1 Which requires more work, lifting a 10kg sack of
coal or lifting a 15kg bag of feathers?

Answers

Answer 1
15KG bag of feathers

Related Questions

the following can increase the amount of friction in the surface, except ______.
a. glue
b. paper
c. lubricant
d. foil​

Answers

Answer:

c. lubricant..........



How much potential energy did the the milkshake have after it fell off of the counter, just before it hit the ground (at the bottom)? Make sure to write the correct units with

your answer!

Answers

Answer:

The formula for potential energy depends on the force acting on the two objects. For the gravitational force the formula is P.E. = mgh, where m is the mass in kilograms, g is the acceleration due to gravity (9.8 m / s2 at the surface of the earth) and h is the height in meters.

Compare and contrast instantaneous and average speed.

Answers

Answer:

instantaneous velocity is a velocity covered at an instant while average velocity is the change in distance/ the change in time taken

1. A stone is thrown vertically upward with velocity of 15 m/s at the same time, 10 m vertically above a second stone is allowed to fall. After what time and at what height do they collide (take g = 10 ms^-2)​

Answers

Let the ball at the ground be A and that at the top be B.

Assume that you see the motion of A while sitting at B.

You(B) are obviously at rest w.r.t. yourselves. However you(B) and A have the same acceleration in the same direction. Thus acceleration of A w.r.t. you(B) is 0.

Thus, to you, it will appear as if A is travelling towards you with an uniform speed of 20m/s.

Dividing the distance 20m with that speed, we get that A reaches you(B) in 1s.

Now, you have considered these motions and time by assuming you were stationed at B. However, the time taken for A to meet B shouldn't be dependent on which reference frame you assume. Thus, time taken for A and B to collide is 1s.

Since B falls freely, he covers a distance of  1/2(g)(1²)=5  (assuming g = 10m/s²)

Thus, they meet at a height of (20–5)m = 15m from the ground.

Which is the BEST example of physics in the body?
A. a single beat of the heart
B. how the circulatory system works
с. balance when the body is standing still
D. the movement of an arm throwing a ball

Answers

I think the answer is gonna be B but check quizlet to be sure

The best example of physics in the body is the movement of an arm throwing a ball. The correct option is D.

What is physics?

Physics is the branch of science that studies the structure of matter and how the universe's fundamental constituents interact.

It investigates objects ranging from the very small to the entire universe using quantum mechanics and general relativity.

Physics is the natural science that investigates matter, its fundamental constituents, its motion and behavior in space and time, as well as the related entities of energy and force.

Physics is one of the most fundamental scientific disciplines, with the primary goal of understanding how the universe functions.

The movement of an arm throwing a ball is the best example of physics in the body.

Thus, the correct option is D.

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Which will be different on the moon than it is on Earth?

weight

mass

Answers

Answer:

Below

Explanation:

On the moon, an objects weight will be different than it is on earth. This is because we cannot change the mass of an object, the mass of an object is the measure of matter an object has. However the weight is depended on the gravitational pull of whatever planet you are on. In this case, weight will be lighter on the moon than it is on earth because the moon's gravitational pull is 1.62 m/s^2 while earths is around 9.8 m/s^2.

Hope that helps!

PLz help--- What's happening here?
This object is not moving
This object is not changing speeds.
This object is changing speeds; it's getting faster.
This object is changing speeds; it's getting slower.

Answers

Answer:

getting faster

Explanation:

the curve gets more steeper, and steeper line shows more distance for less time, meaning faster.

3. What happens if an object has a negative acceleration?​

Answers

Answer:

They will go backwards?

Explanation:

If positive they go forward but is negative they go backwards.

Mercury’s natural state is where the atoms are close to each other but are still free to pass by each other. In which state(s) could mercury naturally exist?

Answers

Answer:

Mercury's natural state is where the atoms are close to each other but are still free to pass by each other. In which state(s) could mercury naturally exist?

Liquid is the answer

Explanation:

A rock excerts a pressure of 20 N/cm^2 on the ground. what does 20N/cm^2 mean?

