1) We need 2 rolls of grass at a cost of 2 rolls x $400 per roll = $800. 2) Number of kids per square yard: 0.06 kids/ sqyrd. 3) The total cost for this playground would be $3170, which is within the budget of $4290.
How will you solve this question?To find the cost of fencing, we need to know the perimeter of the playground. Let's assume the playground is a rectangle with dimensions 100 feet by 75 feet. The perimeter is then 2(100 ft) + 2(75 ft) = 350 feet. This means we need 7 rolls of fencing (350 ft ÷ 50 ft per roll) at a cost of 7 rolls x $90 per roll = $630.To find the cost of laying grass, we need to know the area of the playground. The area of a rectangle with dimensions 100 feet by 75 feet is 100 ft x 75 ft = 7500 square feet. To convert to square yards, we divide by 9: 7500 sq ft ÷ 9 = 833.33 sq yd. This means we need 2 rolls of grass (833.33 sq yd ÷ 500 sq yd per roll) at a cost of 2 rolls x $400 per roll = $800.
The total cost of fencing and grass for this playground is $630 + $800 = $1430.
To find the number of kids per square yard, we need to know the area of the playground and the number of kids it can hold. Let's assume the playground can hold 50 kids and the dimensions are still 100 feet by 75 feet. We already know the area is 7500 square feet or 833.33 square yards. To find the number of kids per square yard, we divide the number of kids by the area: 50 kids ÷ 833.33 sq yd = 0.06 kids per sq yd.Let's assume the budget for Wintermeadow is three times the cost of Springfield's playground, so the budget is $4290 ($1430 x 3). We want to recommend a playground shape and size that can hold at least 3 times as many kids as Springfield's playground at the same density of kids per square yard.From part 2, we know that Springfield's playground can hold 50 kids in 7500 square feet or 833.33 square yards, which is a density of 0.06 kids per sq yd. To hold three times as many kids, the new playground should be able to hold 150 kids.
Let's assume we want to keep the same density of 0.06 kids per sq yd. To find the area needed for the new playground, we divide the number of kids by the density: 150 kids ÷ 0.06 kids per sq yd = 2500 sq yd.
There are many shapes and sizes that could have an area of 2500 sq yd. One option is a rectangle with dimensions 125 feet by 200 feet. The perimeter of this playground is 650 feet, which would require 13 rolls of fencing at a cost of $1170. The area of the playground is 2500 square yards, which would require 5 rolls of grass at a cost of $2000.
The total cost for this playground would be $3170, which is within the budget of $4290. It can hold at least 3 times as many kids as Springfield's playground, with the same density of 0.06 kids per sq yd.
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Answer:
1. It Should be $ 36039.60
2. Total = 432,00 ft / 3 = 14400/360= 40 kids
3. 443880 ft / 3 = 147960 / 360 = 411 kids
Step-by-step explanation:
The teacher tell me the answers
Please I need help with this question
Which are correct representations of the inequality –3(2x – 5) < 5(2 – x)? Select two options. x < 5 –6x – 5 < 10 – x –6x + 15 < 10 – 5x A number line from negative 3 to 3 in increments of 1. An open circle is at 5 and a bold line starts at 5 and is pointing to the right. A number line from negative 3 to 3 in increments of 1. An open circle is at negative 5 and a bold line starts at negative 5 and is pointing to the left.
The sοlutiοns tο the inequality are x values greater than 5.
A number line frοm negative 3 tο 3 in increments οf 1. An οpen circle is at 5 and a bοld line starts at 5 and is pοinting tο the right.
-6x - 5 < 10 - x and -6x + 15 < 10 - 5x are cοrrect representatiοns οf the inequality –3(2x – 5) < 5(2 – x).
Tο sοlve the inequality -3(2x - 5) < 5(2 - x), we can start by distributing the negative 3 and the pοsitive 5 οn the right side:
-6x + 15 < 10 - 5x
Then, we can simplify by mοving all the x terms tο οne side and all the cοnstant terms tο the οther side:
-x < -5
Finally, we can divide bοth sides by -1, remembering tο reverse the inequality sign:
x > 5
Therefοre, the sοlutiοns tο the inequality are x values greater than 5. The representatiοns οf this sοlutiοn οn a number line are:
A number line frοm negative 3 tο 3 in increments οf 1. An οpen circle is at 5 and a bοld line starts at 5 and is pοinting tο the right.
