverse group of people.
c. Develop a point estimate of the proportion of teens aged to who feel pressure to post content that will get a lot of likes and comments.
Complete Question
The complete question is shown on the first uploaded image
Answer:
a
[tex]\^ p_1 = 0.8102 [/tex]
b
[tex]\^ p_2 = 0.6904 [/tex]
c
[tex]\^ p_3 = 0.3701 [/tex]
Step-by-step explanation:
From the question we are told that
The sample size is n = 743
The number that said social media makes them feel more connected to what is going on in their friends' lives is k = 602
The number that said social media helps them interact with a more diverse group of people is y = 513
The number that said feel pressure to post content that will get a lot of likes and comments is c = 275
Generally a point estimate of the proportion of teens aged 13 to 17 who say social media makes them feel more connected to what is going on in their friends' lives is mathematically represented as
[tex]\^ p_1 = \frac{k}{n}[/tex]
=> [tex]\^ p_1 = \frac{602}{743 }[/tex]\
=> [tex]\^ p_1 = 0.8102 [/tex]
Generally a point estimate of the proportion of teens aged 13 to 17 who say social media helps them interact with a more diverse group of people is mathematically represented as
[tex]\^ p_2 = \frac{k}{n}[/tex]
=> [tex]\^ p_2 = \frac{513}{743 }[/tex]\
=> [tex]\^ p_2 = 0.6904 [/tex]
Generally a point estimate of the proportion of teens aged 13 to 17 who feel pressure to post content that will get a lot of likes and comments is mathematically represented as
[tex]\^ p_3 = \frac{k}{n}[/tex]
=> [tex]\^ p_3 = \frac{275}{743 }[/tex]
=> [tex]\^ p_3 = 0.3701 [/tex]
The point estimate of the teens aged to who say social media makes them feel more connected is 0.8102.
How to calculate the point estimateThe point estimate of the proportion of teens aged to who say social media makes them feel more connected to what is going on in their friends' lives will be:
= Number of teens / Sample size
= 602/743
=™0.8102
The point estimate of the proportion of teens aged to who say social media helps them interact with a more diverse group of people will be:
= 513/743
= 0.6904
The point estimate of the proportion of teens aged to who feel pressure to post content that will get a lot of likes and comments will be:
= 275/743
= 0.3701
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Help please
-x^3 = 216
a. +/- 6
B. 6
C. -6 ∛6
D. -6
Answer:
D. -6
Step-by-step explanation:
SInce x is negative, the - before the six would be cancelled out leaving the equation to be 6^3=216 which is correct