A force of __________ acts on each _________ of area​

Answers

Answer:

A force of 20N acts on each cm^2 of area

Look at the diagram shown below. The reading on ammeter 1 is 0.15 A. What will the reading on ammeter 2 be

Answers

There's no way to tell, without knowing the resistance of either X-1 or X-2, or the reading on A3.

Image credit: The Hubble Heritage Team (AURASTSCI/NASA)
To which category does galaxy #2 belong? Why does it belong in this category?
WRITER

Answers

Can i ask u a question

how to do the next ques for more

Brainliest me please

HELPPPPPPPPPPPPPPPPPPP

Answers

Answer:

directly proportional

Explanation:

The spark plugs are threaded into the top of each cylinder and provide a place for the spark to jump within the ________.

Answers

Answer:

"the spark plug gap"

The plug provides a gap between the input voltage and the ground supplied by the car chassis.

Two cars a and b are moving along a straight road in the same direction with velocities of 25km/h and 40km/h . Find the velocity of car b relative to car a

Answers

Please find attached photograph for your answer.

Hope it helps.

Do comment if you have any query.

Two cars A and B are moving along a straight road in the OPPOSITE direction with velocities of 25 km/h and 40 km/h, respectively. Find the velocity of car B relative to car​

Answers

Answer:

65km/h

Explanation:

Here,

Relative velocity of car moving in different directions with different velocities =Va + Vb

=25+40

=65 km/h

Please find attached photograph for your answer.

Hope it helps.

Do comment if you have any query.

A block with initial velocity of 3 m/s slides 9 m across a rough horizontal surface before coming to rest. What is the coefficient of kinetic
friction?

Answers

The coefficient of kinetic friction between the block and the horizontal surface is 0.051.

The given parameters;

initial velocity, u = 3 m/sdistance traveled by the block, s = 9 m

The acceleration of the block is calculated as follows;

[tex]v^2 = u^2 + 2(-a)s\\\\v^2 = u^2 - 2as\\\\a = \frac{u^2 - v^2}{2s} \\\\a = \frac{3^2 - 0^2}{2\times 9} \\\\a =0.5 \ m/s^2[/tex]

The coefficient of kinetic friction between the block and the horizontal surface is calculated as follows;

[tex]\mu_k mg = ma\\\\\mu_k = \frac{a}{g} \\\\\mu_k = \frac{0.5}{9.8} \\\\\mu_k = 0.051[/tex]

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which is not a general characteristic of starburst galaxies?

Answers

Starburst galaxies is simply known as the rate at which the galaxy is now converting gas into stars. The statement that is not a general characteristic of starburst galaxies is that The "starburst" is thought to be caused by the presence of a supermassive black hole in the galaxy's center.

The starburst galaxy is also regarded as the free quantity of gas with which stars can be formed.

They are known to be rare. A starburst is known to be an astrophysical process. It is the process of star formation happening at a rate that is large when compared to the rate that is often observed.

See full question below

Which is not a general characteristic of starburst galaxies?

The "starburst" is thought to be caused by the presence of a supermassive black hole in the galaxy's center.

The observed features that us to classily a galaxy as a 'starburst" galaxy must be only temporary

phenomena in the galaxy' Supernovae occur so frequently that their effects combine to drive a galactic wind that blows material into intergalactic space.

The galaxy's rate of star formation is many times higher than the rate of star formation in the Milky Way

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I need to know how to draw the diagram of the last two questions

Answers

Answer

In the parallel circuit, you have to position the switch on only one of the loops.

Fuses of ________________________
a. same kind are used for different purposes
b. different kind are used for different purposes
c. both of the above are correct
d. none of these

Answers

Answer:

C

Explanation:

fuses of same kind can be used for different things, and of different kinds could be used for different things as well.

if you exert a force on an object, but the object remains stationary as you apply the force, then how much work have you done on the object?

Answers

Answer:

no work done

Explanation:

unless you moved the object

When we apply a force on an object, but the object remains at rest when the force is applied, then we have zero work done on the object because the object does not move.

