1. A bike takes 9.0 seconds to decelerate to a stop over a distance of 30 meters. How fast was the bike traveling before the biker started to decelerate?

Answer:

Pascal (Pa)

Explanation:

the si for pressure is the pascal pa equal to one newton per sqaure meter (N/m^2, or kgxm-^1xs-^2)

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The combination of the graphs that shows a free fall are A and C.

We know that motion has to do with the change of position with time. When an object is falling freely, the velocity of the object would remain constant because the velocity or the speed does not change.

Recall that when we throw objects down from a height, the objects would fall at the same rate irrespective of the masses of the objects. This can be understood to mean that the acceleration that acts on the objects is the same and does not change.

However, the distance that is covered by the object does change with tome and this can be seen from the graph as we have in the question. We can now see that the graph that has a flat speed time graph and a straight distance time graph can describe on object that is undergoing free fall.

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The mass of the car that was stuck is  1657 Kg.

We know that we have to use the laws of the conservation of the linear momentum here. It is known that the momentum before collision must be equal to the total momentum that we have after collision.

In this case, we have;

m1u1 + m2u2 = m1v1 + m2v2

m1  = mass of the truck

m2 = mass of the car

u1 and v1 = the initial and final velocities of the truck

u2 and v2 = initial and final velocities of the car

Again we are told that the two continue to move together hence v1 + v2 = v

m1u1 + m2u2 = (m1 + m2) v

(2900 * 11.0) + 0 = (2900  + m2) 7

31900 = 20300 + 7m2

31900 - 20300 = 7m2

m2 = 31900 - 20300 /7

m2 = 1657 Kg

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The net force acting on: 2.113 x 10⁵ N.

First, we need to calculate the deceleration of the driver by using 3rd equation of motion:  2as = Vf² - Vi²

where,

a = deceleration = ?

s = distance = 5 cm = 0.05 m

Vf = Final Velocity = 0 m/s

Vi = Initial Velocity = 18 m/s

Therefore,

2a(0.05 m) = (0 m/s)² - (18 m/s)²

a = (- 324 m²/s²)/0.1 m

a = - 3240 m/s²

where the negative sign represents a deceleration

From Newton's Second Law of Motion:

F = ma

F = (65 kg)(-3240 m/s²)

F = - 2.106 x 10⁵ N

So, the closest answer is:

F = 2.113 x 10⁵ N

In physics, a force is an effect that can change the motion of an object. A force can cause an object with mass to change speed, ie. accelerate A force can also be intuitively described  as a push or a pull. A force has both magnitude and direction, so it is a vector quantity.

When a body tends to change or change its state under the influence of an external cause, it is called a force. A body can also change its shape, size and direction when a force is applied. For example, kicking a ball, pulling and pushing a door.

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The main difference between the energy of moving water and the energy of stored water is that the energy of moving water has kinetic energy whereas the energy of water that is stored has potential energy.

Potential energy is defined as the stored energy in any object due to its position while on the other hand, while Kinetic energy is defined as the energy an object has due to its motion. The energy stored in the water molecules which is used for the movement of these molecules is called water potential. Stored water has potential energy but the kinetic energy is present only in the moving molecules of water.

So we can conclude that moving water has kinetic energy while on the other hand, the energy of water that is stored has potential energy.

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A car is driving with a constant velocity around a circular track. The track’s radius is 156.1 m, and the car returns to its starting position in

49.3 s the car’s centripetal acceleration is 0.327 m/sec².

Rate of change of velocity with respect to time is called acceleration.

when the magnitude of velocity is constant and direction is changing

than the acceleration is centripetal acceleration.  

Given that is question radius of track  is 156.1 m and  car returns to its starting position in 49.3 s.

Velocity of car = Circumference of Circle / total time

                        = 352.308/ 49.30

                 v     = 7.14 m/sec

Centripetal acceleration = v²/r

                                         = 51.06/156.1

                                         = 0.327 m/sec²

The car’s centripetal acceleration is  0.327 m/sec².

