1) What will the time be 90 minutes after 11:15 in the morning

2) What will the time be 135 minutes after 11:15 in the morning

The solution of the system is a = -1, b = 1, c = 0, and d = -3.

To find the cubic function f(x) = ax³ + bx² + cx + d that satisfies the given equations by using a system of equations and solving the system using matrices, we proceed as follows:Equations for the given cubic function:f(-2) = a(-2)³ + b(-2)² + c(-2) + d = -7 ...(1)f(-1) = a(-1)³ + b(-1)² + c(-1) + d = 2 ...(2)f(1) = a(1)³ + b(1)² + c(1) + d = -4 ...(3)f(2) = a(2)³ + b(2)² + c(2) + d = -7 ...(4)The matrix form of the system of equations is given by AX = B, whereA = [(-2)³ (-2)² -2 1; (-1)³ (-1)² -1 1; (1)³ (1)² 1 1; (2)³ (2)² 2 1],X = [a; b; c; d], andB = [-7; 2; -4; -7].The augmented matrix form of the system of equations is given by [A|B] = [(-2)³ (-2)² -2 1 -7; (-1)³ (-1)² -1 1 2; (1)³ (1)² 1 1 -4; (2)³ (2)² 2 1 -7].Performing the row operations, we get the row echelon form of the augmented matrix as follows:[A|B] = [1 0 0 0 -1; 0 1 0 0 1; 0 0 1 0 0; 0 0 0 1 -3].Therefore, the solution of the system is a = -1, b = 1, c = 0, and d = -3.Hence, the cubic function f(x) = ax³ + bx² + cx + d that satisfies the given equations is given by f(x) = -x³ + x² - 3.

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The cumulative distribution function gives us the probability that the random variable is less than or equal to a given value.

The cumulative distribution function (CDF) of a continuous random variable x is a function which gives the probability that the random variable x is less than or equal to a given value x. Mathematically it is expressed as:

[tex]F(x) = P(X ≤ x)[/tex]

The calculation of the cumulative distribution function is done by integrating the probability density function (PDF) from the lower limit to the given value x. Thus,

[tex]F(x) = ∫-∞ x f(u) du[/tex]

Where f(u) is the probability density function.

For example, if we have a continuous random variable x with probability density function f(x) = x2, then the cumulative distribution function [tex]F(x) = ∫-∞ x x2 du = 1/3x3 + c.[/tex]

Thus, It is a powerful tool for analysing the probability distribution of a continuous random variable.

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Complete question:

What is the cumulative distribution function for a continuous random variable x?

Answer:

-16²+1,000 > 300  [After an edit in the original expression, as noted below).

Step-by-step explanation:

The equation d = -16² +1,000 tells us the height above ground, d, of the object after t seconds.  When t = 0 seconds, the ball has not been dropped yet, but the equation tells us that d = 1,000 at t = 0.  That means the object starts at 1,000 feet above ground.

We want the time it takes for the object to reach any height greater than 300 feet above ground.  This is a tad (metric for just a tiny bit) unexpected, since even at time of 0 the object is greater than 1,000 feet.

Looking at the answer options, note that the left side of the inequalities is -16^2+100.  I will assume the 4th option has a typo:  the f^2.  It should read the same as the others.  

      -16^2+100 is the distance, d.  So to help us think this through, let's rephrase the answer options in terms of distance, d:

1)    d<300

2)   d≤300

3)   d≥300

4)   d>300

   The question asks "We want the time it takes for the object to reach any height greater than 300 feet above ground."

Option 4 says d>300, or height greater than 300.  That is the inequality that matches the question.  [Note:  It did not say greater than or equal to (option 3).]

