0> -2x^2+4x+4Solve each inequality by graphing. Sketch it.

Answers

Answer 1

To solve the inequality we need to find the x-values that are the roots of the quadratic equation, let's use the quadratic formula:

[tex]\begin{gathered} \text{For an equation in the form:} \\ ax^2+bx+c=0 \\ The\text{ quadratic formula is:} \\ x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \\ \text{Then a=-2, b=4 and c=4} \\ x=\frac{-4\pm\sqrt[]{4^2-4(-2)(4)}}{2(-2)} \\ x=\frac{-4\pm\sqrt[]{16+32}}{-4} \\ x=\frac{-4\pm\sqrt[]{48}}{-4} \\ x=\frac{-4\pm6.93}{-4} \\ \text{Then} \\ x1=\frac{-4+6.93}{-4}=\frac{2.93}{-4}=-0.732 \\ x2=\frac{-4-6.93}{-4}=\frac{-10.93}{-4}=2.732 \end{gathered}[/tex]

Now, let's try values less or greater than these roots:

If x=-1:

[tex]\begin{gathered} 0>-2(-1)^2+4(-1)+4 \\ 0>-2\cdot1-4+4 \\ 0>-2\text{ This is right, then number less than -0.732 are solutions of the inequality} \end{gathered}[/tex]

Now let's try x=3:

[tex]\begin{gathered} 0>-2(3)^2+4(3)+4 \\ 0>-2\cdot9+12+4 \\ 0>-18+16 \\ 0>-2\text{ This is correct two, then the values greater that 2.732 are solutions to the inequality too} \end{gathered}[/tex]

Then, the graph of the inequality is:

The red-shaded area are the solution to the inequality, then in interval notation we have:

[tex](-\infty,-0.732)\cup(2.732,\infty)[/tex]

In builder notation it would be:

[tex]x|x<-0.732orx>2.732[/tex]

0&gt; -2x^2+4x+4Solve Each Inequality By Graphing. Sketch It.

Related Questions

A family is traveling from their home to avacation resort hotel. The table below showstheir distance from home as a function of time.Time (hrs)0257Distance(mi)0140375480Determine the average rate of change betweenhour 2 and 7, including the units.

Answers

Let

x -------> the time in hours

y -------> the distance in miles

we know that

To find the average rate of change, we divide the change in the output (y) value by the change in the input value (x)

so

For x=2 h ------> y=140 mi

For x=7 h ------> y=480 mi

rate of change=(480-140)/(7-2)

rate of change=340/5=68 mi/h

The average rate of change is equal to the speed in this problem

Graph the system below. What is the x-coordinate of the solution to the system of linear equations?y= -4/5x + 2y= 2/3x + 2A. -4B. 2C. 3D. 0

Answers

The solution is (x,y) = (0,2)

Use a system of equations to solve the following problem.The sum of three integers is380. The sum of the first and second integers exceeds the third by74. The third integer is62 less than the first. Find the three integers.

Answers

the three integers are 215, 12 and 153

Explanation:

Let the three integers = x, y, and z

x + y + z = 380 ....equation 1

The sum of the first and second integers exceeds the third by 74:

x + y - 74 = z

x + y - z = 74 ....equation 2

The third integer is 62 less than the first:

x - 62 = z ...equation 3

subtract equation 2 from 1:

x -x + y - y + z - (-z) = 380 - 74

0 + 0 + z+ z = 306

2z = 306

z = 306/2

z = 153

Insert the value of z in equation 3:

x - 62 = 153

x = 153 + 62

x = 215

Insert the value of x and z in equation 1:

215 + y + 153 = 380

368 + y = 380

y = 380 - 368

y = 12

Hence, the three integers are 215, 12 and 153

A local children's center has 46 children enrolled, and 6 are selected to take a picture for the center'sadvertisement. How many ways are there to select the 6 children for the picture?

Answers

The question requires us to find how many ways we can select 6 children from a total of 46.