A number line frοm negative 3 tο 3 in increments οf 1. An οpen circle is at negative 5 and a bοld line starts at negative 5 and is pοinting tο the left.
Hοwever, οnly the first representatiοn is cοrrect, since the secοnd representatiοn shοws the sοlutiοns tο x < -5, which is the οppοsite inequality tο the οne we fοund.
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A quality control inspector randomly selects 5 calculators to inspect from 22 calculators. How many ways could the inspector select?
Answer:
22 cakculator is write answer
Which transformations would take Figure A to Figure B?
can someone please help me
Find the area of each shaded region.
Round the answer to two decimal places.
please show work
Answer:
7) S=6.28 yd A=12.57 [tex]yd^{2}[/tex]
8) S=99.48 ft A=945.1 [tex]ft^{2}[/tex]
9) S=21.99 in A=43.98 [tex]in^{2}[/tex]
Step-by-step explanation:
7)
S=r θ
S=4([tex]\frac{90\pi }{180}[/tex])........................................plug in values
S=4([tex]\frac{\pi }{2}[/tex])...........................................simplify
S=6.28 yd...................................solve and round
A=[tex]\frac{1}{2}[/tex]([tex]r^{2}[/tex]) θ
A=[tex]\frac{1}{2}[/tex]([tex]4^{2}[/tex])([tex]\frac{90\pi }{180}[/tex]) ....................................plug in values
A=[tex]\frac{1}{2}[/tex](16)([tex]\frac{\pi }{2}[/tex]) .....................................simplify
A=12.57 [tex]yd^{2}[/tex]...................................solve and round.
8)
S=r θ
S=19([tex]\frac{300\pi }{180}[/tex]).........................................plug in values
S=19([tex]\frac{5\pi }{3}[/tex]).............................................simplify
S=99.48 ft........................................solve and round
A=[tex]\frac{1}{2}[/tex]([tex]r^{2}[/tex]) θ
A=[tex]\frac{1}{2}[/tex]([tex]19^{2}[/tex])([tex]\frac{300\pi }{180}[/tex]) ....................................plug in values
A=[tex]\frac{1}{2}[/tex](361)([tex]\frac{5\pi }{3}[/tex]) .....................................simplify
A=945.1 [tex]ft^{2}[/tex].......................................solve and round.
9)
S=r θ
S=4([tex]\frac{315\pi }{180}[/tex]) ............................................plug in values
S= 4( [tex]\frac{7\pi }{4}[/tex])..............................................simplify
S=21.99 in..........................................solve and round
A=[tex]\frac{1}{2}[/tex]([tex]r^{2}[/tex])θ
A=[tex]\frac{1}{2}[/tex]([tex]4^{2}[/tex])([tex]\frac{315\pi }{180}[/tex]) ....................................plug in values
A=[tex]\frac{1}{2}[/tex](16)( [tex]\frac{7\pi }{4}[/tex])......................................simplify
A=43.98 [tex]in^{2}[/tex]....................................solve and round.
How many times will Sarah have to deposit $300 every six months into her account at 4.5%
compounded semi-annually to save $10 000.00?
25.15
20.82
15.75
1458.90
With 4.5% compounded semi-annually, Sarah will need to make installments for roughly 20.82 years in order to save $10,000. Hence, 20.82 is the answer.
Is every two years or semiannually?
Simply said, semiannual refers to events that occur twice a year. A couple might commemorate their nuptials each two years, a corporation might hold workplace celebrations each two years, as well as a family might go on vacation each two years. Every two years, something that happens twice a year does.
We can utilize the calculation again for future value of an annuity to resolve this issue:
FV = P × ((1 + r/n) - 1) / (r/n)
Where:
FV = Future value
P = Periodic payment
r = Annual interest rate
n = Compounding cycles per year, number
t = Number of years
In this instance, Sarah plans to deposit $300 each six months in order to save $10,000. She will so be required to make two payments each year. P thus equals $300, n equals 2, r equals 0.045 (decimalized 4.5%), and FV equals $10,000. The number of years, t, needs to be solved for.