Answer:The quantity of grocer of price $1.40 is 45 pounds

The quantity of grocer of price 40 cents is 55 pounds

Step-by-step explanation:

Let The quantity of one grocer = x pound

Let The quantity of other grocer = y pound

The selling price of x grocer = 40 cents per pound

The selling price of y grocer = $ 1.40 per pound = 1.40 × 100 = 140 cents

Total quantity = 100 pounds

Total price of both grocer = 85 cents

According to question

x + y = 100                        .........A

And

40 × x + 140 y = 85 × 100

Or, 40 x + 140 y = 8500         ........B

Solving eq A and eq b

(40 x + 140 y) - 40 × ( x + y ) = 8500 - 40 × 100

Or, (40 x - 40 x) + (140 y - 40 y) = 8500 - 4000

or, 0 + 100 y = 4500

∴  y =

i.e  y = 45 pounds

So, The quantity of grocer of price $1.40 = y = 45 pounds

Again

Put the vaue of y in eq A

x + y = 100

i.e x = 100 - y

or, x = 100 - 45

∴   x = 55 pounds

So, The quantity of grocer of price 40 cents = x = 55 pounds

Hence, The quantity of grocer of price $1.40 is 45 pounds

And The quantity of grocer of price 40 cents is 55 pounds  Answer

Answer:

the slope-intercept form of the line which is perpendicular bisector to the segment with endpoints A(5,9), B(7,13) is y = (-1/2)x + 14

a) 1/2, b) 1/4, c) 3/13, d) 7/26 (fraction of black and face cards) in a traditional Western pack of playing cards.

A traditional Western pack of playing cards consists of four suits: Hearts (colored red), Diamonds (colored red), Spades (colored black), and Clubs (colored black). Each suit has 13 cards: Ace, 2, 3, 4, 5, 6, 7, 8, 9, 10, Jack, Queen, and King.

a) To find the fraction of the playing cards that are red, we need to add up the number of red cards and divide by the total number of cards in the deck. There are two red suits, Hearts and Diamonds, and each has 13 cards. So there are 26 red cards in total. Since there are 52 cards in a deck, the fraction of red cards is 26/52 or 1/2.

b) To find the fraction of cards that are Diamonds, we simply divide the number of Diamonds (13) by the total number of cards (52). This gives us a fraction of 13/52 or 1/4.

c) To find the fraction of face cards, we need to add up the number of face cards and divide by the total number of cards in the deck. In each suit, there are three face cards: King, Queen, and Jack. So there are 12 face cards in each deck (4 suits x 3 face cards per suit). Therefore, there are 12/52 or 3/13 face cards in the deck.

d) To find the fraction of black and face cards, we need to count the number of black cards and the number of face cards that are also black. There are two black suits, Spades and Clubs, and each has 13 cards. So there are total 26 black cards. Of these 26 cards, there are 12 face cards (King, Queen, and Jack) which are not black, leaving 14 black cards which are face cards. Therefore, the fraction of black and face cards is 14/52 or 7/26.

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Based on the principle of Inequality, Attached image is a graph of the inequality for  |x| < 5. The red region is the solution set.

A mathematical statement known as an equation demonstrates the relationship between two or more numbers and variables by utilizing mathematical operations such as addition, subtraction, multiplication, division, exponents, and so forth.

Therefore, An expression that demonstrates a non-equal comparison of numbers and variables is called an inequality. So, the graph that best represents this solution set is a number line with open circles at x = -5 and x = 5 and a shaded region in between, indicating that all values of x within this range satisfy the inequality.

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Optiοn B. is cοrrect, the result οf substituting fοr y in the given equatiοns is x - 3 =x² + 2x - 4.

Equivalent expressiοns are expressiοns that wοrk the same even thοugh they lοοk different. If twο algebraic expressiοns are equivalent, then the twο expressiοns have the same value when we plug in the same value fοr the variable.

Tο substitute fοr y in the secοnd equatiοn, we can replace y with its equivalent expressiοn in terms οf x frοm the first equatiοn, which gives us:

x - 3 = x² + 2x - 4

This is option B.

Optiοn A is incοrrect because it substitutes y fοr its expressiοn in terms οf x in the wrοng equatiοn.