The formula for combinations is given as follows;

[tex]nC_r=\frac{n!}{(n-r)!r!}[/tex]

Where n = total number of children, and r = number of children to be selected. The combination now becomes;

[tex]\begin{gathered} 46C_6=\frac{46!}{(46-6)!6!} \\ 46C_6=\frac{46!}{40!\times6!} \\ 46C_6=\frac{5.5026221598\times10^{57}}{8.1591528325\times10^{47}\times720} \\ 46C_6=\frac{5.5026221598\times10^{10}}{8.1591528325\times720} \\ 46C_6=\frac{0.674410967996781\times10^{10}}{720} \\ 46C_6=\frac{6744109679.967807}{720} \\ 46C_6=9,366,818.999955287 \\ 46C_6=9,366,819\text{ (rounded to the nearest whole number)} \end{gathered}[/tex]

144 grapefruits in 4 boxes, How many grapefruits in 100 boxes?

Answers

Problem

144 grapefruits in 4 boxes, How many grapefruits in 100 boxes?​

Solution

for this case we can do the following proportional rule:

4/144 = x/100

And solving for x we got:

x= 100 (4/144)= 2.77

So between 2 and 3 grape fruits are expected

I have to create a graph but I need some help and clarification

Answers

To complete the table you evaluate the equation by the given value of x to find the corresponding value of y:

[tex]y=x+4[/tex][tex]\begin{gathered} x=4 \\ \\ y=4+4 \\ y=8 \\ \\ (4,8) \end{gathered}[/tex][tex]\begin{gathered} x=8 \\ \\ y=8+4 \\ y=12 \\ \\ (8,12) \end{gathered}[/tex][tex]\begin{gathered} x=12 \\ \\ y=12+4 \\ y=16 \\ \\ (12,16) \end{gathered}[/tex][tex]\begin{gathered} x=16 \\ \\ y=16+4 \\ y=20 \\ \\ (16,20) \end{gathered}[/tex]

To put those (x,y) points in the plane;

the frist coordinate x is the number of units you move to the left (if x is negative) or to the right (if x is positive)

the second coordinate y is the number of units you move down (if y is negative) or up (if y is positive)

Then, using the points (0,4), (4,8), (8,12), (12,16) and (16,20) you get the next graph for y=x+4:

Given the diagram below which could be used to calculate AC

Answers

Cos a = adjacent side / hypotenuse

Where:

a= angle = 37°

adjacent side = 20

Hypotenuse = x (the longest side , AC)

Replacing:

Cos (37)=20/ x (option B)

decide wether the following sides are acute obtuse or a right triangle.

Answers

The acute triangle is defined by the condition,

[tex]a^2+b^2The obtuse triangle is defined by the condition, [tex]a^2+b^2>c^2[/tex]

Here, we have,

[tex]\begin{gathered} 19^2=361 \\ 12^2=144 \\ 15^2=225 \\ 12^2+15^2>19^2 \end{gathered}[/tex]

Thus, the triangle is an obtuse triangle.

(Please show your work for question 18.)

Answers

It is given that AB = CB from this information we conclude that <A=<C by reason :angles opposite equal sides.

<A+<B+<C=180°(Sum of angles in a triangle)

[tex](4x - 13) + (5x - 2) + (4x - 13) = 180 \\ 4x + 5x + 4x - 13 - 2 - 13 = 180 \\ 13x - 28 = 180 \\ 13x = 180 + 28 \\ 13x = 208 \\ \frac{13x}{13} = \frac{208}{13} \\ x = 16[/tex]

x=6°

ATTACHED IS THE SOLUTION

GOODLUCK

Put the following equation of a line into slope-intercept form, simplifying all fractions.
4x-3y=9

Answers

Answer:

y=4/3x+3

Step-by-step explanation:

we know that slope intercept form is y=mx+b, where m is the slope and b is the y intercept

for 4x-3y=9, we have to isolate y

we subtract 4x to both sides to get

-3y=-4x+9

to get y alone, we divide both sides by -3

y=4/3x+3

Answer:

Y=4/3x-3

Step-by-step explanation:

Y=4/3x-3

the other guy had the right idea but the two negatives make a positive!

Uptown Tickets charges $7 per baseball game tickets plus a $3 process fee per order. Is the cost of an order proportional to the number of tickets ordered?

Answers

The cost of an order is proportional to the number of tickets if the relation between them is constant.

Then, if we order 1 ticket the cost will be $7 + $3 = $10

And if we order 2 tickets, the cost will be $7*2 + $3 = $17

So, the relation between cost and the number of tickets is:

For 1 ticket = $10 / 1 ticket = 10

For 2 tickets = $17/ 2 tickets = 8.5

Since 10 and 8.5 are different, the cost of an order is not proportional to the number of tickets ordered.