$10,000 = $300 × ((1 + 0.045/2) - 1) / (0.045/2)
When we simplify this equation, we obtain:
20 = (1 + 0.0225) - 1
21 = (1 + 0.0225)
Using both sides' natural logarithms:
ln(21) = ln((1 + 0.0225))
ln(21) = 2×t × ln(1 + 0.0225)
t = ln(21) / (2 × ln(1 + 0.0225))
t = 20.82
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For the numbers 683 and 2329 round each number to the nearest hundred, then find the product of the rounded numbers
Answer:
1,610,000
Step-by-step explanation:
To round to the nearest hundred, we need to go to the hundreds place. In 683, we can round this to the nearest hundred by using this rule:
5 or more, let it sore
4 or less, let it rest
683 rounded to the nearest hundred is 700
2329 rounded to the nearest hundred is 2300
Now we just need to multiply both of them to get the product
[tex]2300\times 700=1,610,000[/tex]
Latasha and Nathan both leave the coffee shop at the same time, but in opposite directions. If Nathan travels 8mph faster than Latasha and after 9 hours they are 288 miles apart , how fast is each traveling
Answer:
Let's use the formula:
distance = rate × time
Let's assume Latasha's rate of travel as "r". Then, Nathan's rate of travel would be "r + 8".
For Latasha:
distance = r × 9
For Nathan:
distance = (r + 8) × 9
According to the problem, the combined distance they traveled is 288 miles. So:
r × 9 + (r + 8) × 9 = 288
Simplifying the equation:
18r + 72 = 288
18r = 216
r = 12
So, Latasha's rate of travel is 12 mph, and Nathan's rate of travel is 20 mph (12 + 8).
Therefore, Latasha is traveling at 12 mph and Nathan is traveling at 20 mph.
what does 2(-3+5) + 7× (-4) + (-1) equal?
Answer:
-25
Step-by-step explanation:
= 2*(2) - 28 - 1
= 4 - 29
= -25
Given:-
[tex] \tt \: 2(- 3+5 ) + 7× (-4) + (-1) = ?[/tex][tex] \: [/tex]
Solution:-
[tex] \tt \: 2(- 3+5 ) + 7× (-4) + (-1) [/tex][tex] \: [/tex]
[tex] \tt \: 2( 2 ) - 28 - 1[/tex][tex] \: [/tex]
[tex] \tt \: 4 - 29[/tex][tex] \: [/tex]
[tex] \boxed{ \: \tt \pink{-25 }\: \: } [/tex][tex] \: [/tex]
━━━━━━━━━━━━━━━━━━━━━━━
hope it helps! :)
Note: Enter your answer and show all the steps that you use to solve this problem in the space provided.
The expression for the area of the shaded region in its simplest form is x² + 23x + 49.
What is the area of the rectangle?
To find the area of a rectangle, we multiply the length of the rectangle by the width of the rectangle.
The shaded area is the difference of the areas of the rectangle and the square.
Rectangle:
A₁ = (x + 10)(2x + 5) = 2x² + 5x + 20x + 50 = 2x² + 25x + 50
Square:
A₂ = (x + 1)² = x² + 2x + 1
Shaded region:
A₁ - A₂ = 2x² + 25x + 50 - (x² + 2x + 1)
= 2x² + 25x + 50 - x² - 2x - 1
= x² + 23x + 49
Hence, the expression for the area of the shaded region in its simplest form is x² + 23x + 49.
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Complete question:
Enter your answer and show all the steps that you use to solve this problem in the space provided.
A rectangle is shown with length x plus 10 and width 2 x plus 5. The inside of the rectangle is shaded other than an unshaded square with length x plus 1 and width x plus 1.
Write an expression for the area of the shaded region in its simplest form. Show all of your steps.
A rectangular pyramid has a height of 5 units and a volume of 50 units3. Shannon states that a rectangular prism with the same base area and height has a volume that is three times the size of the given rectangular pyramid. Which statement explains whether Shannon is correct?
A rectangular prism in which BA = 10 and h = 5 has a volume of 150 units3; therefore, Shannon is correct
A rectangular prism in which BA = 30 and h = 5 has a volume of 150 units3; therefore, Shannon is correct
A rectangular prism in which BA = 10 and h = 5 has a volume of 50 units3; therefore, Shannon is incorrect
A rectangular prism in which BA = 30 and h = 5 has a volume of 50 units3; therefore, Shannon is incorrect
Answer:
B (A rectangular prism in which BA = 30 and h = 5 has a volume of 150 units3; therefore, Shannon is correct)
Step-by-step explanation:
I took the test!
The solution is,: A rectangular prism in which BA = 30 and h = 5 has a volume of 150 units^3; therefore, Shannon is correct
What is volume?In mathematics, volume is the space taken by an object. Volume is a measure of three-dimensional space. It is often quantified numerically using SI derived units or by various imperial or US customary units. The definition of length is interrelated with volume.
here, we have,
step 1
Find the area of the base of the rectangular pyramid
we know that:
The volume of the rectangular pyramid is equal to:
V = 1/3 * bh
where
B is the area of the base
H is the height of the pyramid
we have
V= 50
h = 5
substitute and solve for B
we get,
b= 30
step 2
Find the volume of the rectangular prism with the same base area and height
we know that
The volume of the rectangular prism is equal to
V = bh
we have
b = 30
h = 5
substitute
V = 30 * 5 = 150 unit^3
therefore
The rectangular prism has a volume that is three times the size of the given rectangular pyramid. Shannon is correct
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Given GH = 3x - 2, HI = 7x - 4, 2
and GI = 8x + 10, find x
The value of x is 8 when GH is 3x-2, HI is 7x-4 and GI is 8x+10. It forms a straight line.
What is segment addition?Segment addition is a concept in geometry that states that given three collinear points A, B, and C, with B between A and C, the length of AB added to the length of BC will give the length of AC. This can be expressed algebraically as:
AB + BC = AC
According to question:We can use the fact that GH + HI = GI (by the segment addition postulate) and substitute the given expressions to get:
(3x - 2) + (7x - 4) = 8x + 10
Simplifying the left side by combining like terms, we get:
10x - 6 = 8x + 10
Subtracting 8x from both sides, we get:
2x - 6 = 10
Adding 6 to both sides, we get:
2x = 16
Dividing by 2, we get:
x = 8
Therefore, x = 8.
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I will mark you brainiest!
Given that QRVTSU is a regular hexagon, what are the lengths of QR and ST ?
A) 37
B) 28
C) 14
D) 10
Answer:
QR & ST = 37
Step-by-step explanation:
Because this is a regular hexagon, all the sides are equal.
Thus, since the length of QR = the length of ST, we can set the equations for both sides equal to each other and solve for y:
[tex]3y+19=6y+1\\3y+18=6y\\18=3y\\6=y[/tex]
Now, we can plug in 6 for y into any of the two equations to find the length of both QR and ST:
[tex]QR=3(6)+19\\QR=18+19\\QR=37[/tex]
Harriet is cultivating a strain of bacteria in a petri dish. Currently, she has 103 bacteria in the dish. The bacteria divide every two hours such that the number of bacteria has doubled by the end of every second hour. How many bacteria will Harriet have in the dish at the end of 6 hours?
A.
1024
B.
103
6
C.
603
D.
103
8
Step-by-step explanation:
Since the number of bacteria in the petri dish doubles every two hours, after 2 hours, Harriet will have 103 x 2 = 206 bacteria.
After another 2 hours (i.e., 4 hours from the beginning), the number of bacteria will double again to become 206 x 2 = 412 bacteria.
After another 2 hours (i.e., 6 hours from the beginning), the number of bacteria will double once more to become 412 x 2 = 824 bacteria.
Therefore, Harriet will have 824 bacteria in the dish at the end of 6 hours. Answer: A. 1024 (rounded to the nearest whole number).
Determine the length of x in the triangle. Give your answer to two decimal places. Show the steps, please.
Answer:
35.09 units
Step-by-step explanation:
This is a right-angled triangle where:
Hypotenuse = x units
With respect to angle 20°:
Opposite = 12 units
Use trigonometric function sinФ to solve for x:
sinФ = [tex]\frac{Opposite}{Hypotenuse}[/tex]
∴sin20° = [tex]\frac{12}{x}[/tex]
Cross-multiplication is applied:
[tex](x)(sin20) = 12[/tex]
x has to be isolated and made the subject of the equation:
∴[tex]x = \frac{12}{sin20}[/tex]
x = 35.09 units (Rounded to 2 decimal places)
Answer:
The length of x is 35.09 units to two decimal places.
Step-by-step explanation:
In the given right triangle, we have been given the length of the side opposite the angle and need to find the length of the hypotenuse.
To find the value of x, use the sine trigonometric ratio.
[tex]\boxed{\begin{minipage}{9 cm}\underline{Sine trigonometric ratio} \\\\$\sf \sin(\theta)=\dfrac{O}{H}$\\\\where:\\ \phantom{ww}$\bullet$ $\theta$ is the angle. \\ \phantom{ww}$\bullet$ $\sf O$ is the side opposite the angle. \\\phantom{ww}$\bullet$ $\sf H$ is the hypotenuse (the side opposite the right angle). \\\end{minipage}}[/tex]
Substitute θ = 20°, O = 12 and H = x into the ratio and solve for x:
[tex]\implies \sin 20^{\circ}=\dfrac{12}{x}[/tex]
[tex]\implies x=\dfrac{12}{\sin 20^{\circ}}[/tex]
[tex]\implies x=35.085652...[/tex]
[tex]\implies x=35.09\; \sf (2\;d.p.)[/tex]
Therefore, the length of x is 35.09 units to two decimal places.
I want you to help me solve the variable equations of questions 3
Answer:
[tex]\huge\boxed{\sf x = -24}[/tex]
Step-by-step explanation:
Given equation:[tex]\displaystyle -\frac{1}{2} x - 4 =8\\\\Add \ 4 \ to \ both \ sides\\\\-\frac{1}{2} x = 8+4\\\\-\frac{1}{2} x = 12\\\\Multiply \ both \ sides \ by \ -2\\\\-\frac{1}{2} x \times \ -2 = 12 \times -2\\\\\boxed{x = -24}\\\\\rule[225]{225}{2}[/tex]
Answer:
[tex]\boxed{\mathtt{1) \ x=4}}[/tex]
[tex]\boxed{\mathtt{2) \ x=2}}[/tex]
[tex]\boxed{\mathtt{3) \ x=-24}}[/tex]
Step-by-step explanation:
[tex]\textsf{For these problems, we are asked to solve for x in each equation.}[/tex]
[tex]\textsf{We should use similar steps for each of them.}[/tex]
[tex]\large\underline{\textsf{For Number 1:}}[/tex]
[tex]\textsf{We should first begin by adding 2 to both sides of the equation.}[/tex]
[tex]\mathtt{8x=32}[/tex]
[tex]\textsf{Now, divide by 8.}[/tex]
[tex]\boxed{\mathtt{1) \ x=4}}[/tex]
[tex]\large\underline{\textsf{For Number 2:}}[/tex]
[tex]\textsf{Let's begin by subtracting 5 from both sides of the equation.}[/tex]
[tex]\mathtt{-x=-2}[/tex]
[tex]\textsf{Now, divide by -1.}[/tex]
[tex]\boxed{\mathtt{2) \ x=2}}[/tex]
[tex]\large\underline{\textsf{For Number 3:}}[/tex]
[tex]\textsf{Beginning Number 3, let's multiply by -2 to both sides of the equation.}[/tex]
[tex]\mathtt{x+8=-16}[/tex]
[tex]\textsf{Now, subtract 8 from both sides of the equation.}[/tex]
[tex]\boxed{\mathtt{3) \ x=-24}}[/tex]
The price of an item has dropped to $44 today. Yesterday it was $80. Find the percentage decrease
Answer:
To find the percentage decrease, we need to find the difference between the original price and the new price, divide that difference by the original price, and then multiply by 100 to get the percentage.
The difference between the original price and the new price is:
80 - 44 = 36
To find the percentage decrease, we divide this difference by the original price:
36 / 80 = 0.45
Finally, we multiply by 100 to get the percentage:
0.45 * 100 = 45%
Therefore, the percentage decrease from $80 to $44 is 45%.
Answer: The percentage decrease is 45%.
Step-by-step explanation:
Percentage decrease = [tex](\frac{Oringinal Value-NewValue}{Oringinal Value} )*100[/tex]
= [tex](\frac{80-44}{80} )*100[/tex]
= 45%
if you put 25 ml of concerete in a glass how much water should be added
Answer:
50ml of water should be added
1.A trader sold some goods for #5184 and lost 4%. Find the total cost price of the goods?
Therefore, the total cost price of the goods is #5400.
What is cost price?Cost price refers to the amount of money that is spent by a business or individual to acquire or produce a product or service. It includes all the costs involved in the production or acquisition of the product or service, such as raw materials, labor costs, transportation costs, and other expenses. The cost price is usually used as a starting point for calculating the selling price of a product or service and is an important factor in determining the profitability of a business.
by the question.
Let's assume the cost price of the goods to be "x".