Optiοn C is incοrrect because it subtracts (x-3) instead οf adding it tο the secοnd equatiοn.

Optiοn D is incοrrect because it sets the expressiοn fοr y in the first equatiοn equal tο x² instead οf the expressiοn fοr y in the secοnd equatiοn.

Hence, οptiοn B. is cοrrect, the result οf substituting fοr y in the given equatiοns is x - 3 = x² + 2x - 4.

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Complete question:

What is result of substituting for y in the bottom equation?

y = x – 3,

y = x² + 2x – 4

A. y=(x-3)²+2(x-3)-4

B. x-3=x²+2x-4

C. y=x²+2x-4-(x-3)

D. (x-3)=x²

16. The base side y = 10.565 and altitude x = 22.657

17. The hypotenuse c = 49.70 and base y = 46.70.

18. The value of AB = 30√3 and AC = 45

19. The value of AB = 36√3 and BC = 18√3.

In geοmetry, a hypοtenuse is the lοngest side οf a right-angled triangle, the side οppοsite the right angle. The length οf the hypοtenuse can be fοund using the Pythagοrean theοrem, which states that the square οf the length οf the hypοtenuse equals the sum οf the squares οf the lengths οf the οther twο sides.

16. Given hypotenuse = 25

θ = 25°

Sin θ = opposite/hypotenuse

Sin 25° = y/25

y = Sin 25° × 25

y = 10.565

Given hypotenuse = 25

θ = 25°

Cos θ = adjacent/hypotenuse

Cos 25° = x/25

x = Cos 25° × 25

x = 22.657

17. Given Side = 17

θ = 20°

Sin 20° = 17/c

c = 17/Sin 20°

c = 49.70

Cos θ = adjacent/hypotenuse

Cos 20° = y/49.70

y = Cos 20° × 49.70

y = 46.70

18. Given BC = 15√3

In a 30°−60°−90°  triangle, the length of the hypotenuse is twice the length of the shorter leg, and the length of the longer leg is 3√ times the length of the shorter leg.

Thus, BC = 15√3

AB = 2(15√3)

= 30√3

and

AC = √3(15√3)

= 15 × 3

= 45

Thus, when BC = 15√3, then AB = 30√3 and AC = 45

19. Given AC = 54

In a 30°−60°−90°  triangle, the length of the hypotenuse is twice the length of the shorter leg, and the length of the longer leg is 3√ times the length of the shorter leg.

Thus, BC = x and AC = x√3

54 = x√3

54 = x√3

x = 54/√3

x = 18√3

BC = 18√3

AB = 2x = 2(BC) = 2(18√3)

= 36(√3)

Thus, when AC = 54, then AB = 36√3 and BC = 18√3.

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The equation of the given graph is: y = cosine (x + pi)

By convention, the cosine function like most other trigonometric functions has a period of 2π.

Since, the parental function is y = cos x, which has y-intercept at y = 1, and x-intercept at π/2.

From observation, the function showed in the graph attached has y-intercept at y = -1 and x-intercept at π/2.

This can be interpreted to mean that the function has been translated leftwards π units.

Ultimately, the function that belongs to this graph is; y = cosine (x + pi)

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Answer: D. y = cosine (x + pi)

Step-by-step explanation:

Answer:  C is our answer.

The first thing that we can do is divide the known number of books into the price that they sold for.

Our equation would be 89.25 divided by 7, which is 12.75. This means that one single book is 12.75.  We can look at the charts and point out where one book is 12.75, that is both A and D. While Chart B and C have 7 books for 89.25 which we know is correct.

Lets look at chart D.The next part we can solve is the price of 2 books. 12.75 x 2 is 25.50,  so we can mark question B incorrect since two books are 25.50 not 13.75.Chart B is incorrect because 14 books is double 7, so it should be twice as much as 89.25, which we should know 90 dollars is not two times as much 80. Chart A is incorrect because 11 x 12.75 is 140.25, while the chart reads as 22.75.