Answer: they are not proportional

Solve x^2 - 3x - 10 = 0 by factoring. *Mark only one oval.O {-5,2}O (-2,-5)O {-2,5}○ {-10,1}

Answers

In order to solve this quadratic equation by factoring, we can do the following steps:

[tex]\begin{gathered} x^2-3x-10=0\\ \\ x^2-3x-5\cdot2=0\\ \\ x^2+2x-5x-5\cdot2=0\\ \\ x(x+2)-5(x+2)=0\\ \\ (x-5)(x+2)=0\\ \\ \begin{cases}x-5=0\rightarrow x=5 \\ x+2=0{\rightarrow x=-2}\end{cases} \end{gathered}[/tex]

Therefore the solution is {-2, 5}. Correct option: third one.

State which pairs of lines are:(a) Parallel to each other.(b) Perpendicular to each other.

Answers

So first of all we should write the three equations in slope-intercept form. This will make the problem easier to solve. Remember that the slope-interception form of an equation of a line looks like this:

[tex]y=mx+b[/tex]

Where m is known as the slope and b the y-intercept. The next step is to rewrite the second and third equation since the first equation is already in slope-intercept form. Its slope is 4 and its y-intercept is -1.

So let's rewrite equation (ii). We can begin with substracting 4 from both sides of the equation:

[tex]\begin{gathered} 8y+4=-2x \\ 8y+4-4=-2x-4 \\ 8y=-2x-4 \end{gathered}[/tex]

Then we can divide both sides by 8:

[tex]\begin{gathered} \frac{8y}{8}=\frac{-2x-4}{8} \\ y=-\frac{2}{8}x-\frac{4}{8} \\ y=-\frac{1}{4}x-\frac{1}{2} \end{gathered}[/tex]

So its slope is -1/4 and its y-intercept is -1/2.

For equation (iii) we can add 8x at both sides:

[tex]\begin{gathered} 2y-8x=-2 \\ 2y-8x+8x=-2+8x \\ 2y=8x-2 \end{gathered}[/tex]

Then we can divide both sides by 2:

[tex]\begin{gathered} \frac{2y}{2}=\frac{8x-2}{2} \\ y=\frac{8}{2}x-\frac{2}{2} \\ y=4x-1 \end{gathered}[/tex]

Then its slope is 4 and its y-intercept is -1. As you can see this equation is equal to equation (i).

In summary, the three equations in slope-intercept form are:

[tex]\begin{gathered} (i)\text{ }y=4x-1 \\ (ii)\text{ }y=-\frac{1}{4}x-\frac{1}{2} \\ (iii)\text{ }y=4x-1 \end{gathered}[/tex]

It's important to write them in this form because when trying to figure out if two lines are parallel or perpendicular we have to look at their slopes:

- Two lines are parallel to each other if they have the same slope (independently of their y-intercept).

- Two lines are perpendicular to each other when the slope of one of them is the inverse of the other multiplied by -1. What does this mean? If a line has a slope m then a perpendicular line will have a slope:

[tex]-\frac{1}{m}[/tex]

Now that we know how to find if two lines are parallel or perpendicular we can find the answers to question 4.

So for part (a) we must find the pairs of parallel lines. As I stated before we have to look for those lines with the same slope. As you can see, only lines (i) and (iii) have the same slope (4) so the answer to part (a) is: Lines (i) and (iii) are parallel to each other.

For part (b) we have to look for perpendicular lines. (i) and (iii) are parallel so they can't be perpendicular. Their slopes are equal to 4 so any line perpendicular to them must have a slope equal to:

[tex]-\frac{1}{m}=-\frac{1}{4}[/tex]

Which is the slope of line (ii). Then the answer to part (b) is that lines (i) and (ii) are perpendicular to each other as well as lines (ii) and (iii).

the variable y is directly proportional to x. if y equals -0.6 when x equals 0.24, find x when y equals -31.5.

Answers

You have that y is proportional to x. Futhermore, you have y = -0.6 when x = 0.24.

Due to y is proportional to x, you have the following equation:

[tex]y=kx[/tex]

where k is the constant of proportionality. In order to find the value of x when y = -31.5, you first calculate k.

k is calculated by using the information about y=-0.6 and x=0.24. You proceed as follow:

y = kx solve for k

k = y/x replace by known x and y values

k = -0.6/0.24

k = -2.5

Hence, the constant of proportionality is -2.5.

Next, you use the same formula for the relation between y and x to find the value of x when y = -31.5. You proceed as follow:

y = kx solve for x

x = y/

in this problem you will use a ruler to estimate the length of AC. afterwards you will be able to see the lengths of the other two sides and you will use the pythagorean theorem to check your answer

Answers

Answer:

5.124

Explanation:

Given the following sides

AB = 6.5cm

BC = 4.0cm

Required

AC

Using the pythagoras theorem;

AB^2 = AC^2 + BC^2

6.5^2 = AC^2 + 4^2

42.25 = AC^2 + 16

AC^2 = 42.25 - 16

AC^2 = 26.25

AC = \sqrt{26.25}

AC = 5.124

Hence the actual length of AC to 3dp is 5.124

URGENT!! ILL GIVE
BRAINLIEST!!!!! AND 100 POINTS!!!!!

Answers

Answer:

√52

Step-by-step explanation:

[tex] \sqrt{ {(4 - ( - 2))}^{2} + {(1 - ( - 3))}^{2} } [/tex]

[tex] \sqrt{ {6}^{2} + {4}^{2} } = \sqrt{36 + 16} = \sqrt{52} [/tex]

One evening 1400 concert tickets were sold for the Fairmont Summer Jazz Festival. Tickets cost $30 for covered pavilion seats and $20 for lawn seats. Total receipts were $32,000. Howmany tickets of each type were sold?How many pavilion seats were sold?

Answers

Let p be the number of pavilion seats and l be the number of lawn seats. Since there were sold 1400 tickets, we can write

[tex]p+l=1400[/tex]

and since the total money was $32000, we can write

[tex]30p+20l=32000[/tex]

Then,we have the following system of equations

[tex]\begin{gathered} p+l=1400 \\ 30p+20l=32000 \end{gathered}[/tex]

Solving by elimination method.

By multiplying the first equation by -30, we have an equivalent system of equation

[tex]\begin{gathered} -30p-30l=-42000 \\ 30p+20l=32000 \end{gathered}[/tex]

By adding these equations, we get

[tex]-10l=-10000[/tex]

then, l is given by

[tex]\begin{gathered} l=\frac{-10000}{-10} \\ l=1000 \end{gathered}[/tex]

Now, we can substitute this result into the equation p+l=1400 and obtain

[tex]p+1000=1400[/tex]

which gives

[tex]\begin{gathered} p=1400-1000 \\ p=400 \end{gathered}[/tex]

Then, How many tickets of each type were sold? 400 for pavilion seats and 1000 for lawn seats

How many pavilion seats were sold? 400 tickets

Quadrilateral HGEF is a scaled copy of quadrilateral DCAB. What is themeasurement of lin EG?

Answers

Answer:

14 units

Explanation:

If quadrilaterals HGEF and DCAB are similar, then the ratio of some corresponding sides is:

[tex]\frac{FH}{BD}=\frac{EG}{AC}[/tex]

Substitute the given side lengths:

[tex]\begin{gathered} \frac{6}{3}=\frac{EG}{7} \\ 2=\frac{EG}{7} \\ \implies EG=2\times7 \\ EG=14 \end{gathered}[/tex]

The measurement of line EG is 14 units.

Simplify the expression.

the expression negative one seventh j plus two fifths minus the expression three halves j plus seven fifteenths
negative 19 over 14 times j plus 13 over 15
negative 19 over 14 times j minus 13 over 15
negative 23 over 14 times j plus negative 1 over 15
23 over 14 times j plus 1 over 15

Answers

The expression is simplified to negative 23 over 14 times j plus negative 1 over 15. Option C

What is an algebraic expression?

An algebraic expression can be defined as an expression mostly consisting of variables, coefficients, terms, constants and factors.

Such expressions are also known to be composed or made up of some mathematical or arithmetic operations, which includes;

AdditionSubtractionDivisionBracketMultiplicationParentheses. etc

From the information given, we have that;

negative one seventh j = - 1/7jtwo fifths = 2/5three halves j = 3/2 jseven fifteenths = 7/15

Substitute the values

- 1/7j + 2/5 - 3/2j - 7/15

collect like terms

- 1/7j - 3/2j + 2/5 - 7/15

-2j - 21j /14 + 6  7 /15

-23j/14 + -1/15

Hence, the correct option is negative 23 over 14 times j plus negative 1 over 15

Learn more about algebraic expressions here:

https://brainly.com/question/4344214

#SPJ1

Amtrak's annual passenger revenue for the years 1985 - 1995 is modeled approximately by the formulaR = -60|x- 11| +962where R is the annual revenue in millions of dollars and x is the number of years after 1980. In what year was the passenger revenue $722 million?In the years ____ and ___, the passenger revenue was $722 million.

Answers

ANSWER

1987 and 1995

EXPLANATION

The revenue is modeled by:

[tex]R=-60|x-11|+962[/tex]

To find the years that the revenue was $722 million, we have to solve for x when R is 722.

That is:

[tex]\begin{gathered} 722=-60|x-11|+962 \\ \Rightarrow722-962=-60|x-11| \\ -240=-60|x-11| \\ \Rightarrow|x-11|=\frac{-240}{-60} \\ |x-11|=4 \end{gathered}[/tex]

We can split the absolute value equation into two different equations because the term in the absolute value is equal to both the positive and the negative of the term on the other side of the equality.

That is:

[tex]\begin{gathered} x-11=4 \\ x-11=-4 \end{gathered}[/tex]

Solve for x in both:

[tex]\begin{gathered} x=11+4 \\ \Rightarrow x=15 \\ x=11-4 \\ \Rightarrow x=7 \end{gathered}[/tex]

That is to say 7 and 15 years after 1980.

Therefore, in the years 1987 and 1995, the revenue was $722 million.

Two liters of soda cost $2.50 how much soda do you get per dollar? round your answer to the nearest hundredth, if necessary.

Answers

If two litters of soda cost $2.50;

Then, a dollar would buy;

[tex]\begin{gathered} =\frac{2}{2.5}\text{litres of soda} \\ =0.80\text{ litres of soda} \end{gathered}[/tex]

Find the volume of 12 cm

Answers

Answer:

1728 cm ^ 3.

Step-by-step explanation:

we are given 12 cm

As we know formula of volume of cube = s ^3 ( side * side * side ) So = 12 * 12* 12 = 1728 cm ^ 3.

Find the Volume cylinder (8cm) (12cm) h = 8cm r = 12cm h = 8 cm r = 12 cm. The volume of a cylinder is equal to the area of the base πr2 π r 2 times the height. π⋅(radius)2 ⋅(height) π ⋅ ( r a d i u s) 2 ⋅ ( h e i g h t) Substitute the values of the radius r = 12 r = 12 and height h = 8 h = 8 into the formula to find the volume of the cylinder

P.s hopes this helps

what is 0.09 as a percentage?

Answers

9% is the answer because 0.09 divided by 1 X 100 = 9%

An independent third party found the cost of a basic car repair service for a local magazine. The mean cost is $217.00 with a standard deviation of $11.40. Which of the following repair costs would be considered an “unusual” cost?

Answers

Given

An independent third party found the cost of a basic car repair service for a local magazine.

The mean cost is $217.00 with a standard deviation of $11.40.

To find: The repair costs which would be considered an “unusual” cost.

Explanation:

It is given that, the mean is 217.00, and the standard deviation is 11.40.

Consider, the distribution as a Normal distribution.

Then, the first range is defined as,

[tex]\begin{gathered} First\text{ }range:mean\pm SD \\ \Rightarrow X_1=mean+SD \\ =217.00+11.40 \\ =228.4 \\ \Rightarrow X_2=mean-SD \\ =217.00-11.40 \\ =205.6 \end{gathered}[/tex]

And, the second range is defined as,

[tex]\begin{gathered} Second\text{ }range:mean\pm2SD \\ \Rightarrow X_3=217.00+2(11.40) \\ =217.00+22.8 \\ =239.8 \\ \Rightarrow X_4=217.00-2(11.40) \\ =217.00-22.8 \\ =194.2 \end{gathered}[/tex]

Hence, the answer is option a) 192.53 since it does not belongs to the above ranges.

Geometry Problem - Given: segment AB is congruent to segment AD and segment FC is perpendicular to segment BD. Conclusion: Triangle AEG is isosceles. (Reference diagram in picture)

Answers

As the triangle AEF has 2 angles with the same measure, triangle AEF is isosceles.

Consider the parabola given by the equation: f ( x ) = − 2 x 2 − 12 x − 9 Find the following for this parabola: A) The vertex: B) The vertical intercept is the point C) Find the coordinates of the two x intercepts of the parabola and write them as a list of points of form (x, y) separated by commas: It is OK to round your value(s) to to two decimal places.

Answers

Answer:

it is C) find the coordinated of two x intercept is

Identify all points and line segments in the picture below.Points: A, B, C, DLine segments: AB, BC, CD, AD, BD, ACPoints: A, B, C, DLine segments: AD, AC, DC, BOPoints: A, B, C, DLine segments: AB, AD, AC, DC, BCPoints: A, BLine segments: AB, AC, DC, BC

Answers

Option C

Points: A, B, C, D

Line segments: AB, AD, AC, DC, BC

The Caldwell family placed a large back-to-school order online. The total cost of the clothing was $823,59 and the shipping weight was 32 lb. 10 oz. They live in the LocalZone (shipping = $5.87, plus $. 11 per lb. for each lb. or fraction of a lb. above 15 lbs.) and the sales tax rate is 7.5%. Find the total cost of the order.$864.43$876.77$893.21o $901.22None of these choices are correct.

Answers

The breakdown of fees paid by the Caldwell family are calculated and shown below;

[tex]\begin{gathered} \text{Total cost of clothing = \$823.59} \\ \text{Sales tax = 7.5\% of \$823.59} \\ =\frac{7.5}{100}\times823.59=61.769 \\ \text{Sales tax = \$61.77} \\ \\ \text{Shipping fe}e \\ \text{Total weight of item = 32lb 10oz }\approx\text{ 33lb} \\ \text{The excess weight above 15lbs = 33 - 15=18lbs} \\ \text{Shipping cost on the extra 18lbs = \$0.11}\times18=1.98 \\ \text{Total cost on shipping = \$5.87+\$1.98=\$7.85} \end{gathered}[/tex]

The total cost of the order will now be

Total cost of clothing = $823.59

Shipping cost = $7.85

Sales tax = $61.77

TOTAL = $823.59 + $7.85 + $61.77 = $893.21

Therefore, the total cost of the order is $893.21

The ratio of students polled in 6th grade who prefer lemonade to iced tea is 8:4, or 2:1. If there were 39 students in 6th grade polled, explain how to find the number of students that prefer lemonade and the number of students that prefer iced tea. Be sure to tell how many students prefer each.

Answers

Since we know the ratio is 2:1, then to find the number of students who like iced tea we convert the ratio to a fraction:

[tex]\frac{1}{2}[/tex]

this means that one of two students preferred iced tea.

To find the number of students who prefer iced tea we multiply the total number of students by the fraction, then:

[tex]39\cdot\frac{1}{2}=\frac{39}{2}=19.5[/tex]

Since we can't have a fraction of a student, we conclude that 19 students prefer iced tea and 20 prefer lemonade.

write the exponential function for the data displayed in the following table

Answers

As per given by the question,

There are given that a table of x and f(x).

Now,

The genral for of the equation is,

[tex]f(x)=ab^x[/tex]

Then,

For the value of x and f(x).

Substitute 0 for x and -2 for f(x).

So,

[tex]\begin{gathered} f(x)=ab^x \\ -2=ab^0 \\ -2=a \end{gathered}[/tex]

Now,

For the value of b,

Substitute 1 for x and -1/3 for f(x),

So,

[tex]\begin{gathered} f(x)=ab^x \\ -\frac{1}{3}=ab^1 \\ ab=-\frac{1}{3} \end{gathered}[/tex]

Now,

Put the value of a in above result.

So,

[tex]\begin{gathered} ab=-\frac{1}{3} \\ -2b=-\frac{1}{3} \\ b=\frac{1}{6} \end{gathered}[/tex]

Now,

Put the value of a and b in the general form of f(x).

[tex]\begin{gathered} f(x)=ab^x \\ f(x)=-2\cdot(\frac{1}{6})^x \end{gathered}[/tex]

Hence, the exponential function is ,

[tex]f(x)=-2(\frac{1}{6})^x[/tex]

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If an additional 0.300 mol of HI is then added, what concentration will be present when the new equilibrium is established? allegheny company ended year 1 with balances in accounts receivable and allowance for doubtful accounts of $48,000 and $1,950, respectively. during year 2, allegheny wrote off $3,300 of uncollectible accounts. using the percent of receivables method, allegheny estimates that the ending allowance for doubtful accounts balance should be $3,400. what amount will allegheny report as uncollectible accounts expense on its year 2 income statement? Hello there! Please guys this is for Monday and I need your help. TEXT 1A sense of safety.Within Belfast the west of the city is predominately Catholic, east Belfast is largely Protestant, the southof the city is more mixed, and north Belfast is a patchwork of Protestant and Catholic neighborhoods.We found that the everyday use of parks in west and north Belfast was often focused on local facilitieswithin a 10minute walk. People are prepared to travel for specific activities, but maintain a morefrequent relationship with local spaces which act as community hubs.Remnants of The Troubles remain in Belfast. Distrust of Belfast City Council and the Police ServiceNorthern Ireland, as well as communities from different parts of the city, persists. Some residents stay intheir local area as it provides a sense of ownership and safety they may not feel elsewhere.How Belfasts parks promote shared space in a historically divided city, The Conversation, 20 Oct 2020.TEXT 2The celebrated peace walls.The undercurrent of savagery is rarely far awayIts been that way from ancient times, until the present dayThat murky world of politics, where they always try and failWhere deals are done in private, behind the secret veilHeld up as a precedent, for all the world to seeHow little Ulster saved itself, from a life of miseryWe listen to the sound bites, each days a brand-new startYet our celebrated peace walls, keep communities apartLeslie Wilson, Peace? (excerpt)TEXT 3The Re-Imaging Communities projectIn Belfast, the capital of Northern Ireland, hundreds of colorful murals line the citys streets, detailing acenturys worth of conflict and political division. ()In 1998, the internationally-brokered Good Friday Agreement also called the Belfast Agreement, officiallyended the conflict and set up a power-sharing government between Protestant Unionists and CatholicNationalists. Since then the violence has largely subsided. But tensions still linger between Protestantand Catholic neighborhoods, with some residents reluctant to bridge the gap. ()In the last several years, some communities have repainted portions of the most controversial murals orerected new ones in an effort to continue normalizing relationships between Protestants and Catholics.Under the Re-Imaging Communities project through the Arts Council of Northern Ireland, somecommunities received funding to create new murals in place of older images.These murals lie at the center of a debate over Northern Irelands future, Canvas Arts, PBS NewsHour, Feb25 2017QuestionsMake an account in English of the three texts in order to answer the questions: How is the current situation between Catholics and Protestants in Belfast portrayed in the three texts? What explanations for the situation and solutions for improvement are mentioned? A focus group was formed to provide opinions for a target market.what type of data is being collected from the focus group ? [3] How many solutions does the system of equations have? y = 5x - 6 y = 5x + 2 A training field is formed by joining a rectangle and two semicircles, as shown below. The rectangle is 96 m long and 64 m wide. Find the area of the training field. Use the value 3.14 for n, and do not round your answer. Be sure to include the correct unit in your answer. true or false: sexual selection is a case of natural selection that describes evolution due not to variable survival rates, but rather due to variable reproductive rates stemming from characteristics that allow an individual to successfully attract a mate. group of answer choices by aiming at establishing legitimacy and a traditional balance of power in european political affairs, metternich and his associates at the congress of vienna were advocates of the ideology known as Someone please help! 9) Determine the domain and range of the function represented in the graph. A. Domain: 1 jennifer wants to provide a vivid, concrete, and personal impact for her audience about the effects of pollution. the best supporting material tool jennifer could use is: The Dart Frog is a brightly colored frog. These bright colors could mean that this frog is poisonous, warning predators to stay away. Plants in the rainforest are normally crowded and have very little space. The big leaves of a Hosta Plant allow the plant to receive as much sunlight as possible when the sun is out.What type of adaptations are these? Compare and contrast the adaptations of the Dart Frog and the Hosta Plant. Your answer should be 34 sentences long.PLEASE HELP!! OPTIONS: LIFE CYCLE>PHYSICAL>BEHAVIORAL ADAPTION(ILL GIVE 20 POINTS!!) Can someone help me with this geometry question?A.Triangular prismB.Hexagonal prismC.Triangular pyramidD.Hexagonal pyramid suppose a large shipment of televisions contained 9% defectives. if a sample of size 393 is selected, what is the probability that the sample proportion will differ from the population proportion by less than 3%? round your answer to four decimal places. nancy works for northrop grumman corporation. she is assigned to a group of employees who work on solving quality issues the company is facing. nancy participates in a(n) Which text style makes the text look slanted?A.BoldB.CapitalizationC.FooterD.Italic