What is Work done?

Work done by a force is defined as the product of the displacement and the component of the force exerted by the object in the direction of displacement. Work done is expressed as:

Work done= Force* Displacement

When an object is at rest, there is no external force on it except gravity acting on it, in which case work will be zero because the force acting on it is perpendicular. Thus displacement is zero and if displacement is zero then work done will be zero.

Suppose that displacement is zero then,

W=f×0

Work done is zero

Thus, the work done is zero.

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A. Read these sentences carefully. Choose the correct form of adjectives.
1. Solomon is the
king of all.
a wise
b. wiser
c. wisest
2. Yogurt is
than candies.
a delicious b. more delicious c. most delicious
3. Mayon Volcano is the
volcano for me.
a most majestic b. more majestic
c. majestic
4 My father is an
man
a industrious b. more industrious c. most industrious
5. I was the
when my friend graduated with honors.
a happy b. happier
c. happiest

Answers

Answer:

1. wisest

2. more delicious

3. majestic (not sure about this one)

4. industrious

5. happiest

You and your friend are pushing a box at the same constant speed. You pushed 20 feet in 10 minutes, your friend was pushing for 5 minutes. What distance must she travel so the two of you can travel at the same speed?

Answers

Answer:

60 N.C

Explanation:

The box will move in the direction of the push and pull with a force of 60 N. C.

If you and your friend are pushing a box at the same constant speed. You pushed 20 feet in 10 minutes, your friend was pushing for 5 minutes. , then the distance must she travel so the two of you can travel at the same speed would be 30 feet.

What is speed?

The total distance covered by any object per unit of time is known as speed. It depends only on the magnitude of the moving object.

As given in the problem If you and your friend are pushing a box at the same constant speed. You pushed 20 feet in 10 minutes, your friend was pushing for 5 minutes.

The distance traveled by box = 20 + 10

                                                 = 30 feets

                             

Thus, the distance must she travel so the two of you can travel at the same speed would be 30 feet.

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A rock on the moon has 0.5kg. It is brought to Earth where the gravitational field is stronger. On Earth, the rock will have:
a) Less mass and same weight
b) The same mass and more weight
c) Less mass and less weight
d) The same mass and same weight

Answers

Answer:

Explanation:

It will be B.

The correct answer is the same mass and less weight.

What happens to the weight of an object when it is brought from the moon to the Earth?

The weight decreases. Your weight will be 1/6 of the weight on the moon that you had on Earth. This is because the mass of the moon is less hence the gravitational pull is very low compared to Earth.

What happens to the mass of an object when you take it to the moon?

Therefore, the mass of an object on the Moon remains the same as its mass on Earth. But its weight gets less because the gravity on the moon is less than on the Earth.

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if 20 boys can sweep the school compound in 8 minutes, how many boys can sweep it in 10minutes​

Answers

Answer:

So this is just a ratio/proportion problem

so lets say its in boys:minutes

so in the first scenario

20:8

and we want to find

x:10

So proportion really

20/8=x/10

cross multiply

25

25 boys can sweep it in 10 minutes

Suppose measure the mass of an orange. Then you peel the orange and separate out the slices. If you measure the orange peel and all the slices, will that mass equal the mass of the whole orange?

yes

no

Answers

The mass of the orange after it has been cut into pieces will still remain the same as the mass of the whole orange.

Let us recall that the law of conservation of mass states that, mass can neither be created nor destroyed but is converted from one form to another. In accordance with this law of conservation of mass. The mass of the orange must remain the same after it has been cut in pieces.

Hence, If the mass of an orange is measured after it has been cut into pieces, the mass of the orange after it has been cut into pieces will still remain the same as the mass of the whole orange.

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Which statement describes the flow of heat? Question 8 options: Heat moves from a warmer object to a cooler object. Heat moves from a cooler object to a warmer object. Heat moves from a cooler object to a warmer object. Heat moves only between two cold objects.