Now lets look at chart C. Next we can solve the price of 8 books. 8 x 12.75 is 102. Then we solve  for 9 books. 12.75 x 9 is 114.75, which means that C is correct.

I hope this helped & Good Luck <3!!

The equivalent expressions of [tex]x^3[/tex] are[tex]\frac{(x ^ 6)}{(x ^ 3)}[/tex]and [tex]\frac{(x^{-3}) }{(x^{-6}) }[/tex], the expressions [tex]\frac{(x^{30}) }{(x^{10})}[/tex] and [tex]\frac{(x ^ 4) ^ 2)}{x ^ 2}[/tex] are not equivalent to [tex]x^3[/tex].

What are equivalent expressions?

Equivalent expressions are different algebraic expressions that have the same value when evaluated for a particular set of variables.

The equivalent expressions  [tex]x^3[/tex] are:

[tex]\frac{(x ^ 4) ^ 2)}{x ^ 2}[/tex] : This expression can be simplified as follows:

=[tex]\frac{(x ^ 4) ^ 2)}{x ^ 2}[/tex]

= [tex]\frac{(x ^ 8)}{(x ^ 2) }[/tex]

=[tex]x^{8-2}[/tex]

= [tex]x^6[/tex]

[tex]\frac{(x ^ 6)}{(x ^ 3)}[/tex] : This expression can be simplified as follows:

=[tex]\frac{(x ^ 6)}{(x ^ 3)}[/tex]

= [tex]x^{6-3}[/tex]

=[tex]x^3[/tex]

[tex]\frac{(x^{30}) }{(x^{10})}[/tex] : This expression can be simplified as follows:

=[tex]\frac{(x^{30}) }{(x^{10})}[/tex]

=[tex]x^{30-10}[/tex]

=[tex]x^{20}[/tex]

[tex]\frac{(x^{-3}) }{(x^{-6}) }[/tex] : This expression can be simplified as follows:

=[tex]\frac{(x^{-3}) }{(x^{-6}) }[/tex]

=[tex]x^{-3-(-6)}[/tex]

=[tex]x^{-3+6}[/tex]

=[tex]x^{3}[/tex]

Therefore, the equivalent expressions of [tex]x^3[/tex] are[tex]\frac{(x ^ 6)}{(x ^ 3)}[/tex]and [tex]\frac{(x^{-3}) }{(x^{-6}) }[/tex] , the expressions [tex]\frac{(x^{30}) }{(x^{10})}[/tex] and [tex]\frac{(x ^ 4) ^ 2)}{x ^ 2}[/tex] are not equivalent to [tex]x^3[/tex].

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Answer:

y = - [tex]\frac{5}{2}[/tex] x - 1

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

calculate m using the slope formula

m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]

with (x₁, y₁ ) = (- 4, 9) and (x₂, y₂ ) = (2, - 6) ← 2 ordered pairs from the table

m = [tex]\frac{-6-9}{2-(-4)}[/tex] = [tex]\frac{-15}{2+4}[/tex] = [tex]\frac{-15}{6}[/tex] = - [tex]\frac{5}{2}[/tex]

the line crosses the y- axis at point (0, - 1 ), ordered pair from table, then

c = - 1

y = - [tex]\frac{5}{2}[/tex] x - 1 ← equation of line

Answer:

No

Step-by-step explanation:

[tex]\frac{6}{5}=1.2[/tex]

[tex]\frac{4}{3} =1.33[/tex]

[tex]\frac{6}{5} < \frac{4}{3}[/tex]

Hope this helps.