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Answer:

The answer is 61.45 °C

Explanation:

Clausius-Clapeyron equation:

P2= Normal pressure

T2= Normal boiling point

ln(p2/p1)=−(ΔHv/R)*(1/T2 − 1/T1)

ln(760/190) = –(31400/8.314)*[(1/T2) – (1/298)]

T2 = 334.6 K = 61.45 °C

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Answer:

a) Uniform rectilinear motion

b) 600 m

c) 20 m/s

Explanation:

a) average velocity is described as the change of position divided by the time of travel, so v= ∆x/∆t. This is a linear function (y = mx+ q) which is the same structure of the equation needed to calculate average velocity (x2= x1 + vt). If you do the ratio between a distance and the corresponding time you'll see that the average velocity is the same, which is typical of this kind of motion.

b) At the the time of 30 seconds the corresponding distance on the y axis is 600 m.

c) Again, v=∆x/∆t and we can rewrite is as v=x2-x1/t. If you take the same data we've used before you can write v= 600m-0/ 30s= 20 m/s. The average velocity is 20 m/s.

If we rearrange the circuit so that the inductor and capacitor were connected in series,the impedance would be  Decreased and the resonant frequency would be unchanged.

What is capacitor ?

Frequency is the rate at which something occurs over a particular period of time or in a given sample.

Sol-An LC circuit is made up of an inductor (L) and a capacitor (C). At the resonance condition of the LC circuit, the inductive reactance XL. becomes equal to the capacitive reactance Xc.

It is defined as-

XL= 2πfL

Xc= 1/2πfC

So when reactances are equal we have-

XL=Xc

2πfL= 1/2πfC

f^2=1/4π^2LC

f=1/2π√LC

The resonance condition is the same for both the parallel and series LC circuit, so the resonance frequency will not change.

The impedance of a parallel LC circuit is:

Z(w)= jL w^2-w^2•/w

In a series LC circuit, when w

, the impedance becomes equal to 0.

Therefore the impedance of a series LC circuit will decrease and the resonant frequency will remain the same.

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Satellite B's radius will be less than Satellite A's radius.

m = Satellite Mass

v = Satellite Velocity

r = Orbital radius of the satellite

Relating the gravitational and centripetal forces

mv^2/ r= GmM/r^2

v^2/r=GM/r^2

v^2=GM/r

v = sqrtGM/r

As can be shown, the mass of the satellite has no bearing on the relationship between velocity and radius.

This implies that the radius must shrink for v to increase

Here, vb>va

Therefore, satellite b's radius will be smaller than satellite a's radius.

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The magnitude of the force is equal to 100 newtons.

It's easy! You just need to divide the work by the displacement:

300 = F · 3

300 = 3F

300/3 = 3F/3

100 = F

F = 100

Here, F is the magnitude of force. The standard unit for force is newton (N). Recall that in physics, work is mathematically defined as W = F · x where W is work, F is force, and x is displacement. The standard unit for work is joule (J) and the standard unit for displacement is meter (m).

You are given that the work applied is equal to 300 joules and the displacement is equal to 3 meters. The force used to punch a box along the floor would then be 100 newtons.

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24.46 m/s is the speed of the arrow after passing through the target.

p=mv

Conservation of momentum: m1v1=m2v2

The target has a mometum of -(.3kg)(2.15m/s)

the arrow has a mometum of (.0225kg)(42.0m/s)

After impact the mometum of the target is 0 Ns since its velocity is zero.

After impact the velocity of the arrow can be determined with conservation of momentum calculations.

Δp(arrow)=-Δp(target)

m(arrow)v(arrow)i+m(target)v(target)i=m(arrow)v(arrow)f+m(target)v(target)f

(.0225kg)(42.0m/s)-(.3kg)(2.15m/s)=(.0225kg)vf(arrow)

the final velocity of the arrow should be equal to((.0225kg*42.0m/s)-(.3kg*2.15m/s))/.0225kg

v(arrow) final = 24.46 m/s

       m  is the mass of a body and v is the velocity  of that body, the impulse momentum  can be expressed as  p=m.v

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Answer:

b

Explanation:

For C scale  , water freezes at 0 and boils at 100 C

The hydrostatic pressure on the bottom of the tank is 197.083 kN.

Given,

Length of tank = 10 m

Width of tank = 8 m

height of tank = 4 m

density of kerosene = 820 kg/m³

depth of oil = 3.5 m

A. Hydrostatic pressure at the underside of the tank:

P = ρ g h

P = 820 x 9.81 x 3.5

P = 28154.7 Pa

B. Hydrostatic force at the underside of the tank:

F = P A

⇒A  = 10 x 8 = 80 meter²

⇒F = 28154.7 x 80

    = 2252.38 kN

C. Hydrostatic force at one edge:

Given,

Width = 8 m

depth = z

A = 4 y

dA = 4 dy

P = ρgh

P = ρgz = ρg(y-0.5)

F = P dA

F = ρg(y-0.5)(4dA)

F = 24.5 ρg

Hydrostatic force at one end = 24.5 x 820 x 9.81 = 197.083 kN.

The pressure exerted by a liquid thanks to gravity at any point in equilibrium. Hydrostatic pressure is proportional to the depth measured from the surface because the weight of the liquid increases when a downward force is applied. Hydrostatic pressure is the force produced by still or still water. this is often the constant force that water pressure exerts on underground walls.

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At the summit of the mountain, the mass is 60.18 kg, the weight is 600 N, and the mass is unaltered.

Let the mass on earth be m.

As we know:

Now, calculate as follows:

Therefore, at the summit of the mountain, the mass is 60.18 kg, the weight is 600 N, and the mass is unaltered.

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​

The correct answer is option A.

The rocky inner planets are different than the gaseous outer planets because heat from the growing sun allowed rock to mainly form close in.

In our solar system, the inner planets are rocky while the outer planets are in a gaseous state.

Rocky planets are also called terrestrial planets as their outer surface is solid and composed of rocks and metal.

They have large thick gaseous atmospheres which are abundant in gases such as nitrogen, carbon dioxide, and oxygen.

While the outer planets are giant balls of gases that orbit around the sun.

Unlike terrestrial planets, these gaseous planets do not have thick atmospheres and are 2x larger in size than the rocky inner planets.

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From the Law of conservation of energy, we know that the sum of the kinetic and potential energy of the rocket is the same at the surface of the Earth and at the maximum altitude. Nevertheless, the kinetic energy of the rocket when it is at the maximum altitude is 0:

The kinetic energy is given by:

On the other hand, the gravitational potential energy for big changes in altitude (comparable to the radius of the Earth) is given by the expression:

Where M is the mass of the Earth, m is the mass of the rocket, r is the distance from the center of the Earth to the rocket and G is the gravitational constant:

At the beggining of the movement, the value of r corresponds to the radius of the Earth:

At the end of the movement, the value of r corresponds to the radius of the Earth plus the maximum altitude h:

Substitute the expressions for U_1, K_1 and U_2 and simplify the equation by eliminating the factor m:

Isolate the term GM/(R_E+h):

Divide both sides by the factor GM:

Take the reciprocal to both sides of the equation:

Isolate h:

Substitute the values of each variable: R_E=6.37x10^6m, M=5.98x10^24kg, G=6.67x10^-11 N*m^2/kg^2, and v=9.0x10^-3 m/s:

Therefore, the maximum altitude reached by a rocket with an initial speed of 9.0x10^3m is:

The magnitude of the induced emf in the loop is 1mV.

The formula to be used is:

E = B (dA/dt)

B = magnetic of magnetic field parallel to the axis of loop = 0.5 T

dA/dt = rate of change of area of the loop = 20 cm²/s = 20 x 10⁻⁴ m²

θ = Angle of the magnetic field with the area vector = 0

E = emf induced in the loop

Now, plugging in the values we get:

E = B (dA/dt)

E = (0.5) (20 x 10⁻⁴ )

E = 10 x [tex]10^{-4}[/tex] volts

E = 1 mV

Therefore,  the magnitude of the induced emf in the loop is 1mV.

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The distance covered by the object is given as,

Plug in the known values,

Thus, the distance covered by the object is 81 m.

The freight train has a momentum of mv = (4.5 × 105 kg)(1.4 m/s) = 6.3 ×105 kg-m/s.

An automobile with a mass of 1800 kg would need to go at a speed of 6.3  × 105 kg-m/s ÷ 1800 kg = 350 m/s in order to have a momentum of the same magnitude. (Roughly 800 mph)

A moving body's amount of motion is referred to as momentum. It has units of kg m/s and is theoretically represented as p = m * v.

The momentum equation connects the total force exerted on a fluid element to its acceleration or rate of change of momentum and is a formulation of Newton's Second Law. You're certainly familiar with the formula F = ma, which links applied force and acceleration in solid mechanics analysis.

Momentum is the result of a particle's mass and velocity. Being a vector quantity, momentum possesses both magnitude and direction. According to Isaac Newton's second equation of motion, the force applied on a particle is equal to the time rate of change of momentum.

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The importance of the pressure t exerted via the string connecting the bins evaluate to the value f is T< f.

A force is a power that can trade the movement of an object. A force can encourage an item with mass to exchange its tempo, i.e., to boost up. stress can also be described intuitively as a push or a pull. A strain has both importance and path, making it a vector quantity.

considering both masses together

The acceleration of the system = a

a = f/m+m = f/2m

Now, considering one mass towards left m

T = ma

T = (f/2m)

m = f/2

T = f/2

T<f

Therefore, T must have a magnitude less than f.

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The amount of thermal energy inside a protostar increases with time, We will degree radiative power without delay and infer thermal energy from models: type will we infer from the law of conservation of energy

A protostar is a very younger big name that is nonetheless accumulating mass from its parent molecular cloud. The protostellar phase is the earliest one within the system of stellar evolution. for a low-mass superstar, it lasts about 500,000 years.

A protostar is formed as gravity starts offevolved to pull the gases collectively into a ball. This technique is referred to as accretion. As gravity pulls the gasses toward the center of the ball, gravitational strength begins to warmness them, inflicting the gasses to emit radiation. in the beginning, the radiation simply escapes into space.

Protostar is an early degree in the evolution of a celebrity that generally grows to the factor of beginning nuclear fusion and becoming a star through gathering mass. it's miles made from a contracting cloud of bloodless and dark interstellar medium (often hydrogen gas).

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The magnitude[tex]F_{P}[/tex]  of the force you need to exert on the crate to make it continue to slide along the floor with constant velocity is  437.5N.

The Normal Force (in a horizontal plane, it is comparable to the mass by gravity) and the Kinetic Coefficient of Friction must be multiplied in order to obtain the Friction Force, which must be used in order to solve this problem.

Given that the sentence does not specify the value of the coefficient of friction, I will ascribe a value of 0.5 between the crate and the ground. If a different value has been specified for this coefficient, the below equation will simply need to be changed to reflect it.

[tex]F_{P}[/tex] = µK N

µK = Friction coefficient

Normal Force is N.

Replacing,

[tex]F_{P}[/tex] = 0.5 × 875

[tex]F_{P}[/tex] = 437.5N.

Consequently, the crate is subject to a friction force of 437.5N.

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Complete question is "Suppose you have to move a heavy crate of weight 875 {\rm N} by sliding it along a horizontal concrete floor. You push the crate to the right with a horizontal force of magnitude 300 {\rm N}, but friction prevents the crate from sliding. Now assume that the crate is sliding along the floor with constant velocity. What is the magnitude F_p of the force you need to exert on the crate to make it continue to slide along the floor with constant velocity?"

option c is the correct answer

What is Spectroscopy ?

It is a common method used by astronomers to determine the composition of stars, planets, and other objects. Today, this process uses instruments with gratings that distribute the light from the object by wavelength. This spread of light is called the spectrum.

The science of spectroscopy is very difficult. From the spectral lines, astronomers can not only determine the element, but also the temperature and density of this element within the star. The spectral lines also tell us about each of the star's magnetic fields. The width of the line tells us how fast the matter is moving.

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Answer:

a. their total displacement = 364 meters

b. their average speed      = 33.5 meters/minute

c. their average velocity    =  26 meters/minute SW

Explanation:

See attached worksheet

The centre of gravity, in physics, is an imaginary point in a body of matter where for convenience in certain calculations,

Sources of errors for the center of gravity of an irregularly shaped object: -environmental error: when the wind blows it may remove the irregularly shaped object from equilibrium. add: density variations, shape variations say, thickness], inability to measure precisely, inability to compute precisely. For example, as a result of a number of the center of gravity measurements, we may have the best estimate of the true value for the acceleration due to gravity, the center of gravity is the point between which the force of gravity move on a thing or system. In most mechanics problems the gravitational pasture is assumed to be constant. The center of gravity is then in entirely the same position as the center of mass.

So we can conclude that It is important to know the center of gravity because it predicts the behavior of a moving body when acted on by gravity.

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The horizontal force required for an acceleration of 2.0 m/s² is equal to 54.3 N.

The force of kinetic friction is a type of frictions that acts on a moving object on a surface. In order to calculate the force of kinetic friction, we use the formula F = μN where F is the force of kinetic friction, μ is the coefficient of the kinetic friction, and N is the normal force. However, we need to take into account the force along the x-axis. Therefore, the formula ∑F = μN + ma will help us find the horizontal force.

Let ∑F represent the net force, N represent the normal force, m represent the mass of the box, g represent the acceleration of gravity, µ represent the kinetic friction, and a represent an acceleration of 2 m/s².

∑F = µN + ma

∑F = µmg + ma

∑F = m (µg + a)

∑F = 10 kg (0.35 × 9.8 m/s² + 2 m/s²)

∑F = 10 kg (3.43 m/s² + 2 m/s²)

∑F = 10 kg (5.43 m/s²)

∑F = 54.3 kg × m/s²

∑F = 54.3 N

The net force is equal to 54.3 N. That is the horizontal force required!

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The bond angle of the molecule to the nearest degree is 120 degrees.

According to the valence shell electron pair repulsion theory (VSEPR). We know that the bond angle that an atom has with its neighbors which also call the dihedral angle of the compound is affected by the number of atoms that surround the central atom in the molecule.

Let us recall that when we have two atoms that surround the central atom then we are going to have a three atom compound which has a trigonal planar geometry and has a bond angle of 120 degrees.

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The angle of a vector with x and y component of 3 and 4 respectively is 53.13°

Vectors are quantities that have both magnitude and direction

To calculate the angle of the vector, we use the formula below.

Formula:

Where:

Substitute these values into equation 1

Hence, the angle of the vector is 53.13°.

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The Angular velocity is 54.55 rad/s

What is angular velocity?
The rate at which an angle between two bodies changes is known as angular velocity. Something changes when an object rotates or revolves around an axis. This displacement is depicted in the image by the angle formed by a line on just one body and a line on the other. Technical terms like degrees, 360-degree revolutions, as well as revolutions per minute have been frequently used to describe angles or angular displacements (rpm). Angles and angular velocities are typically expressed in radians as well as radians per second, respectively, in mathematics and physics.

These conversion factors link these measurements together:
A radian equals 1/180 (or 0.0175) of a degree, and a radian per second = 1/30 (or 0.105) of a radian.
Angular velocity W= U/r
Given V= 30m/s ; r=0.55mW=3/0.55 = 54.55 rad/s

Hence the answer is 54.55 rad/s

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