Answers

Answer:

A

Explanation:

Block 1, of mass m1, moves across a frictionless surface with speed ui. It collides elastically with block 2, of mass m2, which is at rest (vi=0). (Figure 1)After the collision, block 1 moves with speed uf, while block 2 moves with speed vf. Assume that m1>m2, so that after the collision, the two objects move off in the direction of the first object before the collision. What is the final speed vf of block 2?

Answers

The conservation of the momentum allows to find the velocity of the second body after the elastic collision is:

           [tex]v_f = \frac{2u_o}{1- \frac{m_2}{m_1} }[/tex]  

the momentum is defined by the product of the mass and the velocity of the body.

        p = mv

The bold letters indicate vectors, p is the moment, m the mass and v the velocity of the body.

If the system is isolated, the forces during the collision are internal and the it  is conserved. Let's find the momentum is two instants.

Initial instant. Before crash.

      p₀ = m₁ u₀ + 0

Final moment. After crash.

      [tex]p_f = m_1 u_f + m_2 v_f[/tex]  

The momentum is preserved.

      p₀ = [tex]p_f[/tex]  

      [tex]m_1 u_o = m_1 u_f + m_2 v_f[/tex]  

Since the collision is elastic, the kinetic energy is conserved.

      K₀ = [tex]K_f[/tex]

      ½ m₁ u₀² = ½ m₁ [tex]u_f^2[/tex]  + ½ m₂  [tex]v_f^2[/tex]  

       

Let's write our system of equations.

       [tex]m_1 u_o = m_1 u_f + m_2 v_f \\m_1 u_o^2 = m_1 u_f^2 + m_2 v_f^2[/tex]

       

Let's solve

       [tex]u_f = u_o - \frac{m_2}{m_2} \ v_f \\u_f^2 = u_o^2 - \frac{m_2}{m_1} \ v_f^2[/tex]

       

       [tex]( u_o - \frac{m_2}{m_1} v_f)^2 = u_o - \frac{m_2}{m_1} \ v_f^2 \\u_o^2 - 2 \frac{m_2}{m_1} \ u_o v_f + (\frac{m_2}{m_1} )^2 v_f^2 = u_o^2 - \frac{m_2 }{m_1} \ v_f^2[/tex]  

         

        [tex]2 \frac{m_2}{m_1} \ u_o = \frac{m_2}{m_1} v_f \ ( 1 - \frac{m_2}{m_1}) \\v_f = \frac{2u_o}{1-\frac{m_2}{m_1} }[/tex]

In conclusion, using the conservation of momentum, we can find the velocity of the second body after the elastic collision is:

           [tex]v_f = \frac{2u_o}{1-\frac{m_2}{m_1} }[/tex]  

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what noncontact forces act on an object that are balanced

Answers

Answer:

I can give you a list of noncontact forces off of my head, if that is what you need.

Explanation:

First, gravity. It acts everywhere and pulls down every object that is in the air towards the ground, unless they have an equal and opposite force that counters it.

Second, wind. I don't think this will count because wind is a physical thing, but it can be used in the same way as we did with gravity. If the force counteracting it is larger, equal, and opposite of the force it is countering, then it will move forward, through the wind.

A car goes from 60 m/s to 75 m/s in 10 seconds.calculate the car’s acceleration?

Answers

Explanation:

Uhhhh here is an example

a=vt. =27 m/s10 s. =2.7 m/s2.

[tex]▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪[/tex]

Acceleration of the car is ~

[tex] \boxed{1.5 \: \: m/s}[/tex]

[tex] \large \boxed{ \mathfrak{Step\:\: By\:\:Step\:\:Explanation}}[/tex]

We know that,

Acceleration = rate of change in velocity ~

that is ~

[tex]a = \dfrac{v - u}{t} [/tex]

where,

v = final velocity

u = initial velocity

t = time taken ~

now, let's solve ~

[tex]a = \dfrac{75 - 60}{10} [/tex]

[tex]a = \dfrac{15}{10} [/tex]

[tex]a = 1.5 \: \: m/s[/tex]
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