Answer:

No

Step-by-step explanation:

6/5=4/3

18=20

9≠10

For the given elementary chemical reaction, the solution to the question is: C = a^2 * (1-t^2/400(1-a))

The question asks about calculating the concentration of C in a chemical reaction. Given that the reaction equation is as follows: A + B → C The rate of reaction can be expressed as: dc/dt = k[A][B] Where, k is the rate constant[A] is the concentration of reactant A in moles/L[B] is the concentration of reactant B in moles/L, c is the concentration of product C in moles/L

The initial concentration of A and B is [A] = a moles/L, [B] = b moles/L Let r be the rate of reaction, i.e. r = dc/dt Thus, using the equation r = k[A][B], we get r = k(a)(b)Now, we can write a differential equation for the concentration of C as follows: dc/dt = r, with initial concentration of C as 0 moles/L∴ dc/dt = kab

Substituting r = k(a)(b) in the equation, we get dc/dt = kabdc/db = kab*dt Differentiating both sides, we get, ln(C) = kab*t + C where C is a constant, ln(C) = ln(a^2) = 2ln(a) = C When a = b, the concentration of C will be maximum at t = (1/k)(ln(a)).

Thus the concentration of C as a function of time (when a = b) is given by C = a^2 * (1-t^2/2)If [C] = a after 20 seconds, then using the equation, we get a = a^2 * (1 - 20^2 * k^2/2)Therefore, 1 = a * (1 - 200k^2) Solving this equation for k, we get, k = ± sqrt[(1-a)/200a^2] For the positive value of k, the concentration of C as a function of time is given by C = a^2 * (1-t^2/400(1-a)).

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The height, in meters, where the pumpkin lands on the hill is 4.9 meters.The equation for the height of the hill is y = 0.9x.

This equation can be rearranged to solve for x, giving x = y/0.9. The equation for the height of the pumpkin is y = -0.1x² + 4.9x. Substituting the x value from the previous equation into the equation for the height of the pumpkin gives y = -0.1(y/0.9)² + 4.9(y/0.9). Simplifying this equation gives y = 4.9, which is the height, in meters, where the pumpkin lands on the hill.

The equation for the height of the hill is y = 0.9x, which describes the incline of the hill. This equation can be rearranged to solve for x, giving x = y/0.9. This equation can then be used to substitute into the equation for the height of the pumpkin, which is y = -0.1x² + 4.9x. When the x value from the previous equation is substituted into the equation for the height of the pumpkin, the equation simplifies to y = -0.1(y/0.9)² + 4.9(y/0.9). Simplifying further gives y = 4.9, which is the height, in meters, where the pumpkin lands on the hill. This can be verified by substituting 4.9 for y in the equation for the height of the hill, which gives x = 4.9/0.9 = 5.4. This value can be substituted into the equation for the height of the pumpkin, which gives y = -0.1(5.4)² + 4.9(5.4) = 4.9, verifying the result.

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Absolutely, Jada's response is right. A square is a quadrilateral with four equal-length sides. A quadrilateral is a square if all four sides measure 5 cm.

Unfortunately, there is no alternative form Jada could have drawn that meets the requirement of all four sides measuring 5 cm. Every other quadrilateral with four equal-length sides is likewise a square. If Jada had drawn a quadrilateral with one or more sides of varying lengths, the specified criterion would not have been met. As a result, the only design Jada could have sketched that meets the requirement of having all four sides measure 5 cm is a square. It is worthwhile to investigate the properties of quadrilaterals and how they connect to the conditions presented in the problem. A quadrilateral is a four-sided polygon. Quadrilaterals come in a variety of shapes, including squares, rectangles, parallelograms, trapezoids, and kites. Certain quadrilaterals have unique qualities, such as opposing sides that are parallel or all angles that are right angles. The criterion in the provided problem is that all four sides of the quadrilateral measure 5 cm.

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The total percentage increase in the investor's stock account is 7.95% (rounded to the nearest tenth).

What is the percentage?

A percentage is a number or ratio expressed as a fraction of 100. It is often denoted using the percent sign, "%", although the abbreviations "pct.", "pct" and sometimes "pc" is also used. A percentage is a dimensionless number; it has no unit of measurement.