According to the problem, the trader sold the goods at a price of #5184 and incurred a loss of 4%.
we know that,
selling price = cost price - loss
Substituting the given values in the above formula, we get:
#5184 = x - 0.04x
Simplifying the equation, we get:
#5184 = 0.96x
Dividing both sides by 0.96, we get:
x = #5400
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Divide 1/20 divide by 5 enter your answer in the box as a fraction in simplest form
Answer:
honestly don't know but you got this bro {=•=}
Which statements are true? Select each correct answer. Responses 15m3−6m=3m(5m2−6m) 15 m cubed minus 6 m equals 3 m left parenthesis 5 m squared minus 6 m right parenthesis 40m6−4=4(10m6−1) 40 m begn power 6 end power minus 4 equals 4 left parenthesis 10 begin power 6 end power minus 1 right parenthesis 32m4+12m3=4m3(8m+3) 32 m begin power 4 end power plus 12 m cubed equals 4 m cubed left parenthesis 8 m plus 3 right parenthesis 6m2+18m=6m2(1+3m)
The true statement are:
A. 15m3-6m=3m(5m2-6m),
B. 40m6-4=4(10m6-1),
C. 6m2+18m=6m2(1+3m),
What are the true statement?15m3-6m=3m(5m2-6m) - This is true. Factoring out 3m from the terms on the left side gives 3m(5m2 - 2), which matches the right side.40m6-4=4(10m6-1) - This is true. Distributing 4 on the right side gives 4(10m6) - 4, which simplifies to the left side.6m2+18m=6m2(1+3m) - This is true. Factoring out 6m2 from the terms on the left side gives 6m2(1 + 3m), which matches the right side.32m4+12m3(8m+3) - This is not an equation or inequality, so it cannot be true or false.Therefore the correct option is A, B, C.
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The correct question is:
Which statements are true
15m3-6m=3m(5m2-6m),
40m6-4=4(10m6-1),
6m2+18m=6m2(1+3m),
32m4+12m3(8m+3)
Please help will mark Brainly
Answer:
[tex]\mathrm{D.\:\:\:f(x) = 2x^2 - 2x - 4; A = 8}[/tex]
Step-by-step explanation:
The formula for the area of a rectangle is A = l x w, where A is the area, l is the length, and w is the width. In this case, the length is 2x - 4 units and the width is x + 1 units. Therefore, the function that models the area of the rectangle is:
f(x) = (2x - 4)(x + 1)
f(x) = 2x^2 - 2x - 4
Therefore, option D is the correct answer.
To find the area when x = 3, we substitute x = 3 into the function:
f(3) = 2(3)^2 - 2(3) - 4
f(3) = 18 - 6 - 4
f(3) = 8
Therefore, when x = 3, the area of the rectangle is 8 square units.
Drag and drop 3 coordinates that satisfy the system above
Y<-2x + 4
2x-4y ≥ 3
The three coordinates that satisfy the system of inequalities include the following:
(0, -2)
(-7, - 5)
(-2, -8).
What is an ordered pair?In Mathematics, an ordered pair is sometimes referred to as a coordinate and it can be defined as a pair of two (2) elements or data points that are commonly written in a fixed order within parentheses as (x, y), which represents the x-coordinate (abscissa) and the y-coordinate (ordinate) on the coordinate plane of any graph.
By critically observing the graph of the given system of inequalities y < -2x + 4 and 2x - 4y ≥ 3, the three required solutions that satisfies it include following;
Ordered pair = (0, -2).
Ordered pair = (-7, - 5).
Ordered pair = (-2, -8).
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The following scenario represents a proportional relationship.
John's last paycheck was $450 for 40 hours of work.
What is the constant of proportionality?
Enter your answer in the box.
We can say that after answering the offered question Therefore, the proportionality constant of proportionality in this scenario is 11.25.
what is proportionality?Proportionate relationships are those that have the same ratio every time. For example, the average number of apples per tree defines how many trees are in an orchard and how many apples are in an apple harvest. Proportional refers to a linear relationship between two numbers or variables in mathematics. When the first quantity doubles, the second quantity doubles as well. When one of the variables decreases to 1/100th of its previous value, the other falls as well. When two quantities are proportional, it means that when one rises, the other rises as well, and the ratio between the two remains constant at all values. The diameter and circumference of a circle serve as an example.
In this case, we may use the following formula to calculate the proportionality constant:
proportionality constant = output/input
where the output is John's pay and the input is the number of hours he worked.
As a result, the proportionality constant is:
Paycheck/hours worked = proportionality constant
proportionality constant = 450/40
proportionality constant = 11.25
As a result, the proportionality constant in this scenario is 11.25.
In this case, we may use the following formula to calculate the proportionality constant:
proportionality constant = output/input
where the output is John's pay and the input is the number of hours he worked.
As a result, the proportionality constant is:
Paycheck/hours worked = proportionality constant
proportionality constant = 450/40
proportionality constant = 11.25
Therefore, the constant of proportionality in this scenario is 11.25.
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15. Many people swimming in a pool experience pain in their ears if they dive to the
bottom. Why is this?
A. Pressure increases as the depth of the water column above them increases.
B. The area of the pool is wider where it's deeper.
C. Pressure decreases as the depth of the water column above them increases.
D. The vapor pressure at the surface is removed.
Answer:
The answer is Ahope this helps
Lost-time accidents occur in a company at a mean rate of 0.4 per day. What is the probability that the number of lost-time accidents occurring over a period of 9 days will be at least 4 ? Round your answer to four decimal places.
The prοbability οf that the number οf lοst-time accidents οccurring οver a periοd οf 9 days will be at least 4 is 0.3975.
What is prοbability?Prοbability is a way οf calculating hοw likely sοmething is tο happen. It is difficult tο prοvide a cοmplete predictiοn fοr many events. Using it, we can οnly fοrecast the prοbability, οr likelihοοd, οf an event οccurring. The prοbability might be between 0 and 1, where 0 denοtes an impοssibility and 1 denοtes a certainty.
We can use here Pοisson distribution with λ=0.4 * 8=3.2
[tex]P[X\geq 4]=1-P[X < 4][/tex]
[tex]=1-{P[X=0] + P[X=1] + P[X=2] +P[X=3] =1-{0.0408+ 0.1304+ 0.2087 + 0.2226} =0.3975[/tex]
Where,
[tex]P[X=0]=\frac{e^{-3.2}(3.2)^0}{0!} = 0.0408[/tex]
[tex]P[X=1]=\frac{e^{-3.2}(3.2)^1}{1!} = 0.1304[/tex]
[tex]P[X=2]=\frac{e^{-3.2}(3.2)^2}{2!} = 0.2087[/tex]
[tex]P[X=3]=\frac{e^{-3.2}(3.2)^3}{3!} = 0.2226[/tex]
Hence the prοbability of that the number of lost-time accidents οccurring over a period of 9 days will be at least 4 is 0.3975.
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5. Find the time in which the loan of N3,900 at the rate of 5% yields N585=
6 What time will the simple interest N70,000 at the rate of 7% be used
for a loan of N20,000.00=
7.If N300.00 amount to N390 at the rate of 3%. Find the time.=
8.The simple interest on N5600.00 in 1 year is N80.00, find the rate percent per annum=
9.What year will N5100 yield an interest of N170.00 at the rate of 2 1/2 per annum=
10.What rate per annum will N4,600 yield an interest of N230.00 for 2 years=
11. What time will N8100 yield an interest of N729 at the rate of 9% per annum=
12.Report from the bank says the interest on N2300 is N23.00 for 2 years find the rate of interest per annum.=
Answer:
5. To find the time in which the loan of N3,900 at the rate of 5% yields N585, we can use the formula for simple interest:
I = P * r * t
where I is the interest, P is the principal (the amount borrowed), r is the interest rate (as a decimal), and t is the time (in years).
Plugging in the given values, we get:
585 = 3900 * 0.05 * t
Solving for t, we get:
t = 3 years
Therefore, it will take 3 years for the loan to yield N585 in interest.
6. To find the time it will take for the simple interest on N70,000 at the rate of 7% to be N20,000, we can again use the formula for simple interest:
I = P * r * t
Plugging in the given values, we get:
20000 = 70000 * 0.07 * t
Solving for t, we get:
t = 4 years
Therefore, it will take 4 years for the simple interest on N70,000 at the rate of 7% to be N20,000.
7. To find the time it takes for N300 to amount to N390 at the rate of 3%, we can use the formula for compound interest:
A = P * (1 + r/n)^(n*t)
where A is the final amount, P is the principal (the initial amount), r is the interest rate (as a decimal), n is the number of times the interest is compounded per year, and t is the time (in years).
Plugging in the given values, we get:
390 = 300 * (1 + 0.03/1)^(1*t)
Simplifying, we get:
1.3^t = 1.3
Taking the logarithm of both sides, we get:
t = log(1.3) / log(1.3)
t ≈ 1.82
Therefore, it takes approximately 1.82 years for N300 to amount to N390 at the rate of 3%.
8. To find the rate percent per annum for a simple interest of N80 on N5600 in 1 year, we can use the formula for simple interest:
I = P * r * t
Plugging in the given values, we get:
80 = 5600 * r * 1
Solving for r, we get:
r = 0.0143 or 1.43%
Therefore, the rate percent per annum is 1.43%.
9. To find the year in which N5100 will yield an interest of N170 at the rate of 2 1/2 per annum, we can use the formula for simple interest:
I = P * r * t
Plugging in the given values, we get:
170 = 5100 * 0.025 * t
Solving for t, we get:
t = 2/3 years
Since the question asks for the year, we need to add 2/3 years to the current year. Assuming the current year is 2021, we get:
2021 + 2/3 ≈ 2022.67
Therefore, N5100 will yield an interest of N170 at the rate of 2 1/2 per annum in the year 2022.
10. To find the rate per annum at which N4,600 will yield an interest of N230 for 2 years, we can again use the formula for simple interest:
I = P * r * t
Plugging in the given values, we get:
230 = 4600 * r * 2
Solving for r, we get:
r = 0.025 or 2.5%
Therefore, the rate per annum is 2.5%.
11. To find the time it takes for N8100 to yield an interest of N729 at the rate of 9% per annum, we can use the formula for simple interest:
I = P * r * t
Plugging in the given values, we get:
729 = 8100 * 0.09 * t
Solving for t, we get:
t = 1 year
Therefore, it takes 1 year for N8100 to yield an interest of N729 at the rate of 9% per annum.
12. To find the rate of interest per annum for an interest of N23 on N2300 for 2 years, we can use the formula for simple interest:
I = P * r * t
Plugging in the given values, we get:
23 = 2300 * r * 2
Solving for r, we get:
r = 0.005 or 0.5%
Therefore, the rate of interest per annum is 0.5%.
select all that are equal to 6^4 (6^5)
need help with This Math
Since line GF = line JK and < G = <J ; the minor arcs, the major arcs of the both circle are also similar and equal.
What is the major and minor arc of a circle?The minor arc of the given circle above can be defined as the part of the circle that is less than 180°. This is represented by <HGF in the first circle( with a red ink).
The major arc of the given circle above can be defined as the part of a circle that is greater than 180°. Thus is represented by <IJK in the second circle (with black ink).
Therefore in conclusion, there is a established similarity between the two circles since line GF = line JK and < G = <J, thus making their minor and major acre to be equal too.
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A steel rod of mass 25kg is melted down to create ball bearings of radius 4mm. One kilogram of this steel has a volume of 150[tex]cm^3[/tex]. How many ball bearings could be made from this steel rod?
Therefore, approximately 110,294 ball bearings of radius 4mm can be made from the steel rod.
What is volume?Volume is the amount of space that a three-dimensional object occupies. It is typically measured in cubic units, such as cubic meters, cubic centimeters, or cubic feet. The volume of an object can be calculated by multiplying its length, width, and height, or by using a specific formula for the shape of the object, such as the formula for the volume of a sphere, cylinder, or cone. Volume is an important concept in mathematics, physics, engineering, and many other fields, and it is used to describe the size and shape of objects, as well as their capacity, density, and other properties.
Here,
To solve this problem, we need to determine the total volume of the steel rod and then calculate how many ball bearings of radius 4mm can be made from this volume. First, we need to calculate the volume of the steel rod. We are given that one kilogram of the steel has a volume of 150 cm³. Therefore, the total volume of the steel rod is:
25 kg * 150 cm³/kg = 3750 cm³
Next, we need to calculate the volume of one ball bearing of radius 4mm. The formula for the volume of a sphere is:
V = (4/3)πr³
Substituting r = 4mm = 0.4cm, we get:
V = (4/3)π(0.4)³ = 0.034 cm³ (rounded to three decimal places)
To find the number of ball bearings that can be made from the steel rod, we divide the total volume of the steel rod by the volume of one ball bearing:
3750 cm³ / 0.034 cm³ ≈ 110,294
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