1) All of the following are homogeneous mixtures except.
* tomato soup.
* a sugar-water solution.
* gasoline.
* a salt-water solution.

Therefore, 0.00723 moles of Na3C6H5O7 can be produced if one tablet containing 0.0217 mol of NaHCO3 is dissolved.

The balanced chemical equation shows that 3 moles of NaHCO3 react with 1 mole of H2C6H6O7 to produce 1 mole of Na3C6H5O7. Therefore, the number of moles of Na3C6H5O7 produced is directly proportional to the number of moles of NaHCO3.

If one tablet containing 0.0217 mol of NaHCO3 is dissolved, then according to the balanced chemical equation, the number of moles of Na3C6H5O7 produced is:

(0.0217 mol NaHCO3) x (1 mol Na3C6H5O7 / 3 mol NaHCO3) = 0.00723 mol Na3C6H5O7

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The pH of the solution is 1.8. Option C is the right answer

First, we need to calculate the moles of LiOH and HNO3:

Moles of LiOH = 0.1 mol/L × 0.025 L = 0.0025 mol

Moles of HNO3 = 0.1 mol/L × 0.035 L = 0.0035 mol

Next, we need to determine which of the reactants will be limiting. LiOH and HNO3 react in a 1:1 stoichiometric ratio, so whichever reactant is present in the smaller amount will be limiting. In this case, LiOH is limiting because it has fewer moles than HNO3.

The balanced chemical equation for the reaction between LiOH and HNO3 is:

LiOH + HNO3 → LiNO3 + H2O

Since LiOH is limiting, all of it will react with HNO3. This means that all of the moles of HNO3 will be consumed, and there will be some excess LiOH remaining.

Moles of LiOH remaining = Moles of LiOH - Moles of HNO3 = 0.0025 mol - 0.0035 mol = -0.0010 mol

Note that the result is negative, which means that all of the HNO3 has been consumed, and there is still some LiOH remaining.

The concentration of LiOH in the final solution is:

[LiOH] = Moles of LiOH remaining / Total volume of solution = -0.0010 mol / (0.025 L + 0.035 L) = -0.010 mol/L

Again, the result is negative, which is not physically meaningful. This indicates that our assumption that LiOH is limiting is incorrect.

To correct this, we can assume that HNO3 is limiting and repeat the calculations. In this case, all of the HNO3 will react with LiOH, and there will be some excess HNO3 remaining.

Moles of HNO3 remaining = Moles of HNO3 - Moles of LiOH = 0.0035 mol - 0.0025 mol = 0.0010 mol

The concentration of HNO3 in the final solution is:

[HNO3] = Moles of HNO3 remaining / Total volume of solution = 0.0010 mol / (0.025 L + 0.035 L) = 0.01 mol/L

The balanced chemical equation for the reaction between HNO3 and LiOH is:

HNO3 + LiOH → LiNO3 + H2O

The stoichiometry of this reaction tells us that one mole of HNO3 reacts with one mole of LiOH to produce one mole of water. Therefore, the moles of water produced in the reaction are equal to the moles of HNO3 remaining:

Moles of water = 0.0010 mol

The volume of the final solution is:

Volume = 0.025 L + 0.035 L = 0.06 L

The molarity of the water in the final solution is:

Molarity of water = Moles of water / Volume of solution = 0.0010 mol / 0.06 L = 0.0167 mol/L

The pH of water is 7.0, and the pH of a solution is related to the concentration of H+ ions in the solution. Since water is neutral and does not contribute any H+ ions, the pH of the final solution is:

pH = 7.0 - log[H+] = 7.0 - log(0.0167) ≈ 1.8

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Determine the pH of the solution when 25ml of 0.1mLiOH is added to 35ml of 0.1m nitric acid

(A) 0.23

(B) 0.47

(C) 1.8

(D) 7.0

Answer:- NaBr and Cl2 are reactants .

The atoms/molecules/ions on RHS of the reaction which react to give products are called reactants.

So here Sodium bromide and chlorine are the reactants.

Option A is the correct choice.

Additional information:-

Law of conservation of Mass :-

According to this law , the mass of reactants is equal to the mass of the products . Take a chemical reaction ,

C + O2 ==> CO2

Now suppose that if 12g of carbon reacts with 16g of oxygen to form carbon dioxide, then what will be the mass of carbon dioxide? So by law of conservation of Mass we can say that mass of carbon dioxide will be equal to mass of the reactants that will be 12g + 16g = 28g

With this I am leaving a sample problem for you to solve,

Question: Consider the following reaction .

2C + O2 ==> 2CO

If the mass of carbon taken is 24g and the amount of carbon monoxide formed is 56g , find the amount of oxygen used in the reaction.

Answer:D. Yields

Explanation:

the area of one of the cat's paws is 4 square centimeters.

The weight of the cat is 4.0 kilograms, which is the force exerted on the scale by the cat's body. The weight per unit area on the scale due to the cat's paws is 0.25 kilograms per square centimeter.

Let A be the area of one of the cat's paws in square centimeters. The weight of the cat is supported by all four paws, so the total force exerted by the paws on the scale is:

force = weight = 4.0 kg

The force exerted by one paw is one-fourth of the total force:

force per paw = force / 4 = 4.0 kg / 4 = 1.0 kg

This force is distributed over the area of one paw, so we can write:

pressure = force per paw / A

where pressure is the weight per unit area, which is given as 0.25 kg/cm

Substituting the values and solving for A, we get:

0.25 kg/cm = 1.0 kg / A

A = 1.0 kg / 0.25 kg/cm = 4 cm

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Law of conservation of mass was crucial to progression of chemistry, as it helped scientists understand that substances did not disappear as result of reaction.

Law of conservation of mass explains that in chemical reaction mass is neither created nor destroyed.

To ensure Conservation of Mass is followed when mixing vinegar and baking soda in a bottle, you should make sure to do the following:

Weigh the bottle and its contents before adding vinegar and baking soda. This will give the initial mass of system.

Carefully measure the amounts of vinegar and baking soda you add to bottle.

Quickly and securely cap the bottle after adding baking soda to avoid any gas from escaping.

Weigh the bottle and its contents again after reaction has completed and the gas has stopped escaping. This will give the final mass of the system.

Compare the initial and final masses of system. They should be equal within experimental error.

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Answer:

0.9299 x [tex]10^-7[/tex] moles of [tex]OH^-[/tex]

Explanation:

[tex]OH^-[/tex]: 5.6 x 10^(15)  (brainly doesn't allow exponents greater than 9)

This number of particles can also be represented as 5.6e15.

'e' in this case means 'times 10 to the n' where n is the number that follows e.

Use stoichiometry to convert between different units.

[tex]\frac{5.6e15 particles}{1 sample} *\frac{1 mole}{6.022 e22 particles}= 0.9299 e -7 moles[/tex]

So in that sample of particles, there are 0.9299 x [tex]10^-7[/tex] moles of [tex]OH^-[/tex].

The name of the formula BF2 is : C.) Boron difluoride. The number of atoms of each element in a compound is known by chemical formula.

Chemical formula is an expression that shows elements in a compound and relative proportions of those elements. If only one atom of specific type is present, then no subscript is used. For atoms that have two or more of a specific type of atom present, then a subscript is written after the symbol for that atom.

Chemical formula contains the symbols of atoms of the elements present in the compound and also how many there are for each element in the form of subscripts.

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Factors that make the higher yield of crop possible are as follows: enough water for irrigation. access of organic manure of high quality . Fertilizers are a factor in the higher yields of high-cost farming.

Fertilizer is used to ensure good vegetative growth (leaves, branches and flowers), giving rise to healthy plants. They are artificially made but have a rapid response. Overuse of fertilisers can cause negative effects like loose soil fertility. There's a risk with any bond that the issuing company might not be able to meet its obligations.

However, the risks of default are typically higher for companies that issue high-yield bonds. Interest rate . If the octet is expanded with preferred number of bonds, formal charge = 0. The S-atom will gain two electrons in order to complete its octet.

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the volume of a 1.80 M solution of potassium chloride that is required to prepare 0.100 L of a 0.600 M solution is 0.0333 L, or 33.3 mL.

To determine the volume of a 1.80 M solution of potassium chloride that is required to prepare 0.100 L of a 0.600 M solution, we can use the formula:

M1V1 = M2V2

where M1 is the initial molarity, V1 is the initial volume, M2 is the final molarity, and V2 is the final volume.

Let's use this formula to solve the problem:

M1 = 1.80 M (since we are starting with a 1.80 M solution)

V1 = ? (what we are trying to find)

M2 = 0.600 M (since we want to prepare a 0.600 M solution)

V2 = 0.100 L (since we want to prepare 0.100 L of the final solution)

Substituting these values into the formula, we get:

1.80 M x V1 = 0.600 M x 0.100 L

Simplifying, we get:

V1 = (0.600 M x 0.100 L) / 1.80 M

V1 = 0.0333 L, or 33.3 mL

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Final volume of the gas would be 850.5 mL when the pressure is increased from 787.0 mmHg to 897.0 mmHg while keeping the temperature constant.

Boyle's Law explains that when temperature of given mass of confined gas is constant, then the product of its pressure and volume is also constant.

Given, P1 = 787.0 mmHg ; V1 = 970.0 mL; P2 = 897.0 mmHg

V2 = ?

As P1V1 = P2V2

V2 = P1V1/ P2

V2 = (787.0 mmHg x 970.0 mL) / 897.0 mmHg

V2 = 850.5 mL

Therefore, the final volume of the gas would be 850.5 mL when the pressure is increased from 787.0 mmHg to 897.0 mmHg while keeping the temperature constant.

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Enzymes speed up chemical reactions by lowering the activation energy needed for the reaction. The correct option is d.

Enzymes are biological molecules, typically proteins, that act as catalysts for chemical reactions. Catalysts are substances that can speed up a chemical reaction without being consumed in the process.

Enzymes work by lowering the activation energy needed for a chemical reaction to occur. Activation energy is the energy required to break the bonds of the reactants and initiate the chemical reaction. By lowering the activation energy, enzymes make it easier for reactants to come together and form products.

Enzymes achieve this by binding to the reactants, or substrates, and bringing them into close proximity to each other. This allows the substrates to interact more easily and lowers the energy barrier for the reaction to occur. Enzymes also stabilize the transition state of the reaction, further reducing the activation energy needed for the reaction to proceed.

Therefore, the correct answer is d) they lower the activation energy needed for the reaction.

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Answer:

burn

Explanation:

we burn fossil fuels, which releases carbon into the atmosphere

Answer:

polution

Explanation:

if the global of earth all polution in earth so,use electric bike

It stays much colder than traditional ice packs with the added bonus of no condesation building up on the inside of the travel box, like no water to make everything soggy &wet? However never take a huge breath of the contents as you open the box or container because inhaling trapped dry ice gas can be very harmful to your lungs! Simply let it mix with the air then carefully use gloves to move any dry ice away from your product and it should still be very frozen. We do this for long distance wedding cake delivery and I've never had one melt, 2 hours or more of driving to the events! Hope this helps!

There are approximately 6.031 x 10^23 molecules of O2 gas contained in 1357 mL of O2 gas at −14°C and 1437 torr.

we can use the ideal gas law:

PV = nRT

where, P = pressure of the gas in torr,

V = volume of the gas in liters,

n = number of moles of gas,

R = ideal gas constant (0.08206 L·atm/mol·K),

T = temperature of the gas in Kelvin.

the volume of the gas from milliliters (mL) to liters (L):

V = 1357 mL / 1000 mL/L

V = 1.357 L

Now to convert the temperature of the gas from Celsius (°C) to Kelvin (K):

T = -14°C + 273.15

T = 259.15 K

Substituting the given values:

(1437 torr) (1.357 L) = n (0.08206 L·atm/mol·K) (259.15 K)

n = (1437 torr x 1.357 L) / (0.08206 L·atm/mol·K x 259.15 K)

n = 1.0008 mol

the number of moles of O2 gas contained in 1357 mL of O2 gas at −14°C and 1437 torr is 1.0008 mol. To find the number of molecules,

we can use Avogadro's number:

1 mol of O2 gas contains 6.022 x 10^23 molecules

So, the number of molecules in 1.0008 mol of O2 gas is:

(1.0008 mol) x (6.022 x 10^23 molecules/mol) = 6.031 x 10^23 molecules

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The particles in suspension can be separated from heterogenous mixtures by passing the mixture through a filter. Option 1.

The particles in suspension can be separated from heterogeneous mixtures by passing the mixture through a filter.

A suspension is a heterogeneous mixture in which the particles are large enough to settle out over time and can be separated by physical means such as filtration.

Other options such as solution, colloid, and pure substances cannot be separated using a filter.

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Answer:  

Generally true.

Explanation:

As you go down the columns of the Periodic Table, the radius of the atom increases.

As you go across the Periodic Table (left to right), the radius of the atoms decrease.

Therefore, the second element on the table, Helium, has the smallest radius and element 87, Francium has the largest radius.

There are a few exception scattered throughout the table, such as the lanthanides and actinides, but generally speaking the radius increases as you travel from right to left and top to bottom.

Answer:

11.2823 grams of NH3 are produced
Explanation:

No. of moles for H2 = 22.3/22.4 = 0.9955 moles

By calculating number of moles produced of NH3, by using ratios:

N2 + 3H2 → 2NH3
1    :   3    :    2
? : 0.9955:  ?

part value = 0.9955/3 = 0.33183
No. of moles for NH3 = 2 * 0.33183 = 0.6637 moles

mass of produced NH3 (Molar mass = 17 g/mol) = 0.6637*17 = 11.2823 grams

Answer: Its the bottom one

Answer:

6 moles of H2O

Explanation:

We need the balanced equation for this reaction.

   C2H2 + O2 = CO2 + H2O

   2C2H2 + 5O2 = 2CO2 + 4H2O   [Balanced reaction]

The balanced reaction tells us that we should expect to obtain 4 moles of water, H2), for every 2 moles of C2H2 (ethylene).

That is a ratio:  (4 moles H2O)/(2 moles C2H2) or (2/1)(moles H2O/moles C2H4)

If we start with 3 moles of C2H4:

 (3 moles C2H4)*((2 moles H2O)/(1 moles C2H2)) = (2*3/1) moles H2O [the moles C2H2 cancel]

(2*3/1) moles H2O = 6 moles of H2O

T = 23 C + 273 = 296 K V(H2) = (1.7 mol*62360 mmHg/mol*K*296 /850 mmHg) = 36917.1 ml = 36.9 L if volume, per liters, of H2 gas is created at 26 C and 800 mmHg.

For instance, hydrogen is not harmful. Also, as hydrogen is that much lighter than the atmosphere, it evaporates quickly when it is discharged, enabling the fuel to disperse relatively quickly in the event of a leak. To ensure its safe use, some of hydrogen's features necessitate additional technical restrictions.

When two atoms of hydrogen join forces to form a hydrogen molecule, the result is a gas known as H2. Molecular hydrogen is another name for H2. There are two protons & two electrons in it. Hence, it has a neutral charge and is stable, making it the most prevalent type of hydrogen.

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Answer: The vapor pressure of pure water at 100°C is 760mm of Hg.

Explanation: We know tat 100 degree Celsius the water will convert into gas phase.  At boiling point the vapor pressure of any liquid is 1 atmosphere and if we boil the water at 100° Celsius  it means 1 atmosphere . So, 1 atmosphere = 760mm of Hg.

The red-colored blocks indicate non metals in the periodic table. Nonmetals are located on the right side of the periodic table, in the p-block.

Non-metals are composed of a variety of elements, such as carbon, nitrogen, oxygen, sulfur, phosphorus, and selenium. These elements are generally non-reactive, but some of them can form compounds with other elements. They are also used in various industries, such as the production of plastics, fertilizers, and explosives. Non-metals are divided into two categories: metalloids and non-metalloids. Nonmetals are characterized by their lack of luster and their low thermal conductivity.

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Answer:

33.67g

Explanation:

To calculate the mass of carbon monoxide, we can use the ideal gas law, which relates the pressure, volume, number of moles, and temperature of a gas:

PV = nRT

Where:

P = pressure

V = volume

n = number of moles

R = ideal gas constant

T = temperature

At STP (standard temperature and pressure), the pressure is 1 atm and the temperature is 273.15 K. The ideal gas constant is R = 0.08206 L atm/(mol K).

To find the number of moles of carbon monoxide in 29.3 L at STP, we can rearrange the ideal gas law to solve for n:

n = PV/(RT)

n = (1 atm)(29.3 L)/(0.08206 L atm/(mol K) * 273.15 K)

n = 1.203 mol

The molar mass of carbon monoxide (CO) is 28.01 g/mol. Therefore, the mass of 1.203 mol of CO is:

mass = n * molar mass

mass = 1.203 mol * 28.01 g/mol

mass = 33.67 g

Therefore, the mass of 29.3 L of carbon monoxide at STP is approximately 33.67 grams.

The positive difference between the

pressure in the balloon and the pressure of the troposphere is 0.048 kPa .

The balloon is being compressed by atmospheric force. The balloon is trying to inflate owing to gas pressure. The atmospheric pressure (outside pressure) in a fully inflated balloon is lower than the internal gas pressure.

An inflated balloon has a higher internal pressure than its surrounding air. Because the contracting force produced by the rubber's surface tension balances the expanding force caused by the pressure differential, the balloon remains stable.

Because to the air pressure on the walls, a balloon's surface feels tighter when it is inflated. The internal air pressure gives the balloon its shape. The balloon will therefore be more pressurized after being inflated.

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The grams of water needed to create a 4 molal solution with 9 moles of NaOH is 2250 grams.

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The final temperature of the water is 32.3°C.

The final temperature of the mixture is 53.3°C.

The heat lost by the copper is 4.19 kJ.

To determine the final temperature of the water, we can use the principle of conservation of energy. The total heat gained by the cooler water is equal to the total heat lost by the hotter water. The heat gained or lost by a substance can be calculated using the formula:

Q = mcΔT

where Q is the heat gained or lost, m is the mass of the substance, c is the specific heat capacity of the substance, and ΔT is the change in temperature.

Let's assume that the final temperature of the water is T. Then, the heat lost by the hotter water is:

Q1 = mcΔT = (100.0 g) x (4.184 J/g°C) x (73.7°C - T)

The heat gained by the cooler water is:

Q2 = mcΔT = (100.0 g) x (4.184 J/g°C) x (T - 27.8°C)

Since the total heat gained is equal to the total heat lost, we can equate Q1 and Q2:

(100.0 g) x (4.184 J/g°C) x (73.7°C - T) = (100.0 g) x (4.184 J/g°C) x (T - 27.8°C)

Simplifying the equation:

3134.4 - 41.84T = 418.4T - 11702.72

459.24T = 14837.12

T = 32.3°C

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The process that could result in the net movement of a substance into a cell, if the substance is more concentrated in the cell than in the surroundings is called osmosis.

Osmosis is a passive transport process where water molecules move from an area of high concentration to an area of low concentration through a selectively permeable membrane. In this process, a solute moves from a region of high concentration to a region of low concentration. A selectively permeable membrane is a type of biological membrane that allows certain molecules or ions to pass through it by diffusion and occasionally specialized "facilitated diffusion" and passive or active transport processes, while preventing other molecules or ions from passing through it. Therefore, the correct answer is the option C - Osmosis.

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