To calculate the total percentage increase in the investor's stock account, we first need to calculate the new values of the stocks in Company A and Company B after the increase.

The new value of the stock in Company A is:

[tex]4500 + (5 \times 4500) = $4725[/tex]

The new value of the stock in Company B is:

[tex]3900 + (11 \times 3900) = 4339[/tex]

The total value of the investor's stock account after the increase is:

$4725 + $4339 = $9064

To calculate the percentage increase in the investor's stock account, we need to find the difference between the new total value and the original total value, and then divide that difference by the original total value:

($9064 - $8400) / $8400 = 0.0795

We then multiply this decimal by 100 to get the percentage increase:

0.0795 x 100 = 7.95%

Therefore, the total percentage increase in the investor's stock account is 7.95% (rounded to the nearest tenth).

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If the screen door spring has a spring constant of 188 N/m, then the force it exert is 54.9 N .

The force exerted by the screen door spring can be calculated using Hooke's law,

The Hooke's Law states that the force exerted by a spring is directly proportional to its spring constant and the amount it is stretched.

The formula for "Hooke's-law" is ⇒ F = kx

Where F is = force exerted by spring, k is = spring constant, and x is = amount spring is stretched.

In this case , the spring constant(k) = 188 , the distance stretched(x) = 292m ;

Substituting the values,

We get,

⇒ F = (188 N/m)(0.292 m)

⇒ F = 54.896 N

⇒ F ≈ 54.9N

Therefore, The force exerted by the screen door spring is approximately 54.9 N.

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Therefore , the solution of the given problem of standard deviation comes out to be he average difference between the population mean and the sample mean is 6.

Variance is a measure of variation used in statistics. The average difference between the gathering and the mean is calculated using the photo of that figure. By comparing each number to the mean, it incorporates those data points into the calculations on their own, in contrast to many other legitimate measures of variable. Variations could result from deliberate errors, unrealistic expectations, or changing economic or commercial circumstances.

Here,

For a group of n = 4, the standard error of the mean (SEM) is as follows:

=> SEM = α/√(n)

=> 24/√(4) = 12

Therefore, for n = 4 scores drawn at random from the population, the average difference between the population mean and the sample mean is 12.

b. The SEM for a group of n = 9 is:

=> α/√(n) = 24/√(9)

=> 8; SEM = α

Therefore, for n = 9 scores drawn at random from the population, the average difference between the population mean and the sample mean is 8.

c. The SEM for a sample of 16 is as follows:

=> α / √(n) = 24 / √(16) = 6;

=>  SEM =α

Therefore, for n = 16 scores drawn at random from the population, the average difference between the population mean and the sample mean is 6.

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Answer:

-25

Step-by-step explanation:

simplification using BODMAS

[tex]-5 * 4 + -5[/tex]
-20 - 5
= -25

Find CD:

Let,

[tex]r_1[/tex] be a radius of Circle A

[tex]r_2[/tex] be a radius of Circle B

Given:

[tex]r=4cm.[/tex]

Circumference: [tex]2\pi r[/tex]

[tex]2\pi r_1=30[/tex]

[tex]r_1=\dfrac{15}{\pi }[/tex]

[tex]CD=D_1+D_2[/tex]

[tex]=2r_1+2rx_2[/tex]

[tex]=2\times(\dfrac{15}{\pi })+2\times4[/tex]

[tex]CD=17.55cm.[/tex]

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Answer:

It depends on the values of x and y. If x is positive and y is negative, then option A (x + y) would have a negative value. If y is greater than x, then option B (x - y) would have a negative value. If either x or y (or both) is negative, then option C (x*y) could have a negative value. Option D (x/y) could also have a negative value if x is negative and y is positive, or if both x and y are negative.

Answer:

Step-by-step explanation:

B because it has subtraction

Answer:

P(0,2), Q(3,5), R(3,0)

Step-by-